... GIAYGIAYPHUTU6 5 67812 3 4 13 14 15 BUS21718192029 3 0 3 1 3 2 3 3 3 4 3 5 1 23 45 6 7891011121 3 1 4 1 5 161718192021222 3 2 4 2 5 262728 35 34 33 32 31 30 29282726 25 24 23 22212019181716 15 14 13 1211109876 5 4 3 212019181716 15 14 13 1211109876 5 4 3 21bus1BUS2121011916V215VV220VV 23 0VV 24 5VV 25 0VU2A+VV312VD2L1S1Q8NPNQ7AQ6AQ5AQ1B 15 U12A 3 U5C 45 U5BU10BU10A9U6DU6C74LS47A3A2A1A0testRBIgfedcbaRBOG174LS47A3A2A1A0testRBIgfedcbaRBOG274LS47A3A2A1A0testRBIgfedcbaRBOG374LS47A3A2A1A0testRBIgfedcbaRBOG4CD 45 2 0CP0ACP1AMRACP0BCP1BMRBQ3AQ2AQ1AQ0AQ3BQ2BQ1BQ0BU7CD 45 2 0CP0ACP1AMRACP0BCP1BMRBQ3AQ2AQ1AQ0AQ3BQ2BQ1BQ0BC1+VV105VCD 45 2 0CP0ACP1AMRACP0BCP1BMRBQ3AQ2AQ1AQ0AQ3BQ2BQ1BQ0BU8Q4CQ4BQ3DQ3CQ3BQ2CQ2B+VV195V74LS1 93 CPUCPDPLMRD3D2D1D0TCUTCDQ3Q2Q1Q0U9Q3A6U6BQ2AN1A 5 U5A74LS47A3A2A1A0testRBIgfedcbaRBOG5a ... =2 ,5 0,1 64 = 0,0 656 => d1= ∏1 4. S =∏ 4. 0,0 82 = 0,2 89 TÝnhθ 2 S2=JI2=2 ,5 3 = 1,2 => d2= ∏ 4. 1,2 = 1 ,5 2 tÝnh a,b: cã Shh= 7,8 7 chän a= 2 ,4 cm =>b= 2 ,4 7,8 7 = 3, 3 cm Vậy ... Phạm Đông Dơng 50 Lớp: ĐK KTĐ2 http://www.ebook.edu.vn SO TIET~ 220V /50 HzDV PHUTDV GIAYGIAYPHUTU6 5 67812 3 4 13 14 15 BUS21718192029 3 0 3 1 3 2 3 3 3 4 3 5 1 23 45 6 7891011121 3 1 4 1 5 161718192021222 3 2 4 2 5 262728 35 34 33 32 31 30 29282726 25 24 23 22212019181716 15 14 13 1211109876 5 4 3 212019181716 15 14 13 1211109876 5 4 3 21bus1BUS2121011916V215VV220VV 23 0VV 24 5VV 25 0VU2A+VV312VD2L1S1Q8NPNQ7AQ6AQ5AQ1B 15 U12A 3 U5C 45 U5BU10BU10A9U6DU6C74LS47A3A2A1A0testRBIgfedcbaRBOG174LS47A3A2A1A0testRBIgfedcbaRBOG274LS47A3A2A1A0testRBIgfedcbaRBOG374LS47A3A2A1A0testRBIgfedcbaRBOG4CD 45 2 0CP0ACP1AMRACP0BCP1BMRBQ3AQ2AQ1AQ0AQ3BQ2BQ1BQ0BU7CD 45 2 0CP0ACP1AMRACP0BCP1BMRBQ3AQ2AQ1AQ0AQ3BQ2BQ1BQ0BC1+VV105VCD 45 2 0CP0ACP1AMRACP0BCP1BMRBQ3AQ2AQ1AQ0AQ3BQ2BQ1BQ0BU8Q4CQ4BQ3DQ3CQ3BQ2CQ2B+VV195V74LS1 93 CPUCPDPLMRD3D2D1D0TCUTCDQ3Q2Q1Q0U9Q3A6U6BQ2AN1A 5 U5A74LS47A3A2A1A0testRBIgfedcbaRBOG5a...