... For this reason it may be of interest to investigate other q-analogues ofthesumofcubes formula In addition, as there are classical results for sums of other powers of integers, it would be ... that the set S consists of pairs of partitions with no primed parts In the definition of φ−1 when there is a primed integer in the image, we consider only the value ofthe integer and ignore the ... proof described to him by N.M Ferrers The Ferrers shape of a partition is an array of boxes, left justified, in which the number of boxes in the first row is equal to the size ofthe first part, the...
... q)(1 − q )(1 − q ) and the q-analogue of n k= k=1 is n k=1 q 2n−2k n+1 n+1 (1 − q k ) = (1 − q) References [1] K C Garrett and K Hummel, A combinatorial proof ofthesumof q -cubes, Electron J Combin ... on n The form of (2) should not really come as a surprise in view ofthe fact that the q-analogue ofthesumof squares n k = n(n + 1)(2n + 1) k=1 is given by n q 2n−2k k=1 (1 − q k )(1 − q 3k ... Proof Since n+1 2 − q2 n 2 = (1 − q n )2 (1 − q 2n ) (1 − q)2 (1 − q ) equation (2) immediately follows by induction on n The form of (2) should not really come as a surprise in view of the...
... (2.82) yields the claim in (2.80) This completes the proof of Lemma This completes the proof of Proposition and hence of Theorem Proof of Theorem In this section we indicate how the arguments ... second term on the right-hand side ofthe analogue of (2.93) Proof of Theorem In Sections 4–6 we prove Theorems 3–5 The proof follows the same line of reasoning as in [3, §5], but there are some ... generalization ofthe proof of Proposition in [3] We outline the main steps, while skipping the details Step One ofthe basic ingredients in the proof in [3] is to approximate the volume ofthe Wiener...
... fragments F and I The number at the right of each RT-PCR product represents the length ofthe product The scheme also shows the location ofthe reverse primer DN+89 used in another starting exon-specific ... numbers over the diagrams indicate the position ofthe corresponding nucleotides relative to the translation start site, and the numbers in parentheses below the diagram show the position ofthe corresponding ... is done from +1 of exon )11871 above the sequence indicates the 5¢-end of exon 1a The numbers in parentheses demonstrate the position ofthe corresponding nucleotides relative to the transcription...
... higher than the beasts – and unworthy ofthe designation of honor, and, the title of man From the founding ofthe From the founding ofthe country, American leaders had argued that the strength ... and hard work The watchword of Northern honor, as it was for the English, was self-restraint This was the virtue that tied the others together; the man who had mastered himself had the discipline ... court-martialed for the use of profanity during the war, in violation ofthe 83rd Article of War requiring conduct appropriate to one’s status as an “officer and a gentleman.”) On the other hand, you...
... our further considerations Let X be a Banach space, Ω(X) is the collection of all nonempty bounded subsets of X, and W (X) is the subset of Ω(X) consisting of all weak compact subsets of X Let ... generalized forms ofthe Krasnoselskii theorem on fixed points for thesum A + B of a weakly-strongly continuous mapping and an asymptotically nonexpansive mapping in Banach spaces These results ... contributions The work presented here was carried out in collaboration between all authors SP and AA defined the research theme SP designed theorems and methods of proof and interpreted the results...
... solution of 2.11 if and only if u satisfies the operator equation ∇F u 2.25 The Main Theorems Now, we state and prove the following theorem concerning the solution of problem 2.11 Theorem 3.1 Assume ... v0 t ω t is exactly a unique solution of v0 t is just a unique solution of 2.12 and u0 t 2.11 The proof of Theorem 3.1 is completed Now, we assume that there exists a positive integer N such ... diagonalization matrix and μ1 λ1 ≤ μ2 B The proof of Lemma 2.2 is fulfilled λ2 ≤ · · · ≤ μn λn are the eigenvalues of Let ·, · denote the usual inner product on Rn and denote the corresponding norm 1/2 by...
... Journal of Inequalities and Applications 11 Applications ofthe Results Wang et al in have obtained the following: let K be the positive semidefinite solution ofthe ARE 1.4 Then the trace of matrix ... including 3.1 Some of our results and 3.1 cannot contain each other Theorem 3.1 If 1/p and K is the positive semidefinite solution ofthe ARE 1.4 , then 1/q the trace of matrix K has the lower and ... Journal of Inequalities and Applications Therefore, considering the application ofthe trace bounds, many scholars pay much attention to estimate the trace bounds for the product oftwo matrices...
... pattern on the weight lattice ofthe affine Weyl group E(1) or one of its degenerations This proliferation of discrete Painlev´ equations raises the question ofthe indepene dence ofthe various ... that the geometry ofthe evolution of this extended equation, together with its Schlesinger transformations, can be described by the affine Weyl group D(1) By using the freedom ofthe origin of ... have pointed out in [11], the geometry ofthe transformations of this equation is related to the affine Weyl group D(1) , just as in the case of (2.1) On the identity oftwo q-discrete Painlev´ equations...
... set of PCRs was carried out to detect the hygromycin resistance gene, CaMV35S promoter (the promoter located in front ofthe AtAOS2 gene), and the AtAOS2 gene in the transgenic rice genome The ... rice genome The results of PCRs would confirm the appearance ofthe AtAOS2 gene in the transgenic rice genome MATERIALS AND METHODS 2.1 Extraction of rice DNA The leaves of one-month-old wild-type ... thaliana AOS2 gene in the rice genome CONCLUSION From the above results, the hygromycin resistance gene, CaMV35S promoter (the promoter located in front ofthe AtAOS2 gene), and the AtAOS2 gene were...
... r the argument would work, but without further human input it could not produce a general proof, i.e., a proof for all p, r This is somewhat analogous to the sums ofthe pth powers of all ofthe ... 2r, completing the proof of Theorem To prove Theorem 2, we see that if r = then Sp,r,s (n) = fp,s (n), and if s = p then Sp,r,s (n) = 2pn − fp,r (n) + pn , so in these two cases the assertion ... immediately rn from Theorem If r = and s = p then write Sp,r,s (n) = fp,s (n) − fp,r (n) + pn rn As in the proof of Theorem 1, fp,s (n) − fp,r (n) can be written as the indefinite sumoftwo hypergeometric...