beyond 5 ht 1a and 5 ht 2 receptor subtypes
Mpeg 7 audio and beyond audio content indexing and retrieval phần 2 doc
... mean Figure 2. 8 illustrates the coefficient grouping procedure within two consecutive bands b (between f = 23 /4 kHz ≈ 1681 Hz and f = kHz) and b + (between f = kHz and f = 25 / 4 kHz ≈ 23 78 Hz) As ... Figure 2 .5 The Bin within-band band power coefficients are completed by two additional values: the powers of the spectrum between Hz and loEdge and between hiEdge and the Nyquist frequency Fs /2 (provided ... = P k = k=0 (2. 23) FT P k + Klow for ≤ k ≤ N2 − Klow The frequencies f k corresponding to the new bins k are given by: f k = for k = FT for ≤ k ≤ N2 − Klow 31 25 f k + Klow (2. 24) where f k...
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Tài liệu Báo cáo khoa học: 1,5-Diamino-2-pentyne is both a substrate and inactivator of plant copper amine oxidases ppt
... and 22 2.3 The former ion showed fragment peaks with m/z 161.3, 149 .2 and 1 35. 2, the latter provided peaks with m/z 2 05. 2, 193 .2 and 176 .2 in the respective MS/MS spectra The peak with m/z 22 2.3 ... those with m/z 178.1 and 25 7 .1 there were three more peaks with m/z 334.3 (fragmentation: m/z 317.3, 3 05. 2, 29 1.1, 25 3 .2 and 24 0.1), 350 .2 (fragmentation: m/z 333 .2 and 307.1) and 431.3 (fragmentation: ... values and elemental composition of ions: 161.11 (C10H13N2), 149.11 (C9H13N2), 1 35. 09 (C8H11N2), 109.08 (C6H9N2), 95. 06 (C5H7N2) and 82. 06 (C5H8N) Ó FEBS 20 04 4704 Z Lamplot et al (Eur J Biochem 27 1)...
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Báo cáo khoa học: Vitamin D stimulates apoptosis in gastric cancer cells in synergy with trichostatin A ⁄sodium butyrate-induced and 5-aza-2¢-deoxycytidine-induced PTEN upregulation ppt
... [19 ,20 ], p14 [21 ], p 15 [22 ,23 ], p16 [24 ], PTEN [ 25 ] , and RASSF1A [ 25 ] , exhibit genetic and epigenetic alterations Some of these genes can be reactivated by the DNA methylation inhibitor 5- aza -2 -deoxycytidine ... 1 02 1.9 5- 10 10 1 02 Annexin V-FITC 17.74% 10 10 B3 10 B4 1. 72% B1 10 100 1 02 Annexin V-FITC B2 3.94% 10 7 .59 % B3 B4 2. 44% 100 10 1 02 Annexin V-FITC 10 Control 5- Aza * 35 5-Aza B3 + VD3 26 . 45% ... single-strand conformation polymorphism analysis Cancer Res 51 , 3 056 –3 058 19 Becker KF, Atkinson MJ, Reich U, Becker I, Nekarda H, Siewert JR & Hofler H (1994) E-cadherin gene 998 20 21 22 23 24 25 26 27 ...
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Giáo án Tiếng anh lớp 6 - Unit 8: OUT AND ABOUT - Lesson 5 B 2 ppt
... 8: T OUT AND ABOUT T eliciting the words Lesson B Vocabulary (to) copy chep (to) correct sua loi 5 - Introduce the dialogue between Lan and Ba Lan is asking Ba about what Ba, Tuan, Nga and Huong ... questions and the answers in the dialogue - Ask Ss to read the questions, read 10’ the dialogue again and find the *Answer the question answers a Ba is doing his homework - Listen and correct ... write the homework Homework: - Learn vocabulary by heart - Do the exercises at home - Prepare C1 -2 2’ - - THE END - ...
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Giáo án Anh văn lớp 6 - Period 59 - Unit 9 - Lesson 5 93 - AT HOME AND AWAY B1,2 P.92 potx
... her neighbor make the dress ? S2 : Yes, she did S1 : Did Hoa buy the material ? S3 : No, She didn’t IV Production : Guessing game Yesterday, I went to and I bought (a/ some) _ Did you go ... of a place / a shop) ? Did you buy _ (thing) ? IV Homework : Retell what you did yesterday ? (5 sentences) ...
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Metal Machining - Theory and Applications Episode 2 Part 5 ppsx
... stresses and temperatures; and for VB = 0 .5 mm) to be 0.00 65 mm/min at a cutting speed of 100 m/min and 0. 024 mm/min at 20 0 m/min, and its change as VB increased could be followed Childs Part 31:3 :20 00 ... et al., 19 92) (C5) f2 Ra = ——— ≤ Ra, max 31.3rn (9 .22 ) where Ra,max is the required surface finish Chatter Chatter limits (C6) have been given by equation (9.15b), (9.15c) or (9.15e), and are often ... gi (x) (9.32a) Childs Part 31:3 :20 00 10:38 am Page 29 2 29 2 Process selection, improvement and control Fig 9. 12 Fuzzy optimization of cutting conditions; only three constraints 1, and 10 are considered...
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Gear Noise and Vibration Episode 2 Part 5 pps
... Tooth No £ *: Tooth No - 25 0 (0 4) 0, Tooth No -300 - 350 l>^ s > * r " , ^ - Tooth No Tooth No 10 50 100 150 Time in minutes -100 - 150 -20 0 - 25 0 -300 150 Time in minutes Fig 15. 4 Test results from ... rattle and give noise and there are fewer high speed shafts so lubrication and churning losses are lower Lower tooth frequencies generally give lower noise Chapter 14 22 6 50 100 150 20 0 25 0 Fig ... rl = (brl*psil - brl*tan(phi2))/(pi*cos(phio)); r2 = (br2*psi2 - br2*tan(phi2))/(pi*cos(phio)); conratio = rl + r2; disp(f angle rl r2 contact ratio') disp([ phi2 rl r2 conratio ]) phi3 = input('enter...
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Gear Noise and Vibration Episode 2 Part 5 potx
... Tooth No £ *: Tooth No - 25 0 (0 4) 0, Tooth No -300 - 350 l>^ s > * r " , ^ - Tooth No Tooth No 10 50 100 150 Time in minutes -100 - 150 -20 0 - 25 0 -300 150 Time in minutes Fig 15. 4 Test results from ... rattle and give noise and there are fewer high speed shafts so lubrication and churning losses are lower Lower tooth frequencies generally give lower noise Chapter 14 22 6 50 100 150 20 0 25 0 Fig ... rl = (brl*psil - brl*tan(phi2))/(pi*cos(phio)); r2 = (br2*psi2 - br2*tan(phi2))/(pi*cos(phio)); conratio = rl + r2; disp(f angle rl r2 contact ratio') disp([ phi2 rl r2 conratio ]) phi3 = input('enter...
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Intelligent Vehicle Technology And Trends Episode 2 Part 5 pps
... Road Administration [10] http://www.estec.esa.nl/wmwww/EMS/ARTESpresentation.htm, accessed May 22 , 20 04 [11] http://www.probeit.org.uk, accessed December 12, 20 04 [ 12] Demir, C., et al., “FCD ... ReisezeitschÃtzung, day of notification: 12. 20 .20 02 [14] “Ford And Minnesota DOT Kickoff Road-Vehicle Communications Project,” IVsource.net, June 11, 20 04 [ 15] “Ford Launches Intelligent Highway ... surveys 12. 1 Driver Perception and Acceptance 27 3 Various assessments of public knowledge and perceptions of IV systems have been conducted and some are reviewed here 12. 1.1 Perceived Positives and...
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Machinery Components Maintenance And Repair Episode 2 Part 5 ppt
... application must be clean, and chip and splinter proof Figure 7 -54 Keep unboxed bearings covered until ready for mounting 426 Machinery Component Maintenance and Repair Figure 7 -55 Cover subassemblies, ... preloads—light, medium, or heavy The magnitude of the preload depends upon the speed of the spindle and required operating temperatures and rigidity requirements 422 Machinery Component Maintenance and ... bearing (Figure 7 -57 ) Note that in the “right” method of mounting, Figure 7 -56 Burnished dots show high point of eccentricity 428 Machinery Component Maintenance and Repair Figure 7 -57 “THRUST HERE”...
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Data Analysis Machine Learning and Applications Episode 2 Part 5 pps
... cluster 6, application: p2p down ( 12% ) x 10 20 0 30 Typical day 12 20 Global p2p down 0.6 0 Typical customer p2p up 0.8 10 11 12 13 14 volume (in byte) 10 15 20 25 15 20 25 global mean 10 x 10 0 ... (in byte) 10 15 20 25 15 20 25 Global mean 2 .5 x 10 1 .5 0 .5 0 10 Fig Profile of another cluster of customers (top left) and mean profile (bottom) and profiles of associated typical days and typical ... value pid lid name 423 alias max (sugg) learner inst kernel inst default 15 64 0. 25 15 64 C conf threshold false false 0. 25 0.01 0.99 15 65 15 65 M nr inst/leaf false false 2 20 Learner inst Learner...
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Adaptive Techniques for Dynamic Processor Optimization Theory and Practice Episode 2 Part 5 pot
... Design 24 7 [20 ] A Efthymiou and J.D Garside, “Adaptive Pipeline Structures for Speculation Control”, Proceedings of Async'03, Vancouver, May 20 03, pp 46 55 ISBN 0-76 95- 1898 -2 ISSN 1 52 2- 8681 [21 ] ... Clockless 32- Bit Processor Core”, IEEE Micro, March 20 07, Vol 27 , No 2, pp 58 –68 ISSN: 027 2-17 32 [9] I Sutherland, “Micropipelines”, Communications of the ACM, June 1989, Vol 32, No 6, pp. 720 –738 ... UK, 20 02 [19] A Efthymiou and J.D Garside, “Adaptive Pipeline Depth Control for Processor Power-Management”, Proceedings of ICCD' 02, Freiburg, September 20 02, pp 454 – 457 ISBN 0-76 95 1700 -5 ISSN...
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Advanced Mathematical Methods for Scientists and Engineers Episode 2 Part 5 pps
... n=0 ln (2n ) ln (3n ) + 1 ln(n + 20 ) 4n + 3n − ∞ (Logπ 2) n n=0 ∞ n =2 ∞ 10 n =2 n2 − n4 − n2 (ln n)n ∞ (−1)n ln 11 n =2 ∞ 12 n =2 ∞ 13 n =2 n (n! )2 (2n)! 3n + 4n + 5n − 4n − 56 2 ∞ 14 n =2 ∞ 15 n =2 ∞ 16 ... z +2 z + 5z + 1 √ =√ + z/3 + z /2 −1 /2 z −1 /2 z = √ 1+ + + ··· 3 z 3z z z2 = √ 1− + + ··· 1− + + ··· 24 32 17 = √ − z + z2 + · · · 12 96 12. 6 1+ −1 /2 z −1 /2 + 2 z 2 + ··· Laurent Series Result 12. 6.1 ... n=0 (ln 2) n n! (n + 1)(n + 2) 2n (−1)n n! (−1)n π 2n+1 (2n + 1)! (−1)n π 2n (2n)! (−π)n (2n)! Hint, Solution 57 0 Exercise 12. 24 Find the first three terms in the following Taylor series and state...
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Advanced Mathematical Methods for Scientists and Engineers Episode 5 Part 2 docx
... 15 25 35 45 Γ(n) 24 8.71783 · 1010 6 .20 448 · 1 023 2. 9 52 33 · 1038 2. 658 27 · 1 054 √ 2 xx−1 /2 e−x relative error 23 .6038 0.01 65 8.66 954 · 1010 0.0 055 6.18384 · 1 023 0.0033 2. 9 453 1 · 1038 0.0 024 54 ... J1 /2 (z) z 1 /2 1 /2 = z −1 /2 sin z − − z π J3 /2 (z) = π 1 /2 z −3 /2 sin z − π 1 /2 z −1 /2 cos z = 2 1 /2 π −1 /2 z −3 /2 sin z + 2 1 /2 π −1 /2 z −3 /2 sin z − 2 1 /2 π −1 /2 cos z π 1 /2 = π 1 /2 = z −3 /2 ... · + 2 4···n·(2n 2) ···(2n−n) ζ n+1 2( 2n 2) 2 4·(2n 2) (2n−4) cn (ζ) = ζ4 ζ n−1 2n−1 n! + ζ + + · · · + 2 4···(n−1)·(2n 2) ···(2n−(n−1)) ζ n+1 2( 2n 2) 2 4·(2n 2) (2n−4) 16 42 for even n for odd n...
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Biofuels, Solar and Wind as Renewable Energy Systems_Benefits and Risks Episode 2 Part 5 pdf
... kga 1 85 kga 23 7 kga 27 kga 12, 000 kgq 5. 8 kga 2 .5 kga 7 15 kgt 1, 621 b 917e 4,902g 3,136i 444k 603m 96o 53 p 20 7r 58 0s 25 0 s 59 3t 52 0.00c 26 4.44f 860.00h 107.80j 73.16l 57 .35n 4.74o 27 .00h 23 0.00h ... unit 15. 37 451 .66 363.83 7.84 13.07 47.73 54 .00 3.19 5. 89 1.31 MJ/unit This study 127 09.7 1003 .5 17 85. 6 1064.4 3061.8 51 .0 488.9 478.9 25 2 .2 14 45. 3 87.3 27 6.8 2 058 .0 MJ/ha/yr 128 156 22 .3 58 .3 ... energy and energy balance computed in this study and that of Pimentel and Patzek (20 07) 49174 .2 656 .6 26 68.1 10 62. 2 3901.8 25 0 .9 1 129 .1 476.7 8 65. 7 20 91.0 836.4 2 25 8 .3 329 77.4 MJ/ha/yr 3 42 R.M...
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Giáo án Anh văn lớp 6 : Tên bài dạy : UNIT 12. SPORTS AND PASTIMES Lesson 2 A3-5 (P125-126) potx
... 2 Pre reading Open prediction Students predict which sport Lan and Nam like (3 each) Lan Nam 1 2 3 While reading A4 P 126 Student read and correct open prediction ... asking and answering questions Post reading Picture drill: A3 P1 25 a→f Example exchange: S1: which sports you do? S2: I (play soccer) and I (swim) Nb: “which sports you play?” is wrong The correct ... you do? S2: I swim S1: what else? S2: I play volleyball S1: you play table tennis? S2: yes, I Name Sports Hoa Swim Volleyball Table tennis III HOME WORK: - Learn by heart vocabulary and pattern...
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Giáo án Anh văn lớp 7 : Tên bài dạy : Unit 5: Work and play. Lesson 2: A2. pdf
... doing in picture ? - Ss guess what they are going to * While - reading: - Ss read through the text and find out the new words - T explains some new words: enjoy(v ) electronics (n ) household appliances ... questions in texbook - Ask Ss to practice in pairs - Call some pairs to practice aloud - Give the right answers: a Ba likes Electronics best b Yes, he does He enjoys school very much c He learn to ... will be able to fix his own appliances f Yes, he is His drawings are very good - Ss copy the right answers * Post - reading: - Ask Ss to practice in pairs to answer the part: About you - Call...
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Giáo án Anh văn lớp 7 : Tên bài dạy : Unit 5: Work and play. Lesson 2: A4-5. pptx
... listening: - Ss look at the pictures and answer the guided questions: What are the pictures about ? What school subjects you like best ? Can you guess what subjects Ba and Hoa have on Saturday ? ... some Ss to give their own answers - T plays the the last time and pauses at each sentence for Ss to check their answers - Give the right answers: Ba: d, a, e Hoa: c, b, e * Post - listening: - Ss ... Science : Preposition English : England 4.Consolidation : - Remind Ss the special words for each subject Homework: - Do Ex in workbook - Prepare the next lesson B1-B2 ...
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Báo cáo khoa học: "The combination effect of sodium butyrate and 5-Aza-2''''-deoxycytidine on radiosensitivity in RKO colorectal cancer and MCF-7 breast cancer cell lines" pot
... Time(min) p14ARF 95 62/ 62 30 40 72 p16INK4a 95 63/63 30 40 72 E-cadherin 95 55/ 57 30 40 72 MINT1(M1) 95 52 / 52 30 37 72 MINT2(M2) 95 59 /59 30 40 72 MINT31(M31) 95 62/ 60 30 38 72 Statistical analysis ... Deacetylase inhibitor and Demethylating agent chromatin compaction and the radiation response by cancer cells Cancer J 20 07, 13: 65- 69 17 18 19 20 21 22 23 24 25 26 27 28 29 Zhu WG, Otterson GA: ... CCD-1 12 RKO Control 87 .2 ± 5. 2 (0.97 ± 0.01) 99.1 ± 4.7 (1.00 ± 0.01) 56 .5 ± 9.7 (0.87 ± 0.04) 5- azaDC 73.7 ± 9.6 (0.93 ± 0.03) 1 02. 6 ± 3.1 (1.01 ± 0.01) 47.1 ± 4.3 (0.84 ± 0. 02) SB 55 .7 ± 5. 1...
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Mpeg 7 audio and beyond audio content indexing and retrieval phần 5 ppt
... the case of words) S5 HMM for word W λw (*) S4 S3 S2 S1 x1 x2 x3 x4 x5 x6 Acoustic Observation X (*) Likelihood Score = b1(x1).a13.b3(x2).a34.b4(x3).a44.b4(x4).a 45. b5(x5).a 55. b5(x6) Figure 4.3 Result ... considering q t and d t as Boolean variables (with a Boolean weighting scheme) and combining q and d as in Equation (4. 12) with addition and multiplication operators representing the logical AND and OR ... sub-lexical indexing terms, such as phones (Ng, 20 00; Ng and Zue, 20 00), phonemes (Ferrieux and Peillon, 1999; Wechsler, 1998) or syllables (Larson and Eickeler, 20 03) Sub-word-based SDR has the advantages...
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