... 5 ,7} = {4},KA(5)={1,4,5}∩ {2, 4,5, 7} = {4,5},KA(6)={6 ,7} ∩ {2, 4,6,8}∩{1, 3, 6} = {6},KA (7) ={6 ,7} ∩{3 ,7} ∩ {2, 4,5, 7} = {7} , and KA(8)= {2, 4,6,8}. and for Table 3.15 and B = A,KA(1)={1,3,4,5,8}∩{1, ... is known and ρ(x,a)=v. For Table3.1 and B = A,KA(1)={1,4,5}∩{1,3,6} = {1},KA (2) = {2} ∩ {2, 4,6,8}∩ {2, 4, 5, 7} = {2} ,KA(3)={3 ,7} ∩{1,3,6} = {3},KA(4)={1,4,5}∩ {2, 4,6, 8}∩ {2, 4, 5 ,7} = {4},KA(5)={1,4,5}∩ {2, 4,5, ... 8},KA (2) = {2, 3,8}∩{1 ,2, 4, 5, 6, 8}∩ {2, 4,5 ,7, 8}= {2, 8},KA(3)={1,3,5 ,7} ∩{1,3, 6, 8} = {1,3},KA(4)={1,3,4,5,8}∩{1, 2, 4, 5,6, 8}∩ {2, 4,5 ,7, 8}= {4,5,8},KA(5)={1,3,4,5,8}∩ {2, 4, 5, 7, 8} =...