... Approximate value (x′) = 0 .33 3Therefore, Absolute Error, 10 .33 3 0 .33 333 3 0 .33 3 0.00 033 3 3 a Exx′=− =− = − =Relative Error, Er= 0.00 033 30.0009990 .33 333 3 a Ex== and Percentage Error, Ep= ... seconddecimal places.Example 4. If 0 .33 3 is the approximate value of 1 3 , then find its absolute, relative and percentageerrors.Sol. Given that True value ()1 3 x=, and its Approximate value ... 0 .33 and 0 .34 . Which of these three is the best approximation?Sol. The number, which has least absolute error, gives the best approximation.True value x =10 .33 333 3 =When approximate value...