... as an
unknown C mol/m
3
.
total input rate = total output rate
5 m
3
/h ¥ 0.01 mol/m
3
+ 0.1 mol/h = 0.15 mol/h = 5 m
3
/h ¥ C mol/m
3
= 5 C mol/h
Thus,
C = 0. 03 mol/m
3
The total inflow and ... in the cross-flow or down-flow directions.
2 .3. 2 Steady- and Unsteady-State Conditions
If conditions change relatively slowly with time, there is an incentive to assume
“steady-state”...
...
3
gcm
3
gcm
3
gg
Deposition 500 1200 500 500 1000 1700 250
Resuspension 200 480 200 200 400 680 100
OM conversion – – 233 233 233 233 117
Burial (solids) 30 0 720 67 67 36 7 787 33
Total ... of 720 g of MM, 67 g of OM, and
633 g of water. The total volumetric burial rate of solids is 36 7 cm
3
/year. Now,
associated with these solids is 633 cm
3
of pore water; thus...
... that
f
2
= (I
2
+ J
1
J
4
/J
3
+ I
3
D
32
/D
T3
+ I
4
D
42
/D
T4
)/(D
T2
– J
2
J
4
/J
3
– D
24
·D
42
/D
T4
)
f
1
= (J
1
+ f
2
J
2
)/J
3
f
3
= (I
3
+ f
1
D
13
)/D
T3
f
4
= (I
4
+ f
2
D
24
)/D
T4
where
J
1
... f
2
D
24
)/D
T4
where
J
1
= I
1
/D
T1
+ I
3
D
31
/(D
T3
D
T1
)
J
2
= D
21
/D
T1
J
3
= 1 – D
31
D
13
/(D
T1
D
T3
)
J
4
= D
12
+ D
32
D
13
/D
T3...
... j
¤
1
3
13 (3. 2)
where v
j
z V
j
/ x
j
is the value-added ratio. Because p
i
occurs on both sides of Equation
(3. 2), it can be solved for them as follows:
pvIA
()
1
(3. 3)
where p ... EoL cost of the product is given by p
3
a
31
, with a
31
= 1, that is, p
3
. The solution
p
1
of equation (3. 3) with the a
21
replaced by
a
21
and a
31
= 1 then gives...
... acid char-
acter. Inclusion of organic acidity from this analog in model calculations
FIGURE 3. 3
MAGIC model hindcast estimates of pre-industrial pH versus diatom-inferred pH for 33 sta-
tistically ... streams
with longer-term records also showed increases in NO
3
-
concentrations, pro-
viding additional evidence for an increasing trend in NO
3
-
. Although SO
4
2-...