gia bai tap hinh hoc lop 9

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... Bài 9. Cho hình chóp ABCS. có đáy là tam giác ABC vuông ở C có aCA=;2aCB=; )(ABCSA⊥ và...

... BD.a) Tính AMuuur theo AB vaø ACuuur uuur.b) AM cắt BC tại I. Tính ICIB và AIAM.Bài 9 : Cho ∆ABC. Tìm tập hợp các điểm M thỏa điều kiện:a) MA MB=uuur uuurb) MA MB MC 0+ + =uuur ... ; 16) c) mur=( 12 ; 15) d) mur= ( 13 ; 14)Câu 16 : Cho tam giác ABC với A( -3 ; 6) ; B ( 9 ; -10) và G( 13 ; 0) là trọng tâm . Tọa độ C là :a) C( 5 ; -4) b) C( 5 ; 4) c) C( -5 ; 4) ... -1) ; B(-4;2) ; C(4; 3). Tìm D để ABDC laø hbha) D( 3;6) b) D(-3;6) c) D( 3;-6) d) D(-3;-6)Câu 19 : Cho ar=3ir -4jr và br=ir -jr. Tìm phát biểu sai :a) ar = 5 b) br...

... caõn:Do OCAB traùi trung ủieồm OCung AC=CB =90 o.Ta laùi coù:Hình 19 2 Lời nói đầu:Trong quá trình ôn thi tốt nghiệp cho học sinh lớp 9, chúng ta đều nhận thấy học sinh rất ngại chứng ... ⇒NI//CD.5/Chứng tỏ N là tâm đường tròn nội tiếp ∆ICM.Ta phải C/m N là giao ủieồm 3 ủửụứng phaõn gia c cuỷa CIM.ã Theo c/m ta coự MN laứ phaõn gia c cuỷa CMIã Do MNIB nội tiếp(cmt) ⇒NIM=NBM(cùng chắn cung ... ⇒BF=FD⇒BF=FC=FD.⇒đpcm.3/C/m GE FB nội tiếp: Do ∆BFC vuông cân ở F ⇒Cung BF=FC =90 o. ⇒sđgóc GBF=21Sđ cung BF=21 .90 o=45o.(Góc giữa tiếp tuyến BG và dây BF)Mà góc FED=45o(tính chất hình...

... M1 = 90 0 ( do tam giác AHM vuông tại H) => C1 + ∠C4 = 90 0 => ∠C3 + ∠C2 = 90 0 ( vì góc ACM là góc bẹt) hay OCK = 90 0 .Xét tứ giác KCOH Ta có OHK = 90 0; OCK = 90 0 => ... Lời giải: 1. Ta cã : ∠ACB = 90 0 ( néi tiÕp chắn nửc đờng tròn ) => MCI = 90 0 (vì là hai góc kề bù). ADB = 90 0 ( nội tiếp chắn nửc đờng tròn ) => MDI = 90 0 (vì là hai góc kề bù).=> ... có BAC = 90 0 ( vì tam giác ABC vuông tại A); DEB = 90 0 ( góc nội tiếp chắn nửa đờng tròn ) => DEB = BAC = 90 0 ; lại có ABC là góc chung => DEB CAB .2. Theo trên DEB = 90 0 =>...

... Tính diện tích tứ giác BMNC.b) Gọi K là giao điểm của CN và HA. Tính các độ dàiAK, KN.c) Gọi I là giao điểm của AM và CB. Tính cá c độ dàiIM, IB 9. Trên một đường thẳng d cho hai điểm A, ... bất kì trênnửa đường tròn cắt Ax tại C và cắt By tại D. Gọi Nlà giao điểm của AD và BC. P là giao điểm của OC vàAN, Q là giao điểm của OP và BM.Chứng minh rằng:a) MN//ACb) P Q//ABc) Ba ... kính đường tròn nội tiếp. 9. Tính bán kính đường tròn ngoại tiếp một tam giác cânbiết rằng cạnh đáy và đường cao tương ứng đều có độdài 8cm. 39 Bài tập hình học lớp 9 TTBDVH: Lửa Việtthuộc...

... có 2; 3 ; 19 b c a= = = thì giá trị góc A là : I. 450 II. 600 III. 90 0 IV.1200 Câu 4: Cho tam giác ABC có 08 ; 3; 60a c B= = = . ðộ dài cạnh b là bao nhiêu I. b = 49 II. b= ... các ñẳng thức sau ñây, ñẳng thức nào sai? I.0 0sin0 cos0 1+ = II. 0 0sin90 cos90 1+ = III. 0 0sin180 cos180 1+ = − IV. 0 0sin60 cos60 1+ = Câu 7: Cho góc α ... 0cos30 sin60= Câu 13: Bất ñẳng thức nào dưới ñây là ñúng? I.0 0sin90 sin100< II.0 0cos95 cos100> III.0 0tan85 tan125< IV.0 0cos145 cos125> Câu 14: Hai...

... 1. Ta có ∠CAB = 90 0 ( vì tam giác ABC vuông t i A); ạ ∠MDC = 90 0 ( góc n i ti p ch n n a đ ngộ ế ắ ử ườ tròn ) => ∠CDB = 90 0 nh v y D và A cùng nhìn BC d i m t góc b ng 90 ư ậ ướ ộ ằ0 ... phân giác c a góc ADE.(1)ủ5. Ta có ∠MEC = 90 0 (n i ti p ch n n a đ ng tròn (O)) => ộ ế ắ ử ườ ∠MEB = 90 0. T giác AMEB có ứ ∠MAB = 90 0 ; ∠MEB = 90 0 => ∠MAB + ∠MEB = 1800 mà đây ... góc chung => ∆DEB ∼ ∆ CAB .. Theo trên ∠DEB = 90 0 => DEC = 90 0 (vì hai góc k bù);ề BAC = 90 0 ( vì ∆ABC vuông t iạ A) hay ∠DAC = 90 0 => ∠DEC + DAC = 1800 mà đây là hai góc...

... BC tại H1/Chứng minh : Tứ gia c CHKA nội tiếp ,xác định tâm I Bài 99 /: Cho tam gia c ABC có 3 góc nhọn (AB<AC) .Vẽ 3 đường cao AF,BD,CE của tam gia c ABC cắt nhau tại H , ... E là tiếp điểm .Gọi H là giao điểm của AE và OD.Chứng minh :1/AC2=BC.DC2/Tứ gia c AHCD nội tiếp3/HE là phân gia c của góc CHB4/Gọi S là giao điểm của OD và AC .Từ ... lượt tại M và N.Chứng minh rằng :1/Các tứ gia c AOCM,BOCN nội tiếp2/ tam gia c MON là tam gia c vuông3/AM.BN=R24/Diện tích tứ gia c AMNB=OM.ON5/Gọi I là trung điểm của OB....

... nt⇒EFD=ECD(cùng chắn cungDE);ECD =90 o-EDC(2 góc nhọn của ∆ vuông EDC)();Do GBCF nt⇒GFB=GBC(cùng chắn cung GB);BCG =90 o-GBC().Từ ()và()⇒EFD+GFB =90 o-EDC +90 o-GBC=180o-2ADC mà EFG=180o-(EFD+GFB)=180o-180o+2ADC=2ADC(2)Từ ... HD=FE;KE=DF⇒∆DHF∽∆EFK(cgc)⇒FK=FH⇒đpcm.  Bài 39: Cho hình bình hành ABCD(A> ;90 o).Từ C kẻ CE;Cf;CG lần lượt vuông góc với AD;DB;AB.1. C/m DEFC nội tiếp.2. C/m:CF2=EF.GF.3. Gọi O là giao điểm AC và DB.Kẻ OI⊥CD.Cmr: ... ⇒BF=FD⇒BF=FC=FD.⇒đpcm.3/C/m GE FB nội tiếp: Do ∆BFC vuông cân ở F ⇒Cung BF=FC =90 o. ⇒sđgóc GBF=21Sđ cung BF=21 .90 o=45o.(Góc giữa tiếp tuyến BG và dây BF)Mà góc FED=45o(tính chất hình...

... vuông.b) Tính khoảng cách từ giao điểm ba đường phân giác đến mỗi cạnh.ĐS: a) Tính được AB = 24cm, AC = 45cm, BC = 51cm ⇒ ∆ABC vuông tại A.b) r = 9cm. Gọi O là giao điểm ba đường phân giác. ... trên đường tròn sao cho góc·MAB0 90 =. Kẻ dây MN vuông góc với AB tại H.a) Chứng minh AM và AN là các tiếp tuyến của đường tròn (B; BM).Trang 29 b) Gọi E là giao điểm của OM và AC ⇒ E là ... tam giác ABC ni tip ng trũn (O; R). Bit àA0 90 = <a. Tớnh độ dài BC.HD: Vẽ đường kính BD. ··BDC BAC= = a. BC BD D R.sin 2 sin= = a.Bài 9. Cho đường tròn (O) có hai bán kính OA và OB...

... điểm bên trong ∆BCD. Tìm giao điểm của: a) MN vaø (ABO). b) AO vaø (BMN).HD: a) Tìm giao tuyeán của (ABO) và (ACD). 9 Hình hoïc 11 – Chương 1 Học thêm toán 093 7 09 05 87c) x2 + y2 – 4x ... thêm toán 093 7 09 05 87a) 2x – y = 0 b) x + y + 2 = 0 c) 2x + y – 4 = 0 d) y = 2 e) x = –110. Tìm ảnh của các đường tròn sau qua phép quay tâm O góc 90 0:a) (x + 1)2 + (y – 1)2 = 9 b) x2 ... ABC.A′B′C′.a) Tìm giao tuyến của (AB′C′) và (BA′C′).b) Gọi M, N lần lượt là 2 điểm bất kì trên AA′ và BC. Tìm giao điểm của B′C′ với mặt phẳng (AA′N) và giao điểm của MN với mp(AB′C′). 9. Cho lăng...

... Vậy: PQ là giao tuyến của mp ( DMN) và (ABC )Dạng 2 : Xác định giao điểm của đường thẳng a và mặt phng () Phng phỏp : ã Tỡm ng thng b nm trong mt phng ()ã Giao im ca a v b là giao đt a ... ,SD.a. Tìm giao điểm I của SO với mặt phẳng ( MNP )b. Tìm giao điểm Q của SC với mặt phẳng ( MNP )Giải a. Tìm giao điểm I ca SO vi mt phng ( MNP )ã Chn mp ph (SBD) SOã Tỡm giao tuyn ca ... .a. Tìm giao điểm của CD và (MNK )b. Tìm giao điểm của AD và (MNK )Giải a. Tìm giao điểm của CD và (MNK ) :Trang 8IQPNMODCBASJIBDCNKMA Chuyên đề hình học không gian lớp...

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