... 191-1 95 refer to the following itinerary and e-mail.
HTCD Bank
20
State Street
Trenton, New Jersey 08 6 25
June 17 ,20 _
Ms. Nukket Topal
451
West Huron Drive
Chicago, Illinois 6 023 9
Dear
... src="data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAABKcAAAaTCAIAAAC3lti4AAAACXBIWXMAABYlAAAWJQFJUiTwAAAgAElEQVR42uzdz04TWwDH8Tk3s/AtXPoWstBNK3FwRWVh0J1PYd/CnSEuaEkkOkkDG0nK+/gA7o6L5t54pX...
... al., 19 92)
f
2
(C5) R
a
= ——— ≤ R
a, max
(9 .22 )
31.3r
n
where R
a,max
is the required surface finish.
Chatter. Chatter limits (C6) have been given by equation (9.15b), (9.15c) or (9.15e), and
are ... d
R
)
2
– (r
w
– d
e
)
2
= R
2
– (R – d
e
)
2
}
(9.9a)
for a convex survace (r
w
+ d
R
)
2
– (r
w
+ d
e
)
2
= R
2
– (R – d
e
)
2
Hence
d
e
2r
w
– d
R
for a concave surface c...
...
= 0;
2
F
2
⎛
⎜
⎝
⎞
⎟
⎠
2
W
2
⎛
⎜
⎝
⎞
⎟
⎠
− 0=
FW= F 175lb=
Man:
+
↑
Σ
F
y
= 0;
N
C
W− 2
F
2
⎛
⎜
⎝
⎞
⎟
⎠
− 0=
N
C
WF+= N
C
350 lb=
b()
Bar:
+
↑
Σ
F
y
= 0;
2
W
4
⎛
⎜
⎝
⎞
⎟
⎠
2
F
2
− 0=
F
W
2
= ... at E.
Given:
F 20 lb= e 0 .5 ft=
a 1.4 ft= f 0 .5 ft=
b 0 .2 ft= g 0 .5 ft=
c 2ft= h 2. 5 ft=
d 0. 75 ft=
θ
60 deg=
Solution:
Member AG:
Σ
M
A
= 0;
Fa b+()F
BC
bsin
θ...
... (E).
1. B
2. E
3. E
4. D
5. C
6. B
7. B
8. D
9. C
10. A
11. B
12. E
13. E
14. E
15. C
16. E
17. A
18. B
19. A
20 . D
21 . B
22 . E
23 . B
24 . D
25 . C
26 . B
27 . E
28 . C
29 . D
30. D
31. D
32. C
33. ... parallelogram DAWN?
(A) 11 .57
(B) 13.64
(C) 14.63
(D) 17 . 25
(E) 20 .00
45. If log
6 .2
x = e, what is the approximate value of x?
(A) 1 42. 54
(B) 173. 82
(C)...