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chapter 2 solution of linear algebraic equations

Tài liệu Solution of Linear Algebraic Equations part 2 ppt

Tài liệu Solution of Linear Algebraic Equations part 2 ppt

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... equationa11a 12 a13a14a 21 a 22 a 23 a 24 a31a 32 a33a34a41a 42 a43a44·x11x 21 x31x41x 12 x 22 x 32 x 42 x13x 23 x33x43y11y 12 y13y14y 21 y 22 y 23 y 24 y31y 32 y33y34y41y 42 y43y44=b11b 21 b31b41b 12 b 22 b 32 b 42 b13b 23 b33b431000010000100001 (2. 1.1)Here ... equationa11a 12 a13a14a 21 a 22 a 23 a 24 a31a 32 a33a34a41a 42 a43a44·x11x 21 x31x41x 12 x 22 x 32 x 42 x13x 23 x33x43y11y 12 y13y14y 21 y 22 y 23 y 24 y31y 32 y33y34y41y 42 y43y44=b11b 21 b31b41b 12 b 22 b 32 b 42 b13b 23 b33b431000010000100001 (2. 1.1)Here ... 36 Chapter 2. Solution of Linear Algebraic Equations Sample page from NUMERICAL RECIPES IN C: THE ART OF SCIENTIFIC COMPUTING (ISBN 0- 521 -43108-5)Copyright (C) 1988-19 92 by Cambridge...
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Tài liệu Solution of Linear Algebraic Equations part 1 docx

Tài liệu Solution of Linear Algebraic Equations part 1 docx

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... 1-800-8 72- 7 423 (North America only),or send email to trade@cup.cam.ac.uk (outside North America). Chapter 2. Solution of Linear Algebraic Equations 2. 0 IntroductionA set of linear algebraic equations ... this:a11x1+ a 12 x 2 + a13x3+ ···+a1NxN=b1a 21 x1+ a 22 x 2 + a 23 x3+ ···+a2NxN=b 2 a31x1+ a 32 x 2 + a33x3+ ···+a3NxN=b3··· ···aM1x1+aM2x 2 +aM3x3+···+aMNxN= ... improvement of a solution ( 2. 5)ã Various special forms: symmetric positive-denite ( 2. 9), tridiagonal( 2. 4), band diagonal ( 2. 4), Toeplitz ( 2. 8), Vandermonde ( 2. 8), sparse( 2. 7)ã Strassens...
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Tài liệu Solution of Linear Algebraic Equations part 11 ppt

Tài liệu Solution of Linear Algebraic Equations part 11 ppt

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... matrices,a11a 12 a 21 a 22 Ãb11b 12 b 21 b 22 =c11c 12 c 21 c 22 (2. 11.1)Eight, right? Here they are written explicitly:c11= a11ì b11+ a 12 ì b 21 c 12 = a11ì b 12 + a 12 ì b 22 c 21 = a 21 ì ... set of formulas was, in fact, discovered by Strassen[1]. The formulas are:Q1 (a11+ a 22 ) ì (b11+ b 22 )Q 2 (a 21 + a 22 ) ì b11Q3 a11ì (b 12 b 22 )Q4 a 22 ì (b11+ b 21 )Q5 ... b11+ a 12 ì b 21 c 12 = a11ì b 12 + a 12 ì b 22 c 21 = a 21 ì b11+ a 22 ì b 21 c 22 = a 21 ì b 12 + a 22 ì b 22 (2. 11 .2) Do you think that one can write formulas for the c’s that involve only...
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Tài liệu Solution of Linear Algebraic Equations part 3 pdf

Tài liệu Solution of Linear Algebraic Equations part 3 pdf

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... 42 Chapter 2. Solution of Linear Algebraic Equations Sample page from NUMERICAL RECIPES IN C: THE ART OF SCIENTIFIC COMPUTING (ISBN 0- 521 -43108-5)Copyright (C) 1988-19 92 by Cambridge ... isxi=1aiibi−Nj=i+1aijxj (2. 2.4)The procedure defined by equation (2. 2.4) is called backsubstitution.Thecom-bination of Gaussian elimination and backsubstitution yields a solution to the set of equations. The ... the case of a single right-hand side vector):a11a 12 a13a140 a 22 a 23 a 24 00a33a34000a44·x1x 2 x3x4=b1b 2 b3b4 (2. 2.1)Here...
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Tài liệu Solution of Linear Algebraic Equations part 4 docx

Tài liệu Solution of Linear Algebraic Equations part 4 docx

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... β 22 β 23 β 24 00β33β34000β44=a11a 12 a13a14a 21 a 22 a 23 a 24 a31a 32 a33a34a41a 42 a43a44 (2. 3 .2) We can use a decomposition such as (2. 3.1) to solve the linear setA · x =(L·U)·x=L·(U·x)=b (2. 3.3)by ... j : αi1β1j+ αi2β2j+ ···+αiiβjj= aij (2. 3.9)i>j: αi1β1j+αi2β2j+···+αijβjj= aij (2. 3.10) Equations (2. 3.8)– (2. 3.10) total N 2 equations for the N 2 + N unknown α’s ... case of a 4 ì 4 matrix A, for example, equation (2. 3.1) would look like this:α11000α 21 α 22 00α31α 32 α330α41α 42 α43α44·β11β 12 β13β140 β 22 β 23 β 24 00β33β34000β44=a11a 12 a13a14a 21 a 22 a 23 a 24 a31a 32 a33a34a41a 42 a43a44 (2. 3 .2) We...
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Tài liệu Solution of Linear Algebraic Equations part 5 docx

Tài liệu Solution of Linear Algebraic Equations part 5 docx

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... elimination.dum=a[i][1]/a[k][1];al[k][i-k]=dum;for (j =2; j<=mm;j++) a[i][j-1]=a[i][j]-dum*a[k][j];a[i][mm]=0.0;}}} 52 Chapter 2. Solution of Linear Algebraic Equations Sample page from NUMERICAL RECIPES IN C: THE ART OF SCIENTIFIC ... 1967,Computer Solution of Linear Algebraic Systems(Engle-wood Cliffs, NJ: Prentice-Hall), Chapters 9, 16, and 18.Westlake, J.R. 1968,A Handbook of Numerical Matrix Inversion and Solution of Linear Equations (New ... Computations, 2nd ed. (Baltimore: Johns HopkinsUniversity Press),Đ4.3. 50 Chapter 2. Solution of Linear Algebraic Equations Sample page from NUMERICAL RECIPES IN C: THE ART OF SCIENTIFIC...
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Tài liệu Solution of Linear Algebraic Equations part 12 pdf

Tài liệu Solution of Linear Algebraic Equations part 12 pdf

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... Inverse(a11)R 2 = a 21 ì R1R3= R1ì a 12 R4= a 21 ì R3R5= R4 a 22 R6= Inverse(R5)c 12 = R3ì R6c 21 = R6ì R 2 R7= R3ì c 21 c11= R1 R7c 22 = R6 (2. 11.6) ... matricesa11a 12 a 21 a 22 andc11c 12 c 21 c 22  (2. 11.5)are inverses of each other. Then the c’s can be obtained from the a’s by the followingoperations (compare equations 2. 7 .22 and 2. 7 .25 ):R1= Inverse(a11)R 2 = a 21 ì R1R3= ... 104 Chapter 2. Solution of Linear Algebraic Equations Sample page from NUMERICAL RECIPES IN C: THE ART OF SCIENTIFIC COMPUTING (ISBN 0- 521 -43108-5)Copyright (C) 1988-19 92 by Cambridge...
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Tài liệu Solution of Linear Algebraic Equations part 6 pptx

Tài liệu Solution of Linear Algebraic Equations part 6 pptx

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... 56 Chapter 2. Solution of Linear Algebraic Equations Sample page from NUMERICAL RECIPES IN C: THE ART OF SCIENTIFIC COMPUTING (ISBN 0- 521 -43108-5)Copyright (C) 1988-19 92 by Cambridge ... quite far from the true solution, one call is generally enough; but a secondcall to verify convergence can be reassuring. 58 Chapter 2. Solution of Linear Algebraic Equations Sample page from ... feasible)? 2. 5 Iterative Improvement of a Solution to Linear Equations 55Sample page from NUMERICAL RECIPES IN C: THE ART OF SCIENTIFIC COMPUTING (ISBN 0- 521 -43108-5)Copyright (C) 1988-19 92 by Cambridge...
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Tài liệu Solution of Linear Algebraic Equations part 7 docx

Tài liệu Solution of Linear Algebraic Equations part 7 docx

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... (scale) { 62 Chapter 2. Solution of Linear Algebraic Equations Sample page from NUMERICAL RECIPES IN C: THE ART OF SCIENTIFIC COMPUTING (ISBN 0- 521 -43108-5)Copyright (C) 1988-19 92 by Cambridge ... q.e.d.Figure 2. 6.1 summarizes our discussion of SVD thus far. 68 Chapter 2. Solution of Linear Algebraic Equations Sample page from NUMERICAL RECIPES IN C: THE ART OF SCIENTIFIC COMPUTING (ISBN 0- 521 -43108-5)Copyright ... n ≤ N (2. 6.3) 66 Chapter 2. Solution of Linear Algebraic Equations Sample page from NUMERICAL RECIPES IN C: THE ART OF SCIENTIFIC COMPUTING (ISBN 0- 521 -43108-5)Copyright (C) 1988-19 92 by Cambridge...
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Tài liệu Solution of Linear Algebraic Equations part 8 docx

Tài liệu Solution of Linear Algebraic Equations part 8 docx

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... 0. 0. 0. 2. 0. 0. 0. 6. 5. (2. 7 .27 ) 74 Chapter 2. Solution of Linear Algebraic Equations Sample page from NUMERICAL RECIPES IN C: THE ART OF SCIENTIFIC COMPUTING (ISBN 0- 521 -43108-5)Copyright ... 1978(Philadelphia:S.I.A.M.). 82 Chapter 2. Solution of Linear Algebraic Equations Sample page from NUMERICAL RECIPES IN C: THE ART OF SCIENTIFIC COMPUTING (ISBN 0- 521 -43108-5)Copyright (C) 1988-19 92 by Cambridge ... j,jl,jm,jp,ju,k,m,n2,noff,inc,iv;float v;n2=ija[1]; Linear size of matrix plus 2. for (j=1;j<=n2 -2; j++) sb[j]=sa[j]; Diagonal elements.iindexx(ija[n2-1]-ija[1],(long *)&ija[n2-1],&ijb[n2-1]);Index...
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Tài liệu Solution of Linear Algebraic Equations part 9 docx

Tài liệu Solution of Linear Algebraic Equations part 9 docx

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... 92 Chapter 2. Solution of Linear Algebraic Equations Sample page from NUMERICAL RECIPES IN C: THE ART OF SCIENTIFIC COMPUTING (ISBN 0- 521 -43108-5)Copyright (C) 1988-19 92 by Cambridge ... equations 11··· 1x1x 2 ··· xNx 2 1x 2 2··· x 2 N···xN−11xN−1 2 ··· xN−1N·w1w 2 w3···wN=q1q 2 q3···qN (2. 8 .2) Write this ... xj.Inotherwords,Pj(xi)=δij=Nk=1Ajkxk−1i (2. 8.4)But (2. 8.4) saysthat Ajkis exactly the inverse of the matrix of componentsxk−1i,whichappears in (2. 8 .2) , with the subscript as the column index. Therefore the solution of (2. 8 .2) is...
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Tài liệu Solution of Linear Algebraic Equations part 10 docx

Tài liệu Solution of Linear Algebraic Equations part 10 docx

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... +1,i +2, ,N (2. 9.5) 92 Chapter 2. Solution of Linear Algebraic Equations Sample page from NUMERICAL RECIPES IN C: THE ART OF SCIENTIFIC COMPUTING (ISBN 0- 521 -43108-5)Copyright (C) 1988-19 92 by ... byLTij= Lji (2. 9.3)Writing out equation (2. 9 .2) in components, one readily obtains the analogs of equations (2. 3. 12) – (2. 3.13),Lii=aii−i−1k=1L 2 ik1 /2 (2. 9.4)andLji=1Liiaij−i−1k=1LikLjkj ... 96 Chapter 2. Solution of Linear Algebraic Equations Sample page from NUMERICAL RECIPES IN C: THE ART OF SCIENTIFIC COMPUTING (ISBN 0- 521 -43108-5)Copyright (C) 1988-19 92 by Cambridge...
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Tài liệu Chapter 2: Indicators of Financial Structure, Development, and Soundness ppt

Tài liệu Chapter 2: Indicators of Financial Structure, Development, and Soundness ppt

Cao đẳng - Đại học

... of the outreach of bank-ing outlets. 25 Chapter 2: Indicators of Financial Structure, Development, and Soundness1IHGFEDCBA 12 11109876543 2 distribution of stress tests results, ... other indicators of competition. See chapter 4 for a discussion of model-based indicators of competition.6. For an example of the computation of the Herfindahl index, see chapter 15 of the Compilation ... discussion of these indicators can be found in section 2. 2.4.Table 2. 2 summarizes the indicators of financial system performance that have been discussed in this section. 2. 1.4 Scope and Coverage of...
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Tài liệu Numerical Solution of Stochastic Differential Equations with Jumps in Finance pdf

Tài liệu Numerical Solution of Stochastic Differential Equations with Jumps in Finance pdf

Quản trị kinh doanh

... Đ1.8 Chapter 2 Chapter 3 Chapter 5Đ6.1 Đ6 .2 Đ6.3Đ7.1 Đ7 .2 Đ7.3 Đ7.4Đ8.1 Đ8 .2 Đ8.3 Đ8.4 Đ8.5 Đ8.6 Đ8.8 Chapter 9 Chapter 10 Chapter 11Đ 12. 1 Đ 12. 2Đ13.1 Đ13 .2 Đ13.3 Đ13.4 Đ13.7 Chapter ... proofs the selected material provides the underlying mathe-matics. Chapter 1 Chapter 2 Chapter 4 Chapter 5Đ6.1 Đ6 .2 Đ6.3Đ7.1 Đ7 .2 Đ7.3 Đ7.4Đ8.1 Đ8 .2 Đ8.3 Đ8.4 Đ8.5 Đ8.6 Đ8.8 Đ8.9 Chapter ... background:Đ1.1 Đ1 .2 Đ1.3 Đ1.4 Đ1.5 Đ1.6 Đ1.7 Đ1.8Đ5.1 Đ5 .2 Đ5.3 Đ5.4Đ6.1 Đ6 .2 Đ6.3Đ7.1 Đ7 .2 Đ7.3 Đ7.4Đ8.1 Đ8 .2 Đ8.3 Đ8.4 Đ8.5 Đ8.6 Đ8.8Đ11.1 Đ11 .2 Đ11.3 Đ11.4 Đ11.5Đ 12. 1 Đ 12. 2Đ13.1 Đ13 .2 Đ13.3...
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Chapter 2 Flow of Control potx

Chapter 2 Flow of Control potx

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... Copyright â 20 06 Pearson Addison-Wesley. All rights reserved. 2- 9Display 2. 3 Precedence of Operators (4 of 4) Copyright â 20 06 Pearson Addison-Wesley. All rights reserved. 2- 5Evaluating ... Display 2. 2 Truth Tables Copyright â 20 06 Pearson Addison-Wesley. All rights reserved. 2- 33Comma OperatorEvaluate list of expressions, returningvalue of the last expression♦Most often ... Addison-Wesley. All rights reserved. 2- 8Display 2. 3 Precedence of Operators (3 of 4) Copyright â 20 06 Pearson Addison-Wesley. All rights reserved. 2- 12 if-else Statement Syntax♦Formal syntax:if...
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