... take to execute (on average)?
(b) Now, modify the fibonacci() function by making the variables a, b, and c register variables.
Recompile and run the code. How long does a single iteration take ... Institute of Technology
Department ofElectricalEngineeringand Computer Science
6.087: Practical Programming in C
IAP 2010
Problem Set 3
Control flow. Functions. Variable scope. Static and global ... complex program is to develop it iteratively, solving one problem
at a time and testing it throroughly. For this problem, start with the following shell and then
iteratively add the missing components....
... the
polarities of the three resistors, and apply KVL to determine that
V
S
− v
1
− v
2
− v
3
= 0
The voltage divider rule tells us that
v
3
= V
S
ì
R
3
R
1
+ R
2
+ R
3
= 3 ì
8
10 + 6 + 8
= 1V
Comments: ... the voltage v
3
in the circuit of Figure 2.31.
v
3
v
2
–+
–
+
v
1
i
V
S
R
3
R
1
R
2
–
+
+
–
Figure 2.31
Solution
Known Quantities: Source voltage, resistance values
Find: Unknown voltage v
3
.
Schematics, ... source and resistor values.
Find: Obtain equations for each of the two circuits by applying KCL and KVL.
Schematics, Diagrams, Circuits, and Given Data: Figure 2.27.
V
S
R
1
V
1
R
2
(a)
–
+
V
2
–
+
–
+
I
R
1
(b)
R
2
I
1
I
2
V
I
S
–
+
Figure...
... flow and to convert the electric energy to heat and light:
v
ab
= v
ba
or
v
1
= v
2
1.5 V
+
–
v
1
i
+
–
i
a
b
v
2
= v
ab
+
–
Illustration of Kirchhoff’s
voltage law: v
1
= v
2
Figure 2.5
Voltages ... Brief History ofElectricalEngineering 9
1.5 Systems of Units 10
1.6 Special Features of This Book 11
2.1 Charge, Current, and Kirchhoff’s
Current Law 16
2.2 Voltage and Kirchhoff’s Voltage Law ... teacher and researcher in both
mechanical andelectrical engineering.
Part I Circuits 21
Gustav Robert Kirchhoff
(1824–1887). Photo courtesy of
Deutsches Museum, Munich.
2.2 VOLTAGE AND KIRCHHOFF’S...
... each of the elements.
By applying KVL, you can verify that the sum of the voltages across the three
resistors equals the voltage externally provided by the battery:
1. 5V= v
1
+ v
2
+ v
3
and since, ... the
polarity of the voltage source). Following the passive sign convention, we label the
polarities of the three resistors, and apply KVL to determine that
V
S
− v
1
− v
2
− v
3
= 0
The voltage divider ... the voltage v
3
in the circuit of Figure 2.31.
v
3
v
2
–+
–
+
v
1
i
V
S
R
3
R
1
R
2
–
+
+
–
Figure 2.31
Solution
Known Quantities: Source voltage, resistance values
Find: Unknown voltage v
3
.
Schematics,...
... State University
over several years.
1.4 BRIEF HISTORY OF ELECTRICAL
ENGINEERING
The historical evolution ofelectricalengineering can be attributed, in part, to
the work and discoveries of the ... equations for a linear resistive circuit by applying
Kirchhoff’s voltage law and Kirchhoff’s current law.
2.1 CHARGE, CURRENT, AND KIRCHHOFF’S
CURRENT LAW
The earliest accounts of electricity date from ... source voltage or current and the voltage or current it
depends on v
x
or i
x
, respectively—which can be any voltage or current in the
circuit.
+
_
v
S
Voltage controlled voltage source (VCVS) v
S
...