... left-hand side and the decryption process going up the right-hand side for a 16-round algorithm. Forclarity, we use the notation and for data traveling through the encryptionalgorithm and and ... have= 03A6 and .Now let’s look at the decryption.We assume that and ,as shown in Figure 3.3, and we want to demonstrate that and . So, we start with and .Then, from Figure 3.3, and [F(03A6, ... halves . Each round of DES maps the right-handinput into the left-hand output and sets the right-hand output to be a function of theleft-hand input and the subkey for this round. So, at each...