fundamentals of electric circuits 3rd edition solutions manual chapter 2
Fundamentals of Corporate Finance 8th edition: Solutions Manual
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01/07/2014, 14:22
... expenses 21 ,000
22 ,750 23 , 625
EBIT $ 20 4,600 $ 22 1,650 $ 23 0,175
Interest 12, 500
12, 500 12, 500
Taxable income $ 1 92, 100 $ 20 9,150 $ 21 7,675
Taxes (35%) 67 ,23 5
73 ,20 3 76,186
Net income $ 124 ,865 ... $4,9 12. 23 + 2, 621 .49 = $7,533. 72
And finally, we are ready to solve the balance sheet identity as:
NFA = TA – CA = $7,533. 72 – 1 ,27 4 = $6 ,25 9. 72
21 . Child: Profit margin = NI / S = $2. 00 ... 0 .25 ( $25 K) + 0.34( $25 K) + X($100K);
X($100K) = $68K – 22 .25 K = $45.75K
X = $45.75K / $100K
X = 45.75%
25 .
Balance sheet as of Dec. 31, 20 06
Cash $2, 528 Accounts payable $2, 656
...
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- 2.3K
- 30
fundamentals of electric circuits
Ngày tải lên :
08/05/2014, 15:37
... i
1
and i
2
as in Eq. (2. 8.1). Equation (2. 8.4) becomes
6i
3
= 3i
2
⇒ i
3
=
i
2
2
(2. 8.5)
Substituting Eqs. (2. 8.3) and (2. 8.5) into (2. 8 .2) gives
30 − 3i
2
8
− i
2
−
i
2
2
= 0
or i
2
= 2 A. From ... Solving 18
1.9
Summary 21
Review Questions 22
Problems 23
Comprehensive Problems 25
2. 1
Introduction 28
2. 2
Ohm’s Laws 28
†
2. 3
Nodes, Branches, and Loops 33
2. 4
Kirchhoff’s Laws 35
2. 5
Series Resistors ... use
Kirchoff’s voltage law to check the results.
i
1
=
v
1
− 5
2
=
2 − 5
2
=−
3
2
=−1.5A
i
2
= i
8
= 0 .25 A
i
3
=
v
1
+ 3
4
=
2 + 3
4
=
5
4
= 1 .25 A
i
1
+ i
2
+ i
3
=−1.5 + 0 .25 + 1 .25 = 0 (Checks.)
Applying...
- 1.3K
- 1.1K
- 4
fundamentals of heat and mass transfer solutions manual phần 1 docx
Ngày tải lên :
08/08/2014, 17:20
...
where
()
2
A DL 0.1m 25 m 7.85m .
== ì=
Hence,
()
()
22 824 444
q 7.85m 10 W/m K 150 25 K 0.8 5.67 10 W/m K 423 29 8 K
=+ìì
()()
22
q 7.85m 1 ,25 0 1,095 w/m 9813 85 92 W 18,405 ... sur
h4T TTT2
εσ
==+
For the condition of ε = 0.05, T
s
= T
sur
+ 10 = 35°C = 308 K and T
sur
= 25 °C = 29 8 K, find that
()
(
)
824 22 3 2
r
h 0.05 5.67 10 W m K 308 29 8 308 29 8 K 0.32W m K
=ìì ... T
2
= -15°C
are
(
)
2
12
x
25 C 15 C
dT T T
q k k 1W m K 133.3W m
dx L 0.30m
−−
−
′′
=− = = ⋅ =
. (1)
22
xx
q q A 133.3W m 20 m 26 67W
=ì= ì =
. (2) <
Combining Eqs. (1) and (2) ,...
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- 928
- 4
fundamentals of heat and mass transfer solutions manual phần 2 docx
Ngày tải lên :
08/08/2014, 17:20
... 0
−=
Hence,
(
)
()
()()
[]
s ,2 s,1
2
2s ,2
12
TT
h4r T T
1r 1r 4 k
π
π
∞
−
−=
−
()()
[]
()
()
s ,2 s,1
2
21 2
s ,2
TT
k
r1r 1r
h
TT
∞
−
−=
−
()
()
(
)
()
s ,2 s,1
22
2
11 1
s ,2
TT
r r k 1.5W m K 30
1
r ... lens:
()
t,wo
23
2- 3
33111
Rm
4 0.35 W/m K 10 .2 12. 7
10
12W/m K4 10 .2 10 m
=+
ì
ì
()
2
2-3
3
191 .2 K/W+13 .2 K/W +24 6.7 K/W=451.1 K/W
6 W/m K4 12. 7 10 m
+=
ì
With lens:
t,w
3
3111
R 191 .2 K/W+13 .2 K/W+ ... outer surface of the insulation, it follows that
cond conv rad
qqq
′′′
=+
() ()()
s,1 s ,2 s ,2 s ,2 sur
21 2 2r
TT TTTT
ln r r 2 k 1 2 r h 1 2 r h
ππ π
∞
−−−
=+
where
()
()
22
r s ,2 sur s ,2 sur
hTTTT
εσ
=+...
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fundamentals of heat and mass transfer solutions manual phần 3 pdf
Ngày tải lên :
08/08/2014, 17:20
... 22 8.9 22 8.3 22 6 .2 222 .6 21 7 .2 209.7 20 0.1 188.4 175.4 161.6 147.5
75 25 5.0 25 4.4 25 2.4 24 8.7 24 3.1 23 5.0 22 3.9 20 9.8 194.1 177.8
100 28 2.4 28 1.8 28 0.1 27 6.9 27 1.6 26 3.3 25 0.5 23 2.8 21 3.5
125 310.9 ... 125 150 175 20 0 22 5 25 0 27 5 300
0 180.7 180 .2 178.4 175.4 171.1 165.3 158.1 149.6 140.1 129 .9 119.4 108.7 98.0
25 20 4 .2 203.6 20 1.6 198 .2 193.3 186.7 178.3 168.4 157.4 145.6 133.4 121 .0
50 22 8.9 ... 105.6 119 131.7 151.6 20 0
50 88 .2 117.4 138.7 156.1 174.6 20 0
50 99.6 137.1 1 62. 5 179 .2 190.8 20 0
50 123 .0 168.9 194.9 20 7.6 20 9.4 20 0
50 173.4 22 0.7 24 0.6 24 6.8 23 9.0 20 0
- 300 300 300 300 300...
- 220
- 1.3K
- 1
fundamentals of heat and mass transfer solutions manual phần 4 docx
Ngày tải lên :
08/08/2014, 17:20
... 315.3 324 .5 325 325 325 325 325
3 54 29 4.7 313.7 320 .3 324 .5 325 325 325 325
4 72 293.0 307.8 318.9 322 .5 324 .5 325 325 325
5 90 28 7.6 305.8 315 .2 321 .5 323 .5 324 .5 325 325
6 108 28 5.6 301.6 ... 319.3 322 .7 324 .0 324 .5 325
7 126 28 1.8 29 9.5 310.5 317.9 321 .4 323 .3 324 .2
8 144 27 9.8 29 6 .2 308.6 315.8 320 .4 322 .5
9 1 62 276.7 29 4.1 306.0 314.3 319.0
10 180 27 4.8 29 1.3 304.1 3 12. 4
Hence, ... Eqs. (2) and (4). The results are
tabulated below.
p t(s) T
0
T
1
T
2
T
3
T
4
T
5
T
6
T
7
(K)
0 0 325 325 325 325 325 325 325 325
1 18 304 .2 324 .7 325 325 325 325 325 325
2 36 303 .2 315.3...
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- 0
Fundamentals of Ecological Modelling, Third Edition pot
Ngày tải lên :
23/03/2014, 01:20
... 22 5
5.1 Introduction 22 5
5 .2 Network Models 22 6
5.3 Network Analysis 23 0
5.4 ECOPATH Software 23 6
5.5 Response Models 24 8
6. Modelling Population Dynamics 25 7
6.1 Introduction 25 7
6 .2 ... Conceptual Models 21 1
4.1 Introduction 21 1
4 .2 Application of Conceptual Diagrams 21 1
4.3 Types of Conceptual Diagrams 21 4
4.4. The Conceptual Diagram as Modelling Tool 22 1
Problems 22 3
5. Static ... Concepts 25 7
6.3 Growth Models in Population Dynamics 25 8
6.4 Interaction between Populations
26 2
6.4 Matrix Models 27 3
Problems 27 6
7. Dynamic Biogeochemical Models 27 7
7.1 Introduction 27 7...
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- 305
- 1
unit operation of chemical engineering 7th ed, solutions manual
Ngày tải lên :
01/04/2014, 11:53
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- 0