... Table3.1 and B = A,KA(1)={1 ,4, 5}∩{1,3,6} = {1},KA (2) = {2} ∩ {2, 4, 6,8}∩ {2, 4, 5, 7} = {2} ,KA(3)={3,7}∩{1,3,6} = {3},KA (4) ={1 ,4, 5}∩ {2, 4, 6, 8}∩ {2, 4, 5,7} = {4} ,KA(5)={1 ,4, 5}∩ {2, 4, 5, 7} = {4, 5},KA(6)={6,7}∩ {2, 4, 6,8}∩{1, ... 8}∩ {2, 4, 5,7,8}= {2, 8},KA(3)={1,3,5,7}∩{1,3, 6, 8} = {1,3},KA (4) ={1,3 ,4, 5,8}∩{1, 2, 4, 5,6, 8}∩ {2, 4, 5,7,8}= {4, 5,8},KA(5)={1,3 ,4, 5,8}∩ {2, 4, 5, 7,8} = {4, 5,8},KA(6)={3,6,7,8}∩{1 ,2, 4, ... {4, 5},KA(6)={6,7}∩ {2, 4, 6,8}∩{1, 3, 6} = {6},KA(7)={6,7}∩{3,7}∩ {2, 4, 5, 7} = {7}, and KA(8)= {2, 4, 6,8}. and for Table 3.15 and B = A,KA(1)={1,3 ,4, 5,8}∩{1, 3, 6, 8}= {1, 3, 8},KA (2) = {2, 3,8}∩{1 ,2, 4, 5,...