... for the absolute value expression |
x
+ 3| .
If
x
> -3, making (
x
+ 3) positive, we can rewrite |
x
+ 3| as
x
+ 3:
x
+ 3 < 4
x
< 1
If
x
< -3, making (
x
+ 3) negative, ... solution:
|2 + 3| = 4(2) – 3
|5| = 8 – 3
5 = 5
Now let's consider what happens when
x
+ 3 is negative. To do so, we multiply
x
+ 3...
... discussion. Answer is C
2. From 1, a+b=-1. From 2, x=0, so ab=6. (x+a)*(x+b)=0x^ 2+( a+b)x+ab=0
So, x= -3, x=2 The answer is C.
3. ( 0+6 +x) /3= 3,x =3 ( 0+0 +y) /3= 2,y=6 Answer is B
4. Just image that, ... 2x + y = px + 7 yields y = 2x + 7
(B) 2x + y = –px yields y = –6x
(C) x + 2y = px + 7 yields y = (3/ 2)x + 7/2
(D) y – 7 = x ÷ (p – 2) yields y = (1/2...
... 0.1(F + G + C)
10C = F + G + C
9C = F + G
The pure Fujis plus the cross pollinated ones total 187
(4) F + C = 187
3/ 4 of his trees are pure Fuji
(5) F = (3/ 4)(F + G + C)
(6) 4F = 3F + 3G + 3C
(7) ... gives us:
(11) (3G + 3C) + C = 187
(12) 3G + 4C = 187
( 13) 9G + 12C = 561
Substituting equation (10) into ( 13) gives:
(14) 9G + 8G...
...
Is (
c
+
d
)/2 > (
a
+
b
+
c
+
d
+
e
+
f
)/6 ?
Is 3(
c
+
d
) >
a
+
b
+
c
+
d
+
e
+
f
?
Is 3
c
+ 3
d
>
a
+
b
+
c
+
d
+
e
+
f
?
Is 2
c
+ 2
d
> ... the set.
Therefore,
(
x
+
y
+
x
+
y
+
x
– 4
y
+
xy
+ 2
y
)
6
=
y
+ 3...
... +
y
=
s
+
q
. Since
x
+
y
+
z
=
180 and since
q
+
s
+
r
= 180, it must be true that
z
=
r
. We can now look at the statements.
Statement (1) tells us that
xq + sy + sx + ... (
a
+
b
)
2
=
c
2
+ 24
c
Substitute (1) and (2) into right side of (5)
(7) (60 –
c
)
2
=
c
2
+ 24
c
Substitute (
a
+
b
) = 60 –
c
from...
... getting a 2,
3, and 5, in any order, can be calculated as follows (remember, when calculating probabilities, OR means add):
(1 /33 6) + (1 /33 6) + (1 /33 6) + (1 /33 6) + (1 /33 6) + (1 /33 6) = 6 /33 6
Now, let’s ... to know is R>W.
For 1, R/(B+W)> W/(B+R)=>R/(B+W)-W/(B+R) >0
[ R(B+R)-W(B+W)]/(B+W)(B+R) >0
(R-W)(R+W+B)/(B+W)(B+R) >0
As (R+W+B)>0,...
... = (2 /3) h, we can solve for h:
(1 /3) h + (2 /3) h + h + l = 2000
(1 /3) h + (2 /3) h + h +( 2 /3) h = 2000
(8 /3) h = 2000
h = 2000 (3/ 8)
h = 750
If h = 750, l = (2 /3) h = 500.
(2) SUFFICIENT: If m = s + 250, ... Captured Ticks Awarded Berks Captured
1 3, 4 or 5 77 30 8, 30 9, 31 0, or 31 1
7 21, 22, or 23 11 44, 45, 46 or 47
11 33 , 34 , or 35 7 28, 2...
... = 3
20
– 3
17
= 3
17
(3
3
– 1) = 3
17
(27 – 1) = 3
17
(26) = 3
17
( 13) (2)
Now we have what we need: the prime factorization of x. We can see that x has three different prime
factors: 2, 3, ... x:
x = (3
2
)
10
– 3
17
= 3
20
– 3
17
Now, we still have not expressed x as a product of prime numbers. We need to pull out a common factor
from both terms. The largest...