... 1 10⎛⎝⎜⎞⎠⎟n − 1 < 10 1 (10 1 )n – 1 < 10 1 (10 )( 1) (n – 1) < 10 1 (10 )–n + 1 < 10 1 –n + 1 < 1 –n < –2 n > 2 But, this is the inequality given in (1) , which ... Inequalities (1) n > 2 –n < –2 10 –n < 10 –2 (10 1 )n < 10 –2 1 10⎛⎝⎜⎞⎠⎟n < 10 –2 1 10⎛⎝⎜⎞⎠⎟n < 0. 01 SUFFICIENT.(2) 1 10⎛⎝⎜⎞⎠⎟n − 1 < 0 .1 1 10⎛⎝⎜⎞⎠⎟n ... index, what was the price of the mixer in 19 70 ? (1) The price of the Model K mixer was $10 2.40 more in 19 89 than in 19 70.(2) The price of the Model K mixer was $14 2.40 in 19 89.Arithmetic...
... D 10 0. D 10 1. B 10 2. D 10 3. D 10 4. E 10 5. B 10 6. D 10 7. B 10 8. D 10 9. A 11 0. A 11 1. E 11 2. B 11 3. D 11 4. D 11 5. D 11 6. A 11 7. D 11 8. E 11 9. E 12 0. B 12 1. E 12 2. C 12 3. ... C 14 8. B 14 9. A 15 0. A 15 1. D 15 2. B 15 3. D 15 4. A 15 5. D 15 6. B 15 7. D 15 8. D 15 9. A 16 0. D 16 1. C 16 2. A 16 3. B 16 4. C 16 5. A 16 6. D 16 7. A 16 8. A 16 9. B 17 0. A 17 1. ... A 12 4. A 12 5. D 12 6. E 12 7. D 12 8. B 12 9. C 13 0. C 13 1. D 13 2. C 13 3. B 13 4. B 13 5. D 13 6. D 13 7. A 13 8. E 13 9. B 14 0. E 14 1. C 14 2. E 14 3. D 14 4. D 14 5. D 14 6. B 14 7....
... from x = 16 5 to x = 16 6.III. For x = 16 5, the denominator is 16 52 – 16 5 = (16 5) (16 5 – 1) = (16 5) (16 4), and for x = 16 6, the denominator is 16 62 – 16 6 = (16 6) (16 6 – 1) = (16 6) (16 5). erefore, ... Review 12 th Edition en replace pn in (iii) with 12 0 to get: 12 0 + n – 10 p – 10 = 12 0 n – 10 p – 10 = 0 n – 10 (p + 1) = 0 n = 10 (p + 1) np = 10 p(p + 1) 12 0 = 10 p(p + 1) 12 = p(p + 1) 0 ... both – 1 x and 1 – 1 x increase. A direct computation can also be used: = 1 165 1 166 16 6 16 5 16 5 16 6 1 165 16 6− =−()()=()(), which is positive, and thus the function increases...