... )−−°++ = +°−26 13 1 25 19 5 19 50 83 6 8 ((, . ),. . .,26 13 1 2526 13 1 25 19 50 83 6 8 19 5 28 0 81 JJJJCtJCtJff+=+°+°==°=°= 85 6 3 28 0 81 32 8 .,.JCtJJtCtfffIt ... )(. )(. ) 12 2922 19 19 2 910 16 10 16 10 01 N=ו×=×−−−FmmF2 304 10 23 10 28 2224..N 11 04That’s the force operating on the particles at a distance of 10 mm. Now ... ofwater from 10 °C to 50°C? The specific heat for water is:4 18 4.()( )JoulesgC°Solution∆∆∆∆QcmTQJoulesgCgC CQ==°°− °=4 18 4500 50 10 83 6.()( )()( ) ,88 0JExampleNow...