... nd2nd31 2000 2000 20003 60 0 5400 16, 200 6 140 5040 30,24010 40 4000 40,00014 15 2940 41, 160 18 5 162 0 29, 160 22 2 968 21,2 96 = 21, 968 = 180,0 56 Thus: ds= (180,0 56/ 21, 968 ) = 8.20 µmThis is ... d1(mm)n1nd1nd21nd31nd41 6. 005.00 0. 26 1.3 6. 5 32.5 162 .54.003.00 0.18 0.54 1 .62 4. 86 14.582.001.375 0.23 0.3 16 0.435 0.598 0.8220.750 .67 0.08 0.05 36 0.0359 0.0241 0.0 161 0.500.37 0.17 0. 062 9 0.0233 0.00 86 ... particlesA 6 × 10 6 m2 6 × 10−4m2dp[(4 6 × 10 6 )/π] = 2. 76 ×10−3m√[(4 6 × 10−4)/π] = 2. 76 ×10−2md3p2.103 × 10−8m32.103 × 10−5m3 volume 6 × 10−9m3 6 × 10−7m3k0.285...