... Sections 9.2, 9.3, and 9.4.
7. AUTOMATA
ã Patterns and Pattern Matching
ã Finite State Machines and Automata
ã Deterministic and Nondeterministic Automata
Reading: Sections 10.2 and 10.3.
8. REGULAR ... & K6, ComputerScience Department, Văn Lang University
Second semester Feb, 2002
Instructor: Trần Đức Quang
0.1 OBJECTIVES AND PREREQUISITES
This course is intended to provide a broad introduction ... opportunities to get an English-working skill and a better
knowledge in computer science.
0.2 TEXTBOOK AND HANDOUTS
There is one required text for this course:
Foundations of ComputerScience (C...
... of C.
1002
5
0
num
8
3
10
0
1
2
3
INTRODUCTIONTOCOMPUTER SCIENCE
HANDOUT #1. REVIEWS
K5 & K6, ComputerScience Department, Văn Lang University
Second semester Feb, 2002
Instructor: Trần ... defined action.
to operate: thao tác, hoạt động.
operator: người điều hành, to n tử.
operand: to n hạng.
Execution: Thực thi, chạy. The running of a program on a computer.
to execute: to run.
Data ... themes:
1. IntroductiontoComputer Science
2. Three Columns: Data Models, Data Structures, and Algorithms
3. C Essentials
4. Arrays and Linked Lists
Reading: Sections 1.1, 1.3, 1.4, and6. 4 (textbook),...
... a cell.
4
6
ã
ã
31
9
42
L
M
INTRODUCTIONTOCOMPUTER SCIENCE
HANDOUT #2. SET THEORY
K5 & K6, ComputerScience Department, Văn Lang University
Second semester Feb, 2002
Instructor: Trần Đức ... (general form): We write
{ x | x ∈ X and P(x) }
and read "the set of elements x in X such that x has property P."
12 INTRODUCTIONTOCOMPUTER SCIENCE: HANDOUT #2. SET THEORY
Equality of ... S
Region 1
Region 2 Region 3 Region 4
S T
16 INTRODUCTIONTOCOMPUTER SCIENCE: HANDOUT #2. SET THEORY
Code: Baûn mã chương trình. Any written program (in any programming languages,
including machine...
... Grade
CS101
CS101
EE 200
EE 200
CS101
PH 100
12345
67 890
12345
22222
33333
67 890
A
B
C
B+
A−
C+
Course StudentId Grade
CS101
CS101
CS101
12345
67 890
33333
A
B
A−
18 INTRODUCTIONTOCOMPUTER SCIENCE: HANDOUT ... cross product (tích cheùo).
Course Room
CS101
EE 200
PH 100
Turing Aud.
25 Ohm Hall
Newton Lab.
Course Room Day Hour
CS101
CS101
CS101
EE 200
EE 200
EE 200
Turing Aud.
Turing Aud.
Turing Aud.
25 Ohm ... The reason is
that relations are sets, and the 1-tuples "12345" and " ;67 890" are duplicates, thus they
are the same elements and need not to be represented twice.
The Join Operation
Unlike...
... 26 INTRODUCTIONTOCOMPUTER SCIENCE: HANDOUT #4. THE LIST DATA MODEL
4.3 QUEUES
A queue is a restricted form of list in which elements are inserted at one end, the rear,
and removed ... STACKS 25
A smart way to implement a stack by an array is to create a structure consisting of:
1. An array to hold the elements, and
2. A variable top to keep track of the top of stack.
In the ... INTRODUCTIONTOCOMPUTER SCIENCE
HANDOUT #4. THE LIST DATA MODEL
K5 & K6, ComputerScience Department, Vaên Lang University
Second semester Feb, 2002
Instructor: Trần Đức Quang
Major themes:
1....
... INTRODUCTIONTOCOMPUTER SCIENCE
HANDOUT #5. THE TREE DATA MODEL
K5 & K6, ComputerScience Department, Vaên Lang University
Second semester Feb, 2002
Instructor: Trần Đức Quang
Major ... the
root, move to the parent of n, to the parent of the parent of n, and so on, we
eventually reach the root of the tree.
r
n
1
n
2
n
3
n
4
n
5
30 INTRODUCTIONTOCOMPUTER SCIENCE: HANDOUT #5. THE ... tree using pointer header to the root. From this pointer, we
can traverse the tree in several ways, but it is beyond the scope of this course.
r
n
1
n
2
n
3
n
4
n
5
n
6
32 INTRODUCTIONTO COMPUTER...
...
1
ME-430 INTRODUCTIONTOCOMPUTER AIDED DESIGN
TORSIONAL ANALYSIS Using Pro/MECHANICA
Pro/ENGINEER Wildfire 2.0
Dr. Herli Surjanhata
The U-Joint shown in the figure below is made of steel. A torsion ... torsion load of 10 ,000 IN-
LB is uniformly applied over the top portion surface of the U-Joint.
Determine the von Mises stresses, and maximum deflection under the given torsion
load and boundary ... tab, and
change the type to
Displacement, and the
Component to Magnitude.
Check Overlay Undeformed
in the Display Options tab.
Click the OK and Show
button.
24
Notice...
... into the output image.
Example. The 6 value (quite possibly noise) in input image is totally eliminated using 3x3
median filter
Input Image
0 1000
01110
0 161 0
01110
01110
01110
01110
00000
... Discovery and Data Mining
3
6. 3 Bresenham’s Algorithms
6. 4 Using Interest points
6. 5 Problems
6.6 Exercies
Chapter 7. Reasoning, Facts and Inferences
7.1 Introduction
7.2 Fact and Rules ... by ty in the y direction (equivalent to
panning left, right, up or down from an image)
B = 1 .000 00Y + 1.77200C
b
There are several ways to convert to/ from YC
b
C
r
. This is the CCIR (International...
... 5
73
74
78
79
82
84
87
88
90
6. Diagonalisation of Matrices
6. 1
Introduction.
92
6. 2 Similar
matrices.
96
6.3 Diagonalisation
of
a matrix whose eigenvalues are all
different
97
6. 4 Matrices with repeated eigenvalues
100
6. 5 ... eigenvalues
100
6. 5 Diagonalisation
of
real symmetric matrices 100
6.6 Diagonalisation
of
Hermitian matrices
102
6. 7 Bilinear
and
quadratic forms
103
6. 8 Lagrange's reduction
of
a quadratic form
105
6. 9 ... 3
denotes
the
mapping
which sends I
into
ai'
2 into a
2
,
3
into
a3
and
4
into
a
4
ã
If
f = (
~ ~
;
~)
and
g = (
~
; i :)
find
Ig
and
gl
Each
mapping
(J
and
g)
is
a
permutation
of
the
numbers
I,...
... 5
(c)
4
Be
12
Mg
20
Ca
38
Sr
56
Ba
88
Ra
3
Li
1
H
11
Na
19
K
37
Rb
55
Cs
87
Fr
5
B
13
Al
31
Ga
49
ln
81
TI
6
C
14
Si
32
Ge
50
Sn
82
Pb
22
Ti
40
Zr
72
Hf
21
Sc
39
Y
57
La
89
Ac
24
Cr
42
Mo
74
W
23
V
41
Nb
73
Ta
26
Fe
44
Ru
76
Os
25
Mn
43
Tc
75
Re
28
Ni
46
Pd
78
Pt
27
Co
45
Rh
77
Ir
30
Zn
48
Cd
29
Cu
47
Ag
80
Hg
59
Pr
58
Ce
61
Pm
60
Nd
63
Eu
62
Sm
65
Tb
64
Gd
66
Dy
67
Ho
68
Er
69
Tm
70
Yb
91
Pa
90
Th
93
Np
92
U
95
Am
94
Pu
97
Bk
96
Cm
98
Cf
99
Es
100
Fm
101
Md
102
No
Solid
Liquid
Gas
Not ... °F
71
Lu
103
Lr
15
P
33
As
51
Sb
83
Bi
16
S
17
CI
18
Ar
34
Se
35
Br
36
Kr
52
Te
84
Po
53
I
54
Xe
85
At
86
Rn
7
N
8
O
9
F
10
Ne
2
He
79
Au
(d)
4
Be
12
Mg
20
Ca
38
Sr
56
Ba
88
Ra
3
Li
1
H
11
Na
19
K
37
Rb
55
Cs
87
Fr
5
B
13
Al
31
Ga
49
ln
81
TI
6
C
14
Si
32
Ge
50
Sn
82
Pb
22
Ti
40
Zr
72
Hf
21
Sc
39
Y
57
La
89
Ac
24
Cr
42
Mo
74
W
23
V
41
Nb
73
Ta
26
Fe
44
Ru
76
Os
25
Mn
43
Tc
75
Re
28
Ni
46
Pd
78
Pt
27
Co
45
Rh
77
Ir
30
Zn
48
Cd
29
Cu
47
Ag
80
Hg
59
Pr
58
Ce
61
Pm
60
Nd
63
Eu
62
Sm
65
Tb
64
Gd
66
Dy
67
Ho
68
Er
69
Tm
70
Yb
91
Pa
90
Th
93
Np
92
U
95
Am
94
Pu
97
Bk
96
Cm
98
Cf
99
Es
100
Fm
101
Md
102
No
Solid
Liquid
Gas
Not ... 1.35 1.22 1.25 1. 16 1.19 1.97
Ionic 1.33 1. 06 0.8
2+
0 .64 0.4
5+
0.3 0.52 0 .67
3+
0 .65 0.78 0. 96 0.83 0 .62 0.44 0 .69 1.91 1. 96 —
Metallic 2.03 1.74 1.44 1.32 1.22 1.18 1.17 1.17 1. 16 1.15 1.17 1.25...
... properties and
stress and deflection analysis to properly shape and size parts for minimum mass while
maximizing the strength and stiffness needed to withstand the dynamic forces.
10.4
MASS MOMENT AND ... centers of the linkage and were described
in Section 6. 5 (p. 263 ). Figure 6- 15b (p. 266 ) shows a pair of centrodes that could be
used for noncircular gears. Teeth would be added to their circumferences ... corresponds to a center of rotation near the end of the handle, and
the handle is usually contoured to encourage gripping it there.
The explanation of this phenomenon is quite simple. To make the...