... )(. )(. ) 12 2922 19 19 2 910 16 10 16 10 01 N=ו×=×−−−FmmF2 304 10 23 10 28 2224..N 11 04That’s the force operating on the particles at a distance of 10 mm. Now ... )−−°++ = +°− 26 13 1 25 19 5 19 50 8 36 8((, . ),. . ., 26 13 1 25 26 13 1 25 19 50 8 36 8 19 528 0 81 JJJJCtJCtJff+=+°+°==°=°=8 56 328 0 81 32 8.,.JCtJJtCtfffIt ... ampere (A). A flow of 6. 25 × 10 18 electrons is required for acharge flow of 1 Cs, which is equal to 1 ampere of current.CHAPTER 5Peterson’s SAT II Success: Physics 16 4• The last shows...