a multitude of structure based explanations
Testing a model of customer-based brand equity in the Vietnamese banking servic
Ngày tải lên :
06/11/2012, 15:52
... are 10 factors extracted at Eigenvalues of 1.022 and total explained variance of 70.641 all factor loading are greater than the cut-off value of 0.4 The result of KMO and Bartlett's Test is also ... concepts and has been an area of interest for marketing academics and practitioners as well There are a numbers of models of brand equity in common marketing settings (Farquhar,1989; David A Aaker, 1991; ... qualitative or quantitative approach or a combination of these two types Data can be acquired via a variety of strategies such as experiment, survey, case study, grounded theory or action research...
- 81
- 562
- 1
Tài liệu Báo cáo khoa học: Deciphering enzymes Genetic selection as a probe of structure and mechanism docx
Ngày tải lên :
19/02/2014, 12:20
... strain and the ability of a cell harboring an individual library member to form a colony on minimal agar media lacking added phenylalanine and tyrosine reports on the chorismate mutase activity of ... chorismate mutase by combinatorial mutagenesis and selection: the importance of electrostatic catalysis Proc Natl Acad Sci USA 93, 5043–5048 11 Haslam, E (1993) Shikimic Acid: Metabolism and Metabolites ... natural evolution of bacterial antibiotic resistance Hydrolysis of aztreonam requires a change in the substrate specificity of TEM-1 b-lactamase The chance of finding the three mutations that effected...
- 8
- 635
- 0
Application of serum proteomics to the Women’s Health Initiative conjugated equine estrogens trial reveals a multitude of effects relevant to clinical findings pot
Ngày tải lên :
28/03/2014, 14:20
... interpretation, and carried out immunoassays RP participated in the design of the study, statistical analysis, and data interpretation, and drafted the manuscript AA performed the statistical analysis ... 158:20-29 33 Jarvinen AK, Autio R, Haapa-Paananen S, Wolf M, Saarela M, Grenman R, Leivo I, Kallioniemi O, Makitie AA, Monni O: Identification of target genes in laryngeal squamous cell carcinoma by high-resolution ... Diabetes Study Genet Epidemiol 1989, 6:691-698 61 Ikeda Y, Imai Y, Kumagai H, Nosaka T, Morikawa Y, Hisaoka T, Manabe I, Maemura K, Nakaoka T, Imamura T, Miyazono K, Komuro I, Nagai R, Kitamura...
- 16
- 598
- 0
a multitude of monsters
Ngày tải lên :
30/05/2014, 23:01
... our name! AFTAOMAIBAC! AFTAOMAIBAC! AFTAOMAIBAC!" A ragged cheer arose from the crowd as they attempted to repeat the group's name So I would be eaten at last Unless-could I dare hope? There was ... I had to talk with Norei again, anyway! It was a brilliant stroke Maybe I would survive this after all I began to think of grackles "AFTAOMAIBAC! AFTAOMAIBAC!" It was hard to concentrate with ... than words It began as the cry of an eagle and ended as the roar of a lion, embodying the harsher characteristics of both calls All in all, it was quite unpleasant "Oh, Pop, come off it!" Another...
- 121
- 131
- 0
báo cáo hóa học: " Back disorders and lumbar load in nursing staff in geriatric care: a comparison of home-based care and nursing homes" pptx
Ngày tải lên :
20/06/2014, 00:20
... statistical analyses, interpreted the data and drafted the manuscript MD participated in the design of the study, interpreted the data and drafted the manuscript AN participated in the design of ... study and interpreted the data BBB participated in the coordination of the study and helped to draft the manuscript All authors read and approved the manuscript Additional material 15 16 17 18 Additional ... that had calculated lumbar load for the sum of daily patient transfer activities We found higher figures of lumbar load in nursing home staff and at the same time back disorders were significantly...
- 9
- 638
- 0
A textbook of Computer Based Numerical and Statiscal Techniques part 62 docx
Ngày tải lên :
04/07/2014, 15:20
... COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUES Enter the value of y2 – 392 Enter the value of y3 – 1452 Enter the value of y4 – 2366 Enter the value of y5 – 5202 Enter the value of x for ... subintervals = Value of the integral is: 1.3571 603 COMPUTER PROGRAMMING IN ‘C’ LANGUAGE 13.34 ALGORITHM FOR FITTING A STRAIGHT LINE OF THE FORM Y = a + bX Step Start of the program for fitting straight ... form of x– Enter the value of x1 – Enter the value of x2 – Enter the value of x3 – 11 Enter the value of x4 – 13 Enter the value of x5 – 17 Enter the value in the form of y– Enter the value of...
- 8
- 353
- 0
A textbook of Computer Based Numerical and Statiscal Techniques part 1 ppt
Ngày tải lên :
04/07/2014, 15:20
... syllabus of Mathematics for B Tech II year and M.C .A I year students of all Engineering colleges affiliated to U.P Technical University, Lucknow The subject matter is presented in a very systematic and ... systematic and logical manner In each chapter, all concepts, definitions and large number of examples in the best possible way have been discussed in detail and lucid manner so that the students ... understand the subject A unique feature of this book is to provide with an algorithm and computer program in Clanguage to understand the steps and methodology used in writing the program Thorough care...
- 10
- 425
- 1
A textbook of Computer Based Numerical and Statiscal Techniques part 2 ppsx
Ngày tải lên :
04/07/2014, 15:20
... numerical answer can be obtained even when a problem has no analytical solution However, result from numerical analysis is an approximation, in general, which can be made as accurate as desired ... significant figures at each step of computation At each step of computations, retain at least one more significant figure than that given in the data, perform the last operation, and then round off ... 0.285714 a quotient which is a nonterminating decimal fraction For using such a number in practical computation, it is to COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUES be cut-off to a manageable...
- 10
- 337
- 1
A textbook of Computer Based Numerical and Statiscal Techniques part 3 ppsx
Ngày tải lên :
04/07/2014, 15:20
... Here absolute error is least when approximate value is 0.33 Hence 0.33 is the best approximation Example Calculate the sum of and relative errors Sol Here 3, and to four significant digits and ... 8.6 Example Three approximate values of number are given as 0.30, 0.33 and 0.34 Which of these three is the best approximation? Sol The number, which has least absolute error, gives the best approximation ... Hence maximum percentage error (Ep)max = 11.667% = Example 26 How accurately should the length and time of vibration of a pendulum should be measured in order that the computed value of g is...
- 10
- 2.2K
- 2
A textbook of Computer Based Numerical and Statiscal Techniques part 4 ppt
Ngày tải lên :
04/07/2014, 15:20
... Given that Also a a ⇒ A = sin–1 b b A A + δb A < a a ∂b 1 % and % respectively sin A = a = ⇒ a = 0.1 a 100 δb = ⇒ δb = 0.2 b× 100 (1) 19 ERRORS AND FLOATING POINT A a A = = and 2 ∂b ... Sol Given δb = mm = 0.2 cm a = mm = 0.1 cm a a ⇒ A = sin−1 b b A 1 ⋅ = = b a a b − a2 1− b sin A = A = ∂b 1− A < a a b2 ⋅− a a =− 2 b b b − a2 A A + δb a a < 0.1 × < (5.7) − (2.3) 2 ... ERRORS AND FLOATING POINT Example 30 The error in the measurement of area of a circle is not allowed to exceed 0.5% How accurately the radius should be measured Sol Area of the circle =πr2 = A (say)...
- 10
- 580
- 0
A textbook of Computer Based Numerical and Statiscal Techniques part 5 ppsx
Ngày tải lên :
04/07/2014, 15:20
... mantissa and by adding the exponent of given normalized floating-point representation Similarly division is evaluated by division of mantissa of the numerator by that of the denominator and denominator ... It can also be written as 0.28el using normalized floating point representation because mantissa is greater than or equal to 0.1 29 ERRORS AND FLOATING POINT Example 12 Calculate the value of ... using direct analytical methods For example, for a quadratic equation ax2 + bx + c = 0, the roots of the equation, obtained by x1 = − b + b − ac 2a and x2 = − b − b − ac 2a These are called closed...
- 10
- 2.6K
- 3
A textbook of Computer Based Numerical and Statiscal Techniques part 6 pptx
Ngày tải lên :
04/07/2014, 15:20
... 37 ALGEBRAIC AND TRANSCENDENTAL EQUATION Here ei and ei + are the errors in ith and (i + 1)th iterations respectively Comparing the above equation with lim i →∞ ei +1 e k i A We get k = and A ... = Again, 43 ALGEBRAIC AND TRANSCENDENTAL EQUATION Thus, f(2.6875) is negative and f(2.75) is positive, therefore, the root lies between 2.6875 and 2.75 Fifth approximation: The fifth approximation ... f(0.375) is negative, therefore, a root lies between 0.375 and 0.4063 45 ALGEBRAIC AND TRANSCENDENTAL EQUATION Sixth approximation: The sixth approximation to the root is given by x6 = Again, 0.375...
- 10
- 469
- 1
A textbook of Computer Based Numerical and Statiscal Techniques part 7 potx
Ngày tải lên :
04/07/2014, 15:20
... x3 and x4 are approximately the same upto four places of decimal, hence the required root of the given equation is 1.4036 54 COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUES Example Find a ... correct to four places of decimal 53 ALGEBRAIC AND TRANSCENDENTAL EQUATION Example Using the method of False Position, find the root of equation x6 – x4 – x3 –1 = up to four decimal places Sol Let ... the order of convergence, it is necessary to find a formula of the type ei + = Ae k with an appropriate value of k i .(6) With the help of (6), we can write ei = Ae k or ei–1 = (ei /A) 1/k i− Now,...
- 10
- 452
- 1
A textbook of Computer Based Numerical and Statiscal Techniques part 8 doc
Ngày tải lên :
04/07/2014, 15:20
... the rate of convergence of Regula-Falsi method Find real cube root of 18 by Regula-Falsi method Discuss method of Falsi Position [Ans 4.4934] [Ans 3.5425] [Ans 0.6071] [Ans 2.62074] 2.6 ITERATION ... significant digits 61 ALGEBRAIC AND TRANSCENDENTAL EQUATION PROBLEM SET 2.2 Find the real root of the equation x3 – 2x – = by the method of Falsi Position correct to three decimal places [Ans 2.094] ... is approximated by 3.646 correct to three decimal places = 3.6460 + 59 ALGEBRAIC AND TRANSCENDENTAL EQUATION Example (1) Solve x3 – 5x + = by using Regula-Falsi method (2) Use the method of Falsi...
- 10
- 764
- 0
A textbook of Computer Based Numerical and Statiscal Techniques part 9 docx
Ngày tải lên :
04/07/2014, 15:20
... prescribed accuracy 2.7.2 Order (or Rate) of Convergence of Newton-Raphson Method Let α be the actual root of equation f(x) = i.e., f (a) = Let xn and xn+1 be two successive approximations to the actual ... decimal places So we have 12 = 3.4641 (2) 75 ALGEBRAIC AND TRANSCENDENTAL EQUATION Example Find a positive root of (17)1/3 correct to four decimal places by Newton-Raphson’s method Sol The iterative ... error at each step is proportional to the square of the previous error and as such the convergence is quadratic Example Find the real root of the equation x2 – 5x + = between and by NewtonRaphson’s...
- 10
- 533
- 1
A textbook of Computer Based Numerical and Statiscal Techniques part 10 ppt
Ngày tải lên :
04/07/2014, 15:20
... 77 ALGEBRAIC AND TRANSCENDENTAL EQUATION Since, imaginary roots occur in conjugate pairs roots are 1.915 ± 1.908i upto places of decimal Assuming other pair of roots to be α ± ... (c) tan x = x (a) sin x = [Ans 1.896] [Ans 1.756] [Ans 4.4934] 79 ALGEBRAIC AND TRANSCENDENTAL EQUATION Using N–R method, obtain formula for N and find 20 correct to two decimal places [Ans 4.47] ... Thus, the root can be taken as 2.0945 correct up to four decimals 85 ALGEBRAIC AND TRANSCENDENTAL EQUATION Solution by Secant method: Taking initial approximations as x0 = 2, x1 = and f(x0) = –1,...
- 10
- 713
- 0
A textbook of Computer Based Numerical and Statiscal Techniques part 11 pdf
Ngày tải lên :
04/07/2014, 15:20
... NUMERICAL AND STATISTICAL TECHNIQUES complex roots, and then complex arithmetic can be avoided because such quadratic factors have real coefficients This method extracts a quadratic factor from ... polynomial is called the defaulted polynomial Another quadratic factor is of obtained using this default polynomial If the initial approximation of p and q are not known then the last three terms of given ... polynomial an – 2x2 + an–1 x + an = can be used to get approximations as p0 = an an−1 , q0 = an − an− Example Find the quadratic factor of the equation x4 – 6x3 + 18x2 – 24x + 16 = using Bairstow’s...
- 10
- 387
- 1
A textbook of Computer Based Numerical and Statiscal Techniques part 12 pdf
Ngày tải lên :
04/07/2014, 15:20
... q1(1) = − a2 a1 a , α1 = – , α2 = + a0 a0 a0 a0 α1 a =– a0 α0 .(3) 101 ALGEBRAIC AND TRANSCENDENTAL EQUATION q1(2) = a a − a2 α2 = α1 aa a2 a3 ∆1(1) = q1(2) – q(1) = a , ∆2(0) = a And so, ∆m(m) ... Eigen values of a matrix An important feature of the method is that it gives approximate values of all the roots simultaneously and this fact enables one to use this method to obtain the first approximations ... cubic equations The disadvantage of this method is that additional computation is also necessary This method can be applied to find the complex roots and multiple roots of polynomials and also for...
- 10
- 470
- 0