... Hence a lower bound for g 1998 g2 33 37 g2g33g37is obtained when g2,g3,g37 are the three smallest primes 2,3,5, with g3 2. Thus,g 1998 3 23 5 120 ... no less difficulty than theoriginal problem.Problem 13Determine the least possible value of f 1998 ,wheref is a function from the set N ofpositive integers into itself such that for all m,n ... 2. Thus,g 1998 3 23 5 120 for each g S. There is, however, a function g Swith g 1998 120; this proves that the minimum in question is 120. Set g1 1, anddefine g on the...