... 10. 2 .0. 0 is directly connected, Serial0 /0/ 0 R 10. 3 .0. 0 [1 20/ 1] via 10. 2 .0. 2, 00 :00 : 04 , Serial0 /0/ 0 C 10. 1 .0. 0 is directly connected, FastEthernet0 /0 R 10 .4. 0.0 [1 20/ 2] via 10. 2 .0. 2, 00 :00 : 04 , ... Serial 0/ 0 /0 10. 3 .0. 0 available through interface Serial 0/ 0/1 R3: 10. 3 .0. 0 available through interface Serial 0/ 0 /0 10 .4. 0.0 available through interface FastEthernet 0/ 0 21 Initial Exchange of Routing ... network 10 .4. 0.0 on Serial 0/ 0 /0 with a metric of (new) Stores network 10 .4. 0.0 in the routing table with a metric of Same update from R2 contains information about network 10. 3 .0. 0 on Serial 0/ 0/0...
... 10. 5 .0. 0/ 16 via R2 Serial 0/ 0 /0 at a cost of 22 20 33 Determining the Shortest Path Network 10. 6 .0. 0/ 16 via R3 Serial 0/ 0/1 at a cost of 34 Determining the Shortest Path 10 Network 10. 7 .0. 0/ 16 ... from R4: Connected to neighbor R1 on network 10 .4. 0. 0/ 16, cost of 20 Connected to neighbor R3 on network 10. 7 .0. 0/ 16, cost of 10 Connected to neighbor R5 on network 10. 10. 0 .0/ 16, cost of 10 29 ... R3 Serial 0/ 0/1 at a cost of 15 35 Determining the Shortest Path 10 Network 10. 8 .0. 0/ 16 via R3 Serial 0/ 0/1 at a cost of 17 36 Network 10. 9 .0. 0/ 16 via R2 Serial 0/ 0 /0 at a cost of 30 Determining...
... class B network 172. 30. 0 .0/ 16: –172. 30. 100 .0/ 24 (FastEthernet 0/ 0) 172. 30. 100 .0/ 24 –172. 30. 1 10. 0/ 24 (Loopback 0) –172. 30. 200 . 16/ 28 (Loopback 1) –172. 30. 200 .32/28 (L 172 30 200 32/28 (Loopback 2) ... R1 and R3 have had the 172. 30. 0 .0/ 16 network subnetted into / 24 subnets subnets –Four of these / 24 subnets are assigned: –two to R1 (172. 30. 1 .0/ 24 and ( 172. 30. 2 .0/ 24) –two to R3 (172. 30. 100 .0/ 24 ... the 172. 30. 0.0 network in its updates to either R1 or R3 •Because the split horizon rule is in effect •R2 learned about 172 30 0/ 16 on both the 172. 30. 0 .0/ 16 Serial 0/ 0 /0 and Serial 0/ 0/1 interfaces,...