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Blender master class

Blender master class

Thiết kế - Đồ họa - Flash

... 21 1 21 1 21 1 21 3 21 3 21 3 21 4 21 5 21 5 21 6 21 6 21 8 21 8 21 9 22 1 22 2 22 2 22 2 22 3 Lighting the Spider Bot Lighting the Jungle Temple World Background ... 22 3 22 4 22 4 22 4 22 5 22 5 22 5 22 6 22 7 14  Rendering and Compositing 22 9 The Render Tab Rendering with Blender Internal Rendering with Cycles ... 19 20 21 22 22 23 23 24 24 24 24 26 26 27 27 28 29 Basic Modeling Terms 29 Edit Mode 29 Other Ways to Model: Curves 32 Modifiers...
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handbook of fluidization and fluid-particle systems

handbook of fluidization and fluid-particle systems

Hóa học - Dầu khí

... California 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 Fluid Catalytic Cracking with Zeolite Catalysts, Paul B Venuto and E Thomas Habib, Jr Ethylene: Keystone to the Petrochemical ... 0. 42 0.35 — 0 .29 7 0 .25 0 0 .21 0 0.177 0.149 — 0. 125 0.105 0.088 — 0.074 0.0 62 0.053 0.044 0.038 0. 020 31 — 10 — 12 — 14 — 16 20 — 24 — 28 — 32 35 42 — 48 60 65 80 100 — 115 150 170 — 20 0 25 0 27 0 ... — 20 0 25 0 27 0 325 400 — — — — — 10 — 12 — 14 — 16 18 — 22 — 25 — 30 36 44 — 52 60 72 85 100 — 120 150 170 — 20 0 24 0 300 — — — — — — 3.353 2. 8 12 — 2. 411 2. 057 1.676 — 1.405 — 1 .20 4 — 1.003 0.853...
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Children’s Health Deficits due to Diarrhoea: Effects of Water Supply and Sanitation Systems in Slums with Different Water Logging Conditions

Children’s Health Deficits due to Diarrhoea: Effects of Water Supply and Sanitation Systems in Slums with Different Water Logging Conditions

Môi trường

... 5 42 316 538 19.8 27 .8 16.4 15 .2 222 357 144 164 336 541 21 9 24 9 Long-term inundation communities (average) Stagnant (LSD) Heavy rainy (LHT) Monsoon flood (LMK) 373 386 28 0 454 30.0 43.5 17 .2 29.4 ... visit, they described how to confirm the presence of diarrhoea They also demonstrated how to mark the day that symptoms first started and the day that the illness ended or the child succumbed to the ... 29 .4 28 1 4 42 114 28 7 426 670 173 436 Persistent inundation communities (average) Drainage (PDL) Heavy rainy (PHS) Stagnant (PSM) 543 679 500 449 36.4 46.3 30.3 32. 6 410 556 329 347 622 843 499 525 ...
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Integration of energy and environmental systems in wastewater treatment plants

Integration of energy and environmental systems in wastewater treatment plants

Môi trường

... variables, and the correlation among them is identified The ISSN 20 76 -28 95 (Print), ISSN 20 76 -29 09 (Online) 20 12 International Energy & Environment Foundation All rights reserved 526 International ... Issue 4, 20 12, pp. 521 -530 527 process is estimated based on the purification process The BOD level is mainly affected in the oxidation ditch; the dissolved oxygen brings down the BOD level in the ... on the other factors such as BOD, suspended solids, average flow, and observations from the other plants with similar conditions The BOD level of the influent is noted for every month, and the...
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Spectroscopic and Microscopic Investigation of Gold NanoparticleFormation: Ligand and Temperature Effects on Rate and Particle Size

Spectroscopic and Microscopic Investigation of Gold NanoparticleFormation: Ligand and Temperature Effects on Rate and Particle Size

Năng lượng

... discuss the correlation of these reaction parameters with the size and the size dispersion of the AuNPs We relate the particle size with the stages of the nanoparticle growth including the rate ... M S Science 1991, 25 2, 688–691 ( 32) Guo, R.; Song, Y.; Wang, G.; Murray, R W J Am Chem Soc 20 05, 127 , 27 52 27 57 (33) Song, Y.; Murray, R W J Am Chem Soc 20 02, 124 , 7096–71 02 (34) Brennan, J L.; ... size (nm)c 25 65 520 3.3 (0.3) 40 45 520 3.1 (0.3) 50 15 518 2. 0 (0.3) 60 5 12 1.7 (0 .2) 70 5 12 1.5 (0 .2) a In each case, at least 20 0 particles were analyzed to determine the size and the size...
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The 8051 microcontroller and embedded systems using assembly and c 2nd ed

The 8051 microcontroller and embedded systems using assembly and c 2nd ed

Điện - Điện tử

... binary and then to decimal Convert directly from hex to decimal by summing the weight of all digits Ex 6B216 = 0110 1011 001 02 1 024 5 12 256 128 64 32 16 1 1 1 0 1 024 + 5 12 + 128 + 32 + 16 + = ... binary number Ex Convert 25 10 to binary Quotient Remainder 25 /2 = 12 LSB (least significant bit) 12/ 2 = 6 /2 = 3 /2 = 1 1 /2 = MSB (most significant bit) Therefore 25 10 = 1100 12 HANEL Department of ... 1 32 + + + = 45 4510 = 0010 110 12 = 2D16 Ex Convert 629 10 to hex 5 12 256 128 64 32 16 1 0 1 1 629 10 = 5 12+ 64+ 32+ 16+4+1 = 0010 0111 010 12 = 27 516 HANEL Department of Computer Science and Information...
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Effect - Particle Systems

Effect - Particle Systems

Kỹ thuật lập trình

... overlap in the scene, usually one is drawn and then the other is drawn “over” the first In other words, the pixels that make up the second node replace the pixels that make up the first If the second ... the Particle from its parent removes the particle from the scene, while removing the Particle from particles stops doStep from being called Lastly, the doStep method updates the location of the ... random.nextFloat() *2. 0*Math.PI; deltaX = Math.cos(theta)*speed; deltaY = Math.sin(theta)*speed; The change in X per step (deltaX) is simply the cosine of the angle theta multiplied by speed The change in...
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Nano and Microelectromechanical Systems P4

Nano and Microelectromechanical Systems P4

Cơ khí - Chế tạo máy

... V/2n) Bit 25 6 19.5 mV None 38 ±50 0.51 25 6 19.5 mV 76 25 0 .26 25 6 19.5 mV 2. 63 100 20 0 .20 25 6 19.5 mV 5 .26 20 0 ±10 0.10 1, 024 4.9 mV None 38 ±50 0.13 1, 024 4.9 mV 76 25 0.06 1, 024 4.9 mV 2. 63 ... mV 2. 63 100 20 0.05 1, 024 4.9 mV 5 .26 20 0 ±10 0. 02 4,096 1 .2 mV None 38 ±50 0.03 4,096 1 .2 mV 76 25 0. 02 4,096 1 .2 mV 2. 63 100 20 0.01 4,096 1 .2 mV 5 .26 20 0 ±10 0.006 10 Bit 12 Bit Table III ... scaling The table provides practical component values R3 VALUE Cf (µF) 100Hz Cf (µF) 30Hz Cf (µF) 10Hz 76m/g 25 g 2. 0 20 0kΩ 0.00 82 0. 027 0.0 82 100m/g 20 g 2. 6 26 1kΩ 0.0056 0. 022 0.056 20 0m/g ±10g...
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Nano and Microelectromechanical Systems P6

Nano and Microelectromechanical Systems P6

Cơ khí - Chế tạo máy

... x2 ) = (x Thus, V ( x1 , x2 ) > The total derivative is © 20 01 by CRC Press LLC ) + x2 ) dV ( x1 , x2 ) & & = x1 x1 + x2 x2 = − x 12 − x2 (1 + x2 ) dt dV ( x1 , x2 ) Therefore, < Hence, the ... finds r '2 = r + r 02 − 2rr0 sin θ sin φ Assuming that r >> r 02 , we have © 20 01 by CRC Press LLC 1  r0  ≈ 1 + sin θ sin φ  r' r  r  Therefore µ ir A = aφ 0 2 = aφ µ ir0 2 r π /2 sin φ ...  (4 .2. 6) To design the Lyapunov functions, the nonnegative integers were used In particular, η = 0,1 ,2, , γ = 0,1 ,2, , ς = 0,1 ,2, , β = 0,1 ,2 , σ = 0,1 ,2, , and µ = 0,1 ,2, From (4 .2. 3) and...
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Nano and Microelectromechanical Systems P5

Nano and Microelectromechanical Systems P5

Cơ khí - Chế tạo máy

... ibs (t ) = 2i M cos ω r t − π = 2i M cos ω e t − π = 2i M cos θ r − π , ics (t ) = 2i M r 2 2i M using the trigonometric identity ( e ( ) 2i M r + π ) cos2 θr + cos2 θ r − π + cos2 θr + π = , ... q 12 + (Lasbs + Lbsas )q1q2 + (Lascs + Lcsas )q1q3 2 &2 & & &2 + Lbsbs q2 + (Lbscs + Lcsbs )q2 q3 + Lc scs q3 ( ) ( ) & & & &2 + ψ m q1 sin q4 + ψ m q2 sin q4 − π + ψ m q3 sin q4 + π + Jq4 3 Then, ...  L2 − L L − L2 ω r ss ss m m + ψ m Lm − ω  L2 − Lss Lm − Lm r ss  P ψm  i J as    Lm 2 L2 − Lss Lm − Lm ss Lss − Lm 2 Lss − Lss Lm − Lm Lm 2 Lss − Lss Lm − Lm 0  ψ m Lm ωr  2 L2 −...
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The Future of Wireless Banking Implementation of Wireless Banking and Financial Systems

The Future of Wireless Banking Implementation of Wireless Banking and Financial Systems

Ngân hàng - Tín dụng

... verification The application server communicates with the gateway server for the specific device that initiates the request The gateway will push the information to the handheld device according to the ... over the handheld device The application server will make decisions for the basic content and push data to the handheld device without waiting for the client’s request In either, method authentication ... At this time, the data will be formatted into appropriate screens for the device that requested the data The data will be passed back to the wireless server provider gateway, and then back to the...
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Darwinism, Design, and Complex Systems Dynamics

Darwinism, Design, and Complex Systems Dynamics

TOEFL - IELTS - TOEIC

... conform to the requirements of the Second Law of Thermodynamics They exploit that law in becoming the kinds of systems they are Behe’s key claim is that there is no way that natural explanations ... possible explanations Unfortunately, too, this is something both camps seem to prefer Both assume that there are only two alternatives and P1: KAF/KAA P2: KaF 0 521 829 496c09.xml CY335B/Dembski 176 521 ... denies that there is any other possible natural explanation, he reasons by disjunctive syllogism that the only other possible explanation is intelligent design We can call this “the argument to the...
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GSM, cdmaOne and 3G systems P1

GSM, cdmaOne and 3G systems P1

Điện - Điện tử

... cells, M, in this cluster is the ratio of the area of the cluster to the area of the cell, which is equal to the ratio of the distance squared between the centres of the clusters to the distance ... considered to be the most likely message sequence In the maximal likelihood decoding algorithm, or the Viterbi algorithm, all the possible paths in the trellis are searched The path having the smallest ... see that the packetiser accepts both the interleaved coded speech and a sounding bit sequence This sounding sequence is placed in the centre of the packet with the coded data on either side If the...
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Tài liệu GSM, cdmaOne and 3G systems P3 doc

Tài liệu GSM, cdmaOne and 3G systems P3 doc

Điện - Điện tử

... E 10ζ=10 i Z = exp ζ 10 = ∞ 2 2 2 ln(10) ln(10) σ exp 10 p pζ 2 σ ln(10) 10 Z 10 2 dζ ∞ p pζ exp ln(10) 2 (4π 2 )1 =2 ∞ exp dζ (4π 2 )1 =2 ∞ Z = ∞ 2 10 2 dζ (4π 2 )1 =2 ∞ and the integral is ... mean The expectation is, therefore, E 10ζ=10] = E 10 ζ=10 ] = Q( ) where Q(k) E 10ζ=10] = = p1 Q (2) Z 2 ∞ k σ ln(10) 10 Z 2p2σ exp p p 10 2 ζ=10 2 exp( 2 =2) 1: 023 exp p 2 and 2 , then we ... Equa- Z 2p2σ 2 ln(10)=10 (3.14) p If we truncate the normal distribution of ζ at tion (3.13) as p σ ln(10) 10 exp ln(10) 2 4 2 (4π 2 )1 =2 exp : dζ (3.15) dλ n pζ p 2 2 (4π 2 )1 =2 ln(10) o2 10...
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Tài liệu GSM, cdmaOne and 3G systems P4 pdf

Tài liệu GSM, cdmaOne and 3G systems P4 pdf

Điện - Điện tử

... traffic (bits/ frame) 26 5 124 54 20 124 54 20 20 124 54 20 54 20 20 54 0 20 20 20 0 137 20 7 24 1 26 1 0 0 22 1 67 101 121 0 81 52 32 0 0 0 0 137 20 7 24 1 26 1 20 0 0 67 101 121 20 0 52 32 20 Pilot Channel ... correspond to those in Figure 4 .22 Time ! Path 1 Point A Path Path Path Point B Path Path 3 7 Path Point C Path Path 7 Path Point D Path Path 7 5 4 3 7 5 2 10 11 12 13 14 15 16 17 18 19 20 21 22 23 7 ... on the CHAPTER THE CDMAONE SYSTEM 21 0 Code Index Bit Position 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53...
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Tài liệu GSM, cdmaOne and 3G systems P5 pdf

Tài liệu GSM, cdmaOne and 3G systems P5 pdf

Điện - Điện tử

... the zeroth BS and the zeroth mobile in the zeroth cell, and for the jth BS to the zeroth mobile in the zeroth cell, respectively Assuming that the receiver is correctly chip synchronised to the ... r ∞ ζ ζln(10) exp 4 2 exp dζ 4π 2 p = exp = exp Z 10α log σln(10) σln(10) ( " Q exp rj r h p pζ p 222 ln(10) i2 dζ p 10α log p rj r 2 ln(10) 2 #) : (5.88) By knowing the mean and variance ... cos(ω2t + θ j ) (5.1 12) where τ0, τi and τi j are the random time delay for the zeroth mobile in the zeroth cell, the ith mobile in the zeroth cell, and the ith mobile in the jth cell, respectively...
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Tài liệu GSM, cdmaOne and 3G systems P6 pdf

Tài liệu GSM, cdmaOne and 3G systems P6 pdf

Điện - Điện tử

... band (MHz) 1885–1900 1900–1 920 1 920 –1980 1980 20 10 20 10 20 25 21 10 21 70 21 70 22 00 Comment Unpaired Unpaired Paired with MSS paired with Unpaired Paired with MSS paired with CHAPTER EVOLUTION OF GSM ... MS multislot classes Multislot class 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 b= c= ( ( Maximum number of slots Rx Tx Sum 1 2 2 3 2 4 3 4 5 5 4 3 NA 4 NA 5 NA 6 NA 7 NA 8 NA ... Cch 2( n+1) 2i = (Cch 2n iCch 2n i ) (6 .2) and Cch 2( n+1) 2i+1 = (Cch 2n i Cch 2n i ): (6.3) For an additional code to be used in a cell the following criterion is applied: none of the codes in the...
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Tài liệu Robotics and Autonomous Systems docx

Tài liệu Robotics and Autonomous Systems docx

Cơ khí - Chế tạo máy

... − |Cωg | This expresses the following rule: the more the robot is pointed towards the goal direction or the further the robot is from the goal, the faster it can move (knowing that the speed ... representing the dilatation The optimal path obtained by the A∗ algorithm is the dashed line joining the source point to the goal point through some sub-goals indicated by the black points The path to ... robot in the memorized and the real environments ( p), knowing that the virtual robot moves along with the orthogonal projection on the planned path of the center point M of the real robot The SFI...
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Tài liệu GSM, cdmaOne and 3G Systems P4 docx

Tài liệu GSM, cdmaOne and 3G Systems P4 docx

Hóa học - Dầu khí

... traffic (bits/ frame) 26 5 124 54 20 124 54 20 20 124 54 20 54 20 20 54 0 20 20 20 0 137 20 7 24 1 26 1 0 0 22 1 67 101 121 0 81 52 32 0 0 0 0 137 20 7 24 1 26 1 20 0 0 67 101 121 20 0 52 32 20 Pilot Channel ... correspond to those in Figure 4 .22 Time ! Path 1 Point A Path Path Path Point B Path Path 3 7 Path Point C Path Path 7 Path Point D Path Path 7 5 4 3 7 5 2 10 11 12 13 14 15 16 17 18 19 20 21 22 23 7 ... on the CHAPTER THE CDMAONE SYSTEM 21 0 Code Index Bit Position 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53...
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Tài liệu GSM, cdmaOne and 3G Systems P5 pptx

Tài liệu GSM, cdmaOne and 3G Systems P5 pptx

Hóa học - Dầu khí

... the zeroth BS and the zeroth mobile in the zeroth cell, and for the jth BS to the zeroth mobile in the zeroth cell, respectively Assuming that the receiver is correctly chip synchronised to the ... r ∞ ζ ζln(10) exp 4 2 exp dζ 4π 2 p = exp = exp Z 10α log σln(10) σln(10) ( " Q exp rj r h p pζ p 222 ln(10) i2 dζ p 10α log p rj r 2 ln(10) 2 #) : (5.88) By knowing the mean and variance ... cos(ω2t + θ j ) (5.1 12) where τ0, τi and τi j are the random time delay for the zeroth mobile in the zeroth cell, the ith mobile in the zeroth cell, and the ith mobile in the jth cell, respectively...
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