... 181 8–1 < /b> (a) Maximum bending moment 2371 lbf · in,< /b> (b) dA= 1.625 in,< /b> d B = 1.810 in,< /b> averagediameter ≥ 1.810 in< /b> 1 8–2 < /b> (a) d = 1.725 in,< /b> (b) d = 1.687 in< /b> 1 8–1 < /b> 3d = 1.371 in;< /b> d = 1.630 in < /b> ... Use d = 138 in< /b> 5–3 < /b> 0y B = 0.0459 in< /b> 5–3 < /b> 7yA=−0.101 in< /b> , yx=20 in< /b> =−0.104 in< /b> 5–4 < /b> 5yA=−0.133 in< /b> 5–4 < /b> 8yx=10 in< /b> =−0.0167 in< /b> 5–5 < /b> 1 (a) σ b = 76.5 kpsi, σc=−15.2 kpsi, (b) σ b = 78.4 kpsi, ... Selected Problems 10171 7–3 < /b> A-3 polyamide belt, b = 6 in,< /b> Fc= 77.4lbf,T =10 946 lbf · in,< /b> F1= 573.7lbf, F2= 117.6lbf,Fi= 268.3lbf, dip = 0.562 in< /b> 1 7–5 < /b> (a) T = 742.8lbf · in,< /b> Fi=...