fundamentals of heat and mass transfer solutions manual phần 4 docx

fundamentals of heat and mass transfer solutions manual phần 4 docx

fundamentals of heat and mass transfer solutions manual phần 4 docx

... 20 3 85 76.9 68.8 44 .4 20 4 20 76.9 76.9 60.7 44 .4 20 5 76.9 68.8 60.7 40 .4 20 6 30 68.8 68.8 54. 6 40 .4 20 7 68.8 61.7 54. 6 37.3 20 8 40 61.7 61.7 49 .5 37.3 20 9 45 61.7 55.6 49 .5 34. 8 20 < The ... Size ∆ xp m T (45 s) x q ′′ (0 ,45 s) x q ′′ (L ,45 s) (mm) ( ° C) kW/m 2 kW/m 2 10 149 .8 - 249 .8 + 149 .8 5 149 .3 - 249 .0 + 149 .0 2 149 .4 - 249 .1 + 149 .0 COMM...
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fundamentals of heat and mass transfer solutions manual phần 1 docx

fundamentals of heat and mass transfer solutions manual phần 1 docx

... a layer of insulation between it and the concrete. PROBLEM 1 .43 (Cont.) ( ) ( ) 44 4 44 4 w,ss w,ss 0.65 1500 T K 0.65 330 T K σσ −+ − () () 22 w,ss w,ss 8W / m K T 700 K 4W / m ... () 3 4 4 0.0181 m /s V 4. 7 m/s o 22 A c D 0.07 m π π ∀∀× == = =  < (b) Heat transfer from the casing is by convection and radiation, and from Eq. (1.10) () (...
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fundamentals of heat and mass transfer solutions manual phần 2 docx

fundamentals of heat and mass transfer solutions manual phần 2 docx

... 1 TTq 4k r r 4k r r 4rh ππ π ∞     =+ −+ −+       () () 4 s,1 2 111 1K T 25 C 48 9W 1. 84 10 4 0. 04 0.51 0.53 W 4 0.53 6 π π −    =°+ × + − +     4 s,1 K T 25 C 48 9W ... 0.38 0 .44 0.5 Outer radius of insulation, m 40 80 120 160 200 240 Outer surface temperature, C Ts,o 0.2 0.26 0.32 0.38 0 .44 0.5 Ou ter radius of ins ulation, m 0 500 1...
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fundamentals of heat and mass transfer solutions manual phần 6 docx

fundamentals of heat and mass transfer solutions manual phần 6 docx

... mdot(kg/s) 5000 10000 15000 20000 25000 30000 Heat rate, q(W) 0.1 0.2 0.3 0 .4 0.5 Mass flowrate, mdot(kg/s) 42 43 44 45 46 Outlet temperature, Tmo(C) Although q increases with increasing m  due to the attendant increase in Re D , and ... ) 4/ 5 0 .4 4/50 .43 D Nu0.023RePr0.0239. 143 100.68229.12 ==×= 2 i hNuk/D29.120.0373 W/mK/0.025 m43 .4 W/mK. =⋅=×⋅=⋅ Hence, the outle...
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fundamentals of heat and mass transfer solutions manual phần 3 pdf

fundamentals of heat and mass transfer solutions manual phần 3 pdf

... 186.7 178.3 168 .4 157 .4 145 .6 133 .4 121.0 50 228.9 228.3 226.2 222.6 217.2 209.7 200.1 188 .4 175 .4 161.6 147 .5 75 255.0 2 54. 4 252 .4 248 .7 243 .1 235.0 223.9 209.8 1 94. 1 177.8 100 282 .4 281.8 280.1 ... and () 2 h x / k 5000W / m K 0.005m / 240 W / m K 0.1 042 , ∆= ⋅ ⋅= the solution to Eqs. (1) – (7) yields 12 34 T 46 .61 C, T 45 .67 C, T 45 .44 C, T 49 .23 C =°=°=°...
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fundamentals of heat and mass transfer solutions manual phần 5 ppsx

fundamentals of heat and mass transfer solutions manual phần 5 ppsx

... K D == ⋅ =⋅ 0625 001 347 21 690 2 . . , ′ = qWm20 43 8, Fluid: Engine Oil () D 62 5m s 0.01m VD Re 147 340 10 m s ν − == = × ()( ) () 4/ 5 1/2 1/3 5/8 D 1 /4 2/3 0.62 147 40 00 147 Nu 0.3 1 120 282,000 1 0 .4 4000 =+ ... 0.0001375 6. 24 1 .44 0.978 0.98 14 9 .47 1 1. 648 E4 0 */ /* Correlation results and air thermophysical properties at Tf NuLbarPr ReL Tf hLbar k nu uinf 22 9...
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fundamentals of heat and mass transfer solutions manual phần 7 pot

fundamentals of heat and mass transfer solutions manual phần 7 pot

... (a) Heat transfer rate by free convection to the room, per unit length of the tube; effect on quality, x, at outlet of 30 m length of tube; (b) Effect of radiation on heat transfer and quality of ... emissivity, and power dissipation of cylindrical heater. Temperature of ambient air and surroundings. FIND: Steady-state temperature of heater and time required t...
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fundamentals of heat and mass transfer solutions manual phần 8 ppsx

fundamentals of heat and mass transfer solutions manual phần 8 ppsx

... K 3000W m K 279 W m K =++ ⋅ ⋅⋅ ( ) 45 32 32 h 1 4. 44 10 9.59 10 3.58 10 m K W 4. 12 10 m K W U −−− − =×+×+× ⋅=× ⋅ 2 h U 243 WmK =⋅ . With C h = C min = 4. 160 × 10 4 W/K and C c = C max = 2.09 × ... NTU = 1. 54 and () () 42 2 hminh A NTU C U 1. 54 4.160 10 W K 243 W m K 264m ==× ⋅= . Hence, () ()() 2 h L 2 oT A 264m N70 DWN 0.02 2 30 m π π == = < (b) Using the IHT C...
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fundamentals of heat and mass transfer solutions manual phần 9 ppt

fundamentals of heat and mass transfer solutions manual phần 9 ppt

... or ()() () 44 12 c2w ss cc TT TT Lk Lk εσ − =− + ( ) 8 244 44 2 2 1500K T 0.8 5.67 10 W m K T 90 K 0.008m 0.005m 25W m K 60W m K − − =× × ⋅ − + ⋅⋅ 6 84 22 3.72 10 247 9T 4. 54 10 T 2.98 − ×− = × − 84 6 22 4. 54 ... 616 1 (4) and G w is equal to the blackbody emissive power at T ch . Using Eqs. (3) and (4) and substituting numerical values, find σεσ εσ TT T bp 4 ww 4 w ch...
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fundamentals of heat and mass transfer solutions manual phần 10 doc

fundamentals of heat and mass transfer solutions manual phần 10 doc

... of heat transfer to tube without ash deposit, (b) Rate of heat transfer with an ash deposit of diameter D d = 0.06 m, (c) Effect of deposit diameter and convection coefficient on heat rate and contributions ... 8170 K / W R 6 944 K / W R 747 1 K / W. === The equivalent resistance is then 1 eq 111 R 249 8 K / W 8170 6 944 747 1 − =++ =    and the total resistance...
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