... $0.70, isn’t it that the apple is more expensive than the orange? Yes, if this means the price of an apple is more than the price of an orange Here, the basis of comparison isthe prices not the ... the scores of Group D are sequenced from the lowest to the highest, the middlemost mark is 55 and it isthe median ofthe set of five marks Statistically, the median is a better average than the ... (the mean of 60s and 70s) In this case, the mean of 55 is not as good as the median of 60 (the middlemost score) to represent the group since 55 is an underestimation ofthe performance of the...
... recognized prefixes, the remainder ofthe word being regarded as the stem The stem dictionary is now searched for this stem If it is found, the associated meaning, and the meanings ofthe recognized ... no match is found in the stem dictionary for a source-language word, the last letter is elided, and a match sought for the truncated word This elision and comparison is continued until the first ... m letters ofthe input word appear as an entry in the stem dictionary, or (2) no such m exists, and the word is unrecognizable by this dictionary Since we wish to permit recognition of prefixes,...
... are the table assignments z ofthe previous customers, nk−i isthe number of customers at table k in z−i , and K(z−i ) isthe total number of occupied tables If we further assume that table k is ... estimates of this distribution are based on the counts of those labels, i.e., the number of tables associated with each word type An example of such a hierarchical model isthe HDP bigram model of GGJ06, ... that ofthe DP model after integrating out the distribution G Note that as long as the base distribution P0 is fixed, predictions not depend on the seating arrangement z−i , only on the count of...
... with the difference ρ Precisely ϕr ofthem have length n/ρ and ϕ − ϕr are of length n/ρ Since these progressions are pairwise disjoint, there are at least (ϕ + ϕr )2 n/ρ the electronic journal of ... or Then κ≥ k + − (k − )θ Proof We may assume that By Lemma we have (3) > 2κ − 1, otherwise the assertion is obvious {0, d , , td } ⊆ A − A, where t ≥ ( + − 2κ)Λ Put m = A Then any ofthe ... sets Thus, the number of (k, )-sum-free sets satisfying neither (1), nor (2) does not exceed (ϕ + ϕr )2 n/ρ + 2n2 2n/(ρ+1) To complete the proof it is sufficient to show that the number of (k, )sum-free...
... worked out the modular ranks of Wt,k (v) Unfortunately, the condition (k − t) = in the hypothesis of our theorem precludes a new proof of Wilson’s theorem via our recursive formula In the special ... when the characteristic p of F is larger than k, our recursion does apply, with the same conclusion and proof as the above corollary In conclusion, we raise the question as to whether there is ... according to whether x belongs to them or not Further, there isthe elementary product formula Wt,k (v)Wk,l (v) = l−t k−t Wt,l (v) (4) whose proof is left as a straightforward exercise Using (4),...
... Denote this block M2 Denote by M3 the block consisting ofthe rows i = |A+ | + 1, , m and the columns j = 1, , ρn Denote by M4 the block consisting ofthe rows i = |A+ | + 1, , m and the ... Denote by M5 the block consisting ofthe rows i = 1, , |A+ | and the columns j = 2ρn + 1, , n Define β = |A+ |/m Figure visualizes these terms Let c(s, k) denote the number of entries of M equal ... least m/2 Assume, without loss of generality, that |A+ | ≥ m/2 (otherwise we can reverse the directions ofall edges and the result remains intact) Order the vertices of A such that A = {v1 , ...
... allow the special case where m = 0; in this case the path Q is a path on vertices, and R = P satisfies the lemma trivially The remainder ofthe proof is by induction on m For m = 1, let i be the ... apply the induction hypothesis using the paths P and Q to obtain a path R satisfying the lemma Next, we repeat the above argument with the portion of R beginning at um−1 and the vertex um Theorem ... vertex in V \ C and is beaten by a vertex in V \ C If T − C is strong, then A = C and B = V \ {x0 , x1 } satisfy the lemma Otherwise, let W1 (resp Wt ) be the set of vertices in the initial (resp...
... two ofthem there are either all possible edges or none ofthemThe factorial layer is substantially richer It contains most ofthe unitary classes mentioned above (the unique exception in the ... particular, • E2,0 isthe class of bipartite graphs, • E1,1 isthe class of split graphs, • E0,2 isthe class of graphs complement to bipartite Then the index k(X) of a class X isthe maximum k such ... us extend this definition by assuming that the index of every finite hereditary class is 0, and the index ofthe class ofall graphs equals infinity With this extension, the family ofall hereditary...
... Ku is WACC before taxes And this isthe condition for the validity ofthe first proposition of MM 14 same as the risk ofthe cash flows ofthe firm rather than the value ofthe debt Hence, the ... fact, in the article the authors say that the methodology is to calculate the risk ofthe cost of capital, although at the end they say it is to define the risk for the equity cost The way the methodology ... methodology is presented allows thinking that it isthe firm risk that is dealt with and this risk is added to the risk free rate With this, the cost of capital before taxes for the firm is found This...
... removed the condition nP(|X1 | > ηn ) ≤ c(log n)ε0 , < ε0 < in theorem 1.1 of [12] Remark 1.4 If EX < ∞, then X is in the domain of attraction ofthe normal law Therefore, the class of random ... The purpose of this article is to study and establish the ASCLT for self-normalized partial sums of random variables in the domain of attraction ofthe normal law, we will show that the ASCLT holds ... from the ordinary CLT, but in general the validity of ASCLT is a delicate question of a totally different character as CLT The difference between CLT and ASCLT lies in the weight in ASCLT The terminology...
... for the strong stability of Jamison’s weighted sums But most of their results were achieved under the identically distributed condition and some results were obtained even under the condition of ... identically distributed random variables converges completely to the expected value if the variance ofthe summands is finite Erdös [9] proved the converse The result of Hsu-Robbins-Erdös is a fundamental ... al Journal of Inequalities and Applications 2011, 2011:92 http://www.journalofinequalitiesandapplications.com/content/2011/1/92 Page ofThe proof of Theorem 2.1 is complete Remark 3.1 Theorem 2.1...
... be proved Theorem 1.6 by using Theorem 2.4 But it is not easy to prove Theorem 2.4 by using Theorem 1.6 So Theorem 2.4 is more general than Theorem 1.6 Proof of Theorem 1.6 The set ofall natural ... i=1 The rest ofthe proof is same as that of Theorem 1.6 except using Theorem 2.6 instead of Theorem 2.4 and is omitted ■ Acknowledgments The author would like to thank the referees for the helpful ... for all > When mean zero condition is imposed in Theorem 1.6, Dehua et al [10] established a complete convergence result However, the proof of Theorem in Dehua et al is mistakenly based on the...
... satisfies the hypotheses ofthe Theorem and that any ofthe equivalent conditions holds, then for r = |z| log |σ (z)| = o log log 1−r We also provide the following restatement ofthe hypotheses ... H then we deduce from the proof ofthe Theorem that ϕ ∈ B0 is equivalent to lim γ w→∂ δ (w) = δ (γ w) (4) In this situation, the finite part ofthe boundary of Ω plays a complicated role in the ... holds To complete the proof, we require the following lemma whose proof we merely sketch Lemma Under the hypotheses ofthe theorem, lim sup w→∞ δ (w) ≤ K < δ (γ w) Sketch of Proof First note that...
... and the twisted generalized q-Bernoulli polynomials attached to χ of higher order and investigate some symmetric properties ofthem Furthermore, using these symmetric properties of them, we can ... with the q-analog ofthe two-variable p-adic L-function,” Russian Journal of Mathematical Physics, vol 12, no 2, pp 186–196, 2005 10 T Kim, “Multiple p-adic L-function,” Russian Journal of Mathematical ... In this paper, we give the symmetric property for q-Bernoulli numbers in the viewpoint to give the answer of Kim’s open questions The Twisted Generalized Bernoulli Polynomials Attached to χ of...
... is independent of τ,T,U Proof The proof of Proposition 4.1 is divided into two steps First, we estimate the L∞ ([0,T],H σ+ε ) norm of U, and the L2 ([0,T],H σ+ε ) one of u Then, we estimate the ... which completes the proof of Theorem 1.1 The proof of Corollary 1.2 is similar to that in [1]; here, we omit the details, the interested readers can refer to [1] Acknowledgments This work was supported ... limit ofthe multidimensional isothermal Euler equations,” Transactions ofthe American Mathematical Society, vol 359, no 2, pp 637–648, 2007 [2] S Junca and M Rascle, “Strong relaxation ofthe isothermal...
... row-span of this table Since the dimension ofthe row-span of a matrix is equal to the dimension of its column-span, we can equally well study the dimension ofthe space spanned by the columns ofthe ... (q) isthe generating function for the entries ofthe column corresponding to the λ-cycles The dimension ofthe column-span of our table is therefore equal to dim Fn , and the proposition is proved ... power of Φj (q) in the least common multiple ofthe denominators ofallofthe fλ (q)’s excluding those in Sj is only n − 1, so the degree of this common j denominator is only n(n + 1)/2 − φ(j) Therefore,...
... obtained in [2] isthe exact computation ofthe probability involving the conjunction ofthe events using the occupancy problem for random placements of balls into bins We make use ofthe sharp estimates ... This analogy, that also resulted in an improvement ofthe upper bound for the unsatisfiability threshold in [9], alleviates the problem of overestimating the probability ofthe conjunction of ... from the pairs of partitions (V1 , V2 ), (V1 , V3 ) and (V2 , V3 ) respectively It is clear that the joint distribution ofthe r.v.’s λ1 , λ2 , λ3 isthe multinomial distribution (see [6]) In the...
... consecutive points /2 a−1 is bounded, then the height distribution Derivation of Results We establish the five parts of Theorem Since the analysis involves a routine use ofthe saddle point method ... denotes the fractional part) If n/b is a power of then β = and for = part (e) of Theorem yields (with j = 0) hk0 n √ ∼ 2k0 √ 2πb 2k0 −1 , 2k0 = n/b which is asymptotically small On the other hand ... expansions ofthe distribution Pr{Hn ≤ k} ofthe height Hn for five ranges of n, k, and b (cf Theorem 2) This should be compared to three regions of n and k for fixed b (cf Theorem 1) We shall prove...
... graph is 1-distinguishable exactly when it is rigid, i.e |Aut(G)| = The smallest d for which G is d-distinguishable is dubbed the distinguishing number of G, denoted (G) An instantiation of this ... > ln|Aut(G)|, G is d-distinguishable Another natural question is that ofthe computational complexity ofthe graph distinguishability problem (see the discussion in [1]) Specifically, one would ... following theorem: Theorem If (G)ln d > ln|Aut(G)| then G is d-distinguishable Proof We study the behavior of a random d-coloring of G, the probability distribution given by selecting the color of...