Đang tải... (xem toàn văn)
Tổng hợp các dạng về bài toán dao động cơ học để ôn thi đại học có đáp án và lời giải chi tiết.
C©u 1 : A. !" " C. # $ %&' C©u 2 : ())*+,-+.-/+012,-34565&78*9) ):-;< A. =4+2>?@'A: #B2>?@'A: C. =4+2>1@'A: $ #B2>1@'A: C©u 3 : (C/&8+D?22>E')F58G> 8GAHIJ 0 DKL ?MN π−π O+CJ ? DK N π +P!- ? π D02#6QBC* B:JD ?? +RS A. ? T C. U $ K C©u 4 : V8G>>R&&8&?+CK+ A&T+&'RS A. LW0M?O π ? π C. L?W0O π $ L?X0O π M? C©u 5 : (&7G8YA+Z->HARS#+Z- -# +Z-J5C[DM1#\H&7 A. #M 1 ? 1 # C. ? 1 # $ 1 # C©u 6 : 3ZR98[,-C57& sai < A. PE+Z>&E4&+ B&8 #&[H]ZAH 7 C. $R4+&E+Z>&E 4+A8FZ&C/ $ PE4Y&E+Z&[H]ZAH 7 C©u 7 : (&7G5-,-A^& l D?2+A^_`&7&'aC_A\,RS 2>0AC5\R4A)A-5C/0T+M^8GCC[,-C5\C_A\, RSb&75bcc:C_A\,RS>58G8[dC_A\, RS\R4>F&&;&7]C_A\,RS& !P!-De>U+M ? 38GAH&7:I A. D? ? Lf π X π M?O+ D?LfX π M?O+ C. D? ? LfX π M?O+ $ D? ? Lfg π M?O+ C©u 8 : b&7G,-A^0+5hA+J^:-A+Y α D12 2 C[ 8G`&8]4&+D022 1 P!-D02+M ? a]+ZQRZJ^C+Y 8F`C/iC_A\,RSAJ^-9A+Yj>,-C[ 8Gj RS A. 1N 2 12 2 C. K2 2 $ TN 2 C©u 9 : k/5^8GAHJDL π g? π M1OL+O#FC/8]l8FmD N+9dF9+RD2& A. 0MK 0MT C. 0M? $ 0M0? C©u 10 : (C/5]C_A\,RSn#A4F0M0NLOC/^ :C4:-I#-P#Ac$-W2efUef2fNTWIMM+C+ Trường PT Triệu Sơn #-P#Ac$- ÔN TẬP HẾT CHƯƠNG: DAO ĐỘNG CƠ Lb8GAHP#%VO #FIooooooo 0 p + ? 0 5,+dC_A\& 1 ? A x = *C_A\,RS`& ? 1x cm= HC/C/ 02 π +M C/& A. T+ 1+ C. N+ $ K+ C©u 11 : V&7Y:C[A+Yjq&&8&0>TC 0>U`&7AaC_A\,RS+:8A))FRrH&7s )FAi&:C_A\-F7! A. K>1LO ?N>?LO C. 0?>KLO $ N2>TLO C©u 12 : $-AH&7+8FlI A. P++!&E4+A8FC[C/ -9 `\\&:R_7 C. #Z:&ER*5^F C $ #Z:&ECC/5 C[-9A+dq C©u 13 : b?5h8GIJ 0 DL 0 t ω ϕ + OCJ ? DL ? t ω ϕ + O '+; A. pD? 0 ? ? c ϕ ϕ + " pD?" C. pD? ? 0 ? c ϕ ϕ − $ pD? 0 ? L Oc ϕ ϕ − " C©u 14 : `&8AZ!&[G&8+YABU0&%8F\AZ!&[G8F\+Y AB1>f&%^++&7GdAZ!&+YABHH-8*< A. bHB&1& bH4+?>T1& C. bHB&?>T1& $ bH4+1& C©u 15 : b+C/+)FT58G>8GAH&&8&J 0 D02L?2 π X π M1OL+O>J ? DK 1 L?2 π OL+O>J 1 DT 1 L?2 π g π M?OL+O>J T D02L?2 π X? π M1OL+O38GAH:& A. JDKL?2 π X π MTOL+O JD K L?2 π X π MTOL+O C. JDK K L?2 π X π MTOL+O $ JDK K L?2 π g π MTOL+O C©u 16 : b'LCsO* 0 D02tM+" ? D0NtM+"+D022#l? &hJ&N+`C/[C_A\9&hJ? >lA)4Ak/ 5tB&8 C/& A. N+u 0>N+u C. ?>N+u $ T+u C©u 17 : (&7G+C/YAc&8?t>&7A+A8F+Z`C/ iC_A\RH&EB,-RS0tPEB,-C/]C_A\,RS& A. 1t Tt C. Kt $ ?t C©u 18 : (&7&hJC/Y&8+D?22A^j 5b5E &hJ&l 2 D12+P!-D02+M ? `&hJ5 lD?U+HC/RSC&;&E )&[v D?ttB&8C/& A. 2>2Uu 2>2?u C. 0>Nu $ 2>0u C©u 19 : bc,A4&Fkhông đúng A. V'8R8wR B *+ZA_E:&E 8wR RSA'8 c&E8i 8i&[+Z a C. V'88i9&Y: AFCx/ $ V'88iJ4-A:&E 8wR &[G&E+Z,-7 C©u 20 : (C/5h8GAHJDU02y#F9+C/]C_A\JDT& ?22e9d :C4:-I#-P#Ac$-W2efUef2fNTWIMM+C+ ? F9+R7& A. K2?N 12 LO K?2N 12 LO C. K>2?N 12 LO $ K?N2 12 LO C©u 21 : (C/A^C8[&hJj >A&JA^C9+_#dC_A\,RS C/J+:1+A)A-5C/C 2 j 8[&k/&8U+A8[J C/& A. T+ N+ C. 00+ $ UL+O C©u 22 : (&7&hJYA+YjS+)+&hJr+_>7C[C/a + 0 QC/+ 0 :C_A\+&hJR_K+>YC/a+ ? &8RS&8D?+ 0 A+YjS+CZC[C/+ 0 r9C/R7-9^8GA &hJa]+c+ZzF9+&hJ5E:&H4ZQC/+ 0 C+ ? &R A. 0>eff+ ?+ C. cm1? $ ?>U?+ C©u 23 : #A^+&7G0+A+J^-9J α D12 2 C[+Y jS+V'+ZQRZJ^C+Y8F& µ D2>?"AcA8F:C&7 &D02+M ? bHa&7RS A. 1>0 ?>N C. ?>0 $ 0>? C©u 24 : b&7&hJ7A+Yj*`D022tM+>+D022>'+Z2>?>C/ &'02+A)R->D02+M ? NH& A. T+ N+ C. 1+ $ K+ C©u 25 : (&7G5,-A^l>]4Y&8+C+'\]*]{||+` 'A8F&75C[H# 2 t*&75A' A8FQR4'jCG8F'A8F { uur j 8[JHH &7&ILbL0gO D0g*||0OI A. #D# 2 L0X ]{ + O #D# 2 L0X 0 ]{ ? + O C. #D# 2 L0g 0 ]{ ? + O $ #D# 2 L0g ]{ + O C©u 26 : (&7G5,-A^RS l D0>K+5C[H#t*7R[,-A^ +:2>f+HHR,-F&# 0 D1t*7*,-A^+:Q2>N+HH R,-F# ? RSR< A. 1 ? C. 0 $ 0>N C©u 27 : (C/+)F58G>R&&8&K+C U+&02+&' ϕ∆ RS A. L?W0O π LW0O π C. ? π $ L?X0O π M? C©u 28 : (&7G5 l .`&7&'aC_A\,RS+ 2 α D12 2 A)4r `]C_A\,RS,-A^R_C8[C+*S+A8Fj Z9+ A^&7+: M ?l #\R 2 β +&7:8C8[< A. 1T 2 TN 2 C. T1 2 $ 12 2 C©u 29 : 3ZR9,-C5Gc< A. $7R4+^F #8wR RS :&E8wR C. `:&E8wR RS A'HJ4-A 8i $ $7GB^F C©u 30 : (7C/&8+D?C['&hJ 0 > ? +7HH'&# D? π :C4:-I#-P#Ac$-W2efUef2fNTWIMM+C+ 1 M1LOt*?&hJ-+7*HH&# D ? π LO"R* 0 } ? % 0 > ? & &8& A. 0 D0?tM+" ? DKtM+ 0 DetM+" ? D?tM+ C. 0 D0?tM+" ? DKtM+ $ 0 D0?tM+" ? DUtM+ C©u 31 : b&7&hJ DT2tM+5^8Gj C[&02AM bc:niC_A\,RS>58G8[&CCD2H&hJR*:PE )ZCC/C/&C[C/CDXU2+M& A. 0>KtYK>Tt T>Kt C. ?>Tt $ ?t C©u 32 : bHa&7G A. %5'\\R&7 #6Ac&8C&8&7 C. &7 $ `&8&7 C©u 33 : 3ZR9,-& A. bq+&7G6&'_ C[BR/AcA8FG &7 bq+&7G CR C. bqa&7G6&'C[B R/5 $ bq&7GC &8 C©u 34 : b&7&hJ 5C[Rpb&7G)+,-A^5 l >C/ Y&8+5C[R 2 α iGAcA8FtB&8 &7RS#6M+RSI A. ? 2 ? ? p αl ? 2 ? p αl C. ? ? 2 p αl $ 2 ? p αl C©u 35 : t*5h8G>8H&; A. &&! AZ!RRS>!R Z C. *R $ RS*R C©u 36 : (C/5C/&J 0 D1+HC/&C 0 DT2+M>C/]C_A\, RSC/C/C ? DN2+PC/C/C 1 D12+M& A. ± T+ T+ C. 0K+ $ ?+ C©u 37 : (&7Ga5hC[R~ 2 L\RSAOb5,-A^&•> AcA8F&=cC&C/&7:&~bcR9 ;I A. ? ? ? 2 g v α α = + l ? ? ? 2 g v α α = + l C. ? ? ? 2 0 v g α α = + l $ ? ? ? 2 v g α α = + l C©u 38 : (C/&8+D?22E')F58GAHIJ 0 D T02L+OCJ ? DK02L+OPEZE:,-AC/& A. ?2t 2>2?t C. 2>?t $ ?t C©u 39 : bqa&7G A. &8&7 C_A\&7 C. Z\\&7 $ R4&7 C©u 40 : b&7G5iGDe>U+M ? RR&2>2UA>5022+> &8022>#A]AH&_Z&E4022Hdjb&7 7/+#\!\ARH A. T 1>0T02 − € K 1>0T02 − € C. f 1>0T02 − € $ N 1>0T02 − € C©u 41 : bc,A4&Fđúng(8F8C•m&\\RSZ:,J! H8FS+-9C•E-9b-9C•AA8F&I A. E 8i :C4:-I#-P#Ac$-W2efUef2fNTWIMM+C+ T C. 8wR $ 7 C©u 42 : ())]4&7859Ri&7G:-;F5A^ ( ) ml ?1T>2 = CAcA8F ( ) ? MU1?>e smg = t*5A^ ( ) ml ?1?>2‚ = CAcA8F ( ) ? MU10>e‚ smg = HA+-+:--/+R A. t1K>NTf? t Tf?1KN. C. b/+1KN>Tf? $ b/+1K>NTf? C©u 43 : bR&75,-A^>&8C/Yb&7 !C&7 + '\] 0 C] ? >&7 R+'\bH5h;A' A8F58Gj &&8&# 0 "# ? C# 1 C[# 0 D# 1 M1"# ? D?# 1 M1*] 0 X] ? Df>T02 gU b #6'\ 0 ? ] ] RS A. 1>? K>T C. ?>1 $ T>K C©u 44 : b&7GA^RS+ Ac&8A!aC[]4Y>l> ( ) ml eU>2 = $&7A959))]4&7=AGEiY& ( ) ? MU0e>e smg = >C' & C 2 ?2 %)):-;Fb'i,-A^& ( ) -1 é§ N 02? − = λ t*A^&7 !-iVt>GAGE& ( ) ? Mfe1>e smg = C'12 2 b%9)):-;H4 B-4+5R< A. =4+?>fe+ #B2>?fe+ C. =4+2>?fe+ $ #B?>fe+ C©u 45 : (&7G8A^CA+J^-9^8Gbq &7GAA8FJ^-95C[&# 0 CJ^-9 /+5C[&# ? >J^-9j5&# 1 9 ,-&;I A. # ? D# 0 D# 1 # 0 D# ? |# 1 C. # ? |# 0 |# 1 $ # ? D# 1 }# 0 C©u 46 : b5&&88GAHIJ 0 Dp 0 O?ML π+ω +CJ ? Dp ? OL ω +bc ZR9,-&đúng : A. $ !C[ $ !CC[ C. $ !8C[ $ $ !AƒC[ C©u 47 : b6A,`8G>88H A. Ra! sC[+A C. R&[! $ s8C[+A C©u 48 : (C/^8GAHJD1LN π g? π M1OX0L+O#A,-C/]C_A\t JD0++!-&< A. N& 1& C. T& $ ?& C©u 49 : 3ZR9,-không đúng<%C[G7H A. GB4+^F +ZC&E4&[H7 C. R4+^F $ 4+^F C©u 50 : (C/7>*A4F ∆ GB'4+?&HC/E: 4+ A. ?? & ?& C. T& $ ? & C©u 51 : 3ZR9,-&;<#A5JDpLωXϕO>+HH A. &C/AiC5ZA_R C/&:AiC5ZA_R C. C/&:AiC5C_A\R $ C/C/&:AiC5ZA_R C©u 52 : V5h8G>q8GAH&&8&I cmtx O 1 02LT 0 π π += " :C4:-I#-P#Ac$-W2efUef2fNTWIMM+C+ N ? x 38GAHA& cmtx O ? 02L1? π π += #H+ h&: A. cmtx O02L1? ? π = cmtx O T 02L? ? π π += C. cmtx O02L? ? ππ += $ cmtx O T 02LT ? π π += C©u 53 : b&7G,-A^0+5hA+J^:-A+Y α D12 2 C[ 8G`&8]4&+D022 1 P!-D02+M ? a]+ZQRZJ^C+Y 8FPEB,-ZA_RS A. 0>2t 0>Nt C. ?>2t $ 1t C©u 54 : (!9+&8+5J]C_,RSC[Rp=cC +J > +J > € +J &&8&&[C/E:>E:CBE:!9+#:F9+ !9+&-JCC/&Cb ,-&9\H5 !9+< A. #D ? ? ?y p XJ C #D +J + ?yp ?€ C. #D +J p ?y $ #D +J p ?y C C©u 55 : (&7G5 l D0+>5iGAcA8FD ? π D02+M ? P; D2>&7]C_A\,RS^58GC[C/2>N+Mm?>NC/&7 &[& A. 2>0?N+M 2 C. 2>?N+M $ 2>N+M C©u 56 : (C/E')F15 >ONLK>O?NLU>OTNL?U 1?0 cmtxcmtxcmtx −=−=+= ππ 38GAH A. >OTMNL? cmtx π −= >ONL? cmtx π −= C. >ONL? cmtx = $ >OKMNL? cmtx π −= C©u 57 : 8wR A. R:&EZ&C/ '&E4L+Z[OZ&C/ C. :&EZ&C/ $ R:&EZ& C/ C©u 58 : b&77 +.HR4+1@3AB+B&8R_+7+Z+. H& A. 1@ e@ C. 0?@ $ K@ C©u 59 : PhJ DU2tM+>+7CZ_>h&:7C[+]4a &8+DU22t8F\\]45RSZJ8[C_A\,RS ^8Gj *C_A\ZC_A\,RS02+A)4r#F7!9]4d C_A\!!*C_A\+:&hJR*:&L&!-D02+M ? A. 2>0yLO 2>?yLO C. 2>?L $ 2>0LO C©u 60 : (&7G0+>+]4Y:H&8+DT22+'\]DgT02 gK bP!- D02+M ? %Y&7CC'A8F5L8GA8GAc&EOH H&7&?>2TZ_8[C&['A8F< A. 8[&>{DN>?02 N kM+ 8[J>{D2>N?02 N kM+ C. 8[J>{DN>?02 N kM+ $ 8[&>{D2>N?02 N kM+ C©u 61 : bc,sai`C58wR I A. $8wR &5 $8wR RS&E 8wR C. $8wR &8[Z $ 8wR -^F :C4:-I#-P#Ac$-W2efUef2fNTWIMM+C+ K :&ER* C©u 62 : (C/' QC/C&& 0 0K J KT2 C ?? =+ LJI+"CI+MO*AS&;D2C/ ]C_A\JDpM?^58[C5C_A\,RS38GAHC/& A. O+OL1M?LTJ π+π= O+OL1M?LUJ π+π= C. O+OL1MTLTJ π+π= $ O+OL1M?LTJ π−π= C©u 63 : (C/&8+ 2 D022R-^8GC[C/C 2 D02+M*C:+C]4 +&7G&8+De22mC:+>C/+ 2 \C]4tB&8 &7G& A. 0>Nu Nu C. 2>Nu $ 0u C©u 64 : (&7&hJS+5J]C_A\,RSC[q#D 02 π %YA cnJS+>n:C_A\,RSbAS&;D2>C/iC_A\&JDg0+C8 A-5C/?2 1 +M^58G`8GAHC/:I A. JD?L?2g π MKO+ JD?L?2X π MKO+ C. JD?L?2g π MKO+ $ JD?L?2g π M1O+ C©u 65 : b+&hJ5npDl 2 DN2+> 2 D?2tM+#A^&hJnpj >n_( ]4Y+D0C9+b&hJb]4Y^8Gj *H &7&2>K?U%9+bZ9+A^n+4RS A. 02+ 0N+ C. f>N+ $ ?2+ C©u 66 : 3ZR9,-C5BC*BA5&;< A. %BR*qC[ C/ #BC*BC F C. %BC*BR* q $ #*BR*C[!?& & C©u 67 : (C/EHR7_Z+:&E&[k/s A. E'8wR iA:Z8i C. -9E'+5hC[ H+[ $ R7C[R4+ C©u 68 : bcZR9;I A. t*I π=ϕ∆ ? HIpDp 0 Xp ? %&'ZC Ah]-*_[R C. t*&'R!HI ?0 pp − ≤ p ≤ p 0 Xp ? $ t*8I π+=ϕ∆ O0?L HIpDp 0 Wp ? C©u 69 : `8+&7G&^8Gj L5&7OH 5hs A. CHH5h CAcA8F 4+CHAcA8F4+^ C. BCHH5h4+ $ BCH5h6&'_C[ AcA8F C©u 70 : V58G>RpRS>H#RSC'R ϕ∆ D ? π M1$sRRS A. 2 p ? C. p $ ?p C©u 71 : b+&7&hJ5^8Gj >R*ASA]ZAH v +J Mv + DfM1C/RS02+P!-D02+M ? D ? π +M ? #C/ RS A. 0V„ 2>NV„ C. 2>K?UV„ $ ?V„ C©u 72 : 38GAHG5+!9+>&8+>&JDpL 1 ? π +ω O%B R*^F^8GAHI :C4:-I#-P#Ac$-W2efUef2fNTWIMM+C+ f A. € D π +ω− ω 1 T ?0 T +p ?? € D π +ω+ ω 1 T ?0 T +p ?? C. € D π −ω+ ω 1 T ?0 T +p ?? $ € D π +ω+ ω 1 ?0 T +p ?? C©u 73 : (&7G&>A4F ∆ E'80?t8F4+R[ 0K+>…A4F ∆ 8A8[E'8?2b5 &7R& A. &D?N+ &D?N+ C. &De+ $ &De+ C©u 74 : (&7GC/Y+D022t*Y8[&7++,+HHR - 0 0222 C[+,+#\&E;+,+ZC&7P!- ? 02 Mg m s= A. T ?02f N − = 1 ?02f N − = C. 2>2?f N= $ 2>?f N= C©u 75 : V&7&hJ&8C/Y02LO> &hJ022π ? tM+5hc ^8Fj5&5LC_A\,RSC/5icO&7 !&[!&7 *ASC/Y;-985 `4FQR&C/YY&*& A. 2>2?LO 2>20LO C. 2>21LO $ 2>2TLO C©u 76 : (&7GpaC[# p A8[+Y+&7))•,-C[H# D?LOb &7G&7p+;L# p }# OQ&&7-95 CAC[:C_A\,RS;Lc&Q&AO†Z!-& A**ZK2LObq&7Gp& A. ?>0KeLO ?>2KeLO C. ?>2KKLO $ ?>2feLO C©u 77 : (C/5C[ ω DNAMP;D2>C/]C_A\&JDg?+CC/ 02L+MO8[C5\C_A\R!38GAHC/& A. JD? ? LNX T 1 π OL+O JD?LNg T π OL+O C. JD? ? LNX T π OL+O $ JD ? LNX T N π OL+O C©u 78 : (&7G)++,-&8Z9>,-A^hRRS+&: &8+D2>20+'\]D?02 gf b%Y&7A+'A8F5 { 8G j 8[J8[bH&7{D2&# 2 D?#H+H&7{D 02 T kM+bD02+M ? A. ?>2? 0>eU C. 2>ee $ 0>20 C©u 79 : (C/7GBR{ 2 D2>Nub +HHR4+?@ 3B&8+!A+H& A. 0e>Uu TU2>?u C. TU2>?+u $ 0e>U+u C©u 80 : b&7&hJA^j D02tM+>+D022=cn&k#b>8C/&C_A\Zk#bU+A) R-PE4Z&&7&2>20t>D02+M ? P&[!]C_A\ ,RS& A. N+ N>f+ C. U>N+ $ f>U+ C©u 81 : (&7G)++]4+D?28A^C+,-&D?+P!- ? 02 Mg m s= a] +Z`&7ak#b+ 2 12 α = A)RC/`]k#b+& ,-R_ Va]4:+!Zk#bRJL\^8GO<*k#bZ+Y! 0+I A. mD2>TK+ mD0>21+ :C4:-I#-P#Ac$-W2efUef2fNTWIMM+C+ U C. mD?>1+ $ mDT>K+ C©u 82 : b+&7&hJ &>&8C/+D0#A^&7AAi-\A ARZJ^b5A-&PD0?>N+#:-C[C/NT+MH&7+:! % &hJ& A. f1>KtM+ 022tM+ C. f1KtM+ $ NK>UtM+ C©u 83 : (C/&8+D022E')F58G>‡D 02V„>Rp 0 DU+C 0 ϕ D π M1"p ? DU+C ? ϕ Dg π M1P!- ? π D029 *BC/ ^F& A. € D?>NK ? L?2 π OLuO € D0>?U ? L?2 π OLuO C. € D0?U2 ? L?2 π OLuO $ € D0>?U ? L?2 π OLuO C©u 84 : (C/5hC[8GAHJDˆK ?2 1 π + ÷ +#ARHC/A 4F 01 K2 π = >9dR7&I A. fe>11+M f0>1f+M b ff>1f+M $ fN>1f+M C©u 85 : (C/5h4+!2>?N9d9+C/RS[9+*^…8 C/-4ZQ9+&1K+> ‰ Š G ‹ D2& Š C, ‰ ]C ‰ AŒ Š R,+k, ‰ Š A RŒ ‹ 8 ‹ G ‹ • +R, ‹ Š G ‹ • +C, ‰ Š &- ‰ JDe+C ‹ - • ‰ ^ ‹ ,+&I A. 01N+M 01f+M b 01e+M $ 011+M C©u 86 : #A+8F&Z:>+8F&ZA:8F&I+&J^4C[C/ C0>C+&J^4C[C/C?mZC0>C? C[A8FA>R7J! 'EJ+:!A\J^< A. C0DC? C0}C? b C0|C? $ C0D?C? C©u 87 : b&7GR8\'RH#2#\']4A)YA' A8Fj >&;-H#0t*45'A8FH#?(&' #2>#0>#?I A. 2 0 ? ?T T T= + 2 0 ? ? M 0M 0MT T T= + b ? ? ? 2 0 ? ?T T T= + $ ? ? ? 2 0 ? ? 0 0 T T T = + C©u 88 : b&7&hJj >&hJD022tM+>C/+D0t,C/&&hJ5E A)4r9&7a]&E4`+[C_A\!!H8E7++ C/+2DN22+ZrP!-D02+M?'RSR< A. 02+ 0N+ b N+ $ ?2+ C©u 89 : (!9+5hAAnJC[8GAHJDTL02yXyM1O+#ARH !9+dF9+D2*F9+]C_A\JDg?+& ?20?&I A. U2+M T2+M b 2+M $ 022+ C©u 90 : b&7&8+5hC[8GAHcJDpLŽX•Ob! FE :&7&I A. 1 ? m A ω . B. 1 ? 1 T m A ω . b 1 ? 0 ? m A ω . D. 1 ? 2>?Nm A ω . C©u 91 : V&hJ&8Z9>* ` 0 D?` ? >h&:&hJ?C[C/ +C'YA+YRS+a]+c&E4`C/9'&hJl0?+>A)4 9C/5hc^A&hJt-BRS*B&>8FQY 9+Q&hJC/RSI A. K 1cm T Ncm b U ?cm $ K ?cm C©u 92 : V&7&hJ5)+C/&8T7C&hJ 022tM+V &78YZR?AL…&AZ&hJO8&ACS+ #dk#bC/^8GA&hJC5+\+:T+CRr&; bcD2&F9+RC/L0O#F9+4RC/L?O9L?OC[L0OR E:9&I A. 1yM02 ?yMN b D1yMN $ yM02 C©u 93 : bD02+M ? zC_A\,RS+&7&hJA^^8Gj >&hJl02+` &75h>FC/Yd&;&hJ5E:*&;C/]C_A\, RS& & :C4:-I#-P#Ac$-W2efUef2fNTWIMM+C+ e A. 2>1yLO 2>0NyLO b 2>?yLO $ 2>0yLO C©u 94 : (&7&hJ5h^8Gj t/J,-&< A. `&E&hJZCZw&[E:H&EZ&C/…&[ E: B. PEZ&hJCZw&RS&EZCC/ C. V&EZCC/R_A'C/]C_A\,RS D. PEZ&hJCC/R_A'C/]C_A\&hJR*: C©u 95 : (!9+-9Ah5A+Yjj RZ\]•:U+>RYdk# !!8FAh85+))C[C/& 0K L M Ocm s π VH* !9+&AJS+>],+8FAhS+A+Yj]•:>5dAZ] 4&I A. U L? O ? x c t cm π π = − 0K L? O ? x c t cm π π = − C. 0K L? O ? x c t cm π π = + $ U L? O ? x c t cm π π = + C©u 96 : (&7G5&A^CA+J^-9J+~C[ 8GS+V'+ZQJ^C+Yj&>AcA8F&b&7G 5hC[H& A. ? l T g π α = ? L 0O l T g k π α = + C. ? ? 0 lc T g k α π = + $ ? ? 0 l T g k π α = + C©u 97 : (!9+5hC[8GAH ? L O ? x Ac t cm T π π = − #\dF9+D2*F 9+ T T ‘QR]l8F&*+!9+8A+4F&I A. L 1 0OI ? I L 1 0O+ − L 1 0OI ? I L? 1O+ − C. 1 I0I L? 1O− $ L 1O I0I L 1 0O− C©u 98 : b&7&hJA^j )+&hJrA_>8[A^C/Y+0>C/S+, RS&hJl?>N+k/+?D?+08C[+0RS+,-+5+>r`',RS> ,-9+05hP!-D02+M?#A0H+0F&hJR_&< A. 2>1UT 2>?00 b 2>02N $ 2>0NT C©u 99 : (!9+5h^8GAHI ? J K L O 1 1 c t cm π π = − #\dF9+D2> 4F9!9+]k#BRS*B& ?201&I A. ?20?>0?NLO 0N2e>0?NLO C. 022K>K?NLO $ ?20?>K?NLO C©u 100 : VC/AAnJ8GAH 1 x 3cos 5 t 3 π = π − ÷ +C 2 x 3 cos 5 t 6 π = π − ÷ +H09 dF9+D2&?C/]& A. N U b f $ K 3R4‡&^’AC,-IIMM+C+ (FR:B+IMM+C+- Mạng học tập, giải trí hàng đầu! Chuyên cung cấp tài liệu, bài giảng, . pt=$p3pt b 001 0 b ? b :C4:-I#-P#Ac$-W2efUef2fNTWIMM+C+ 02 . :C4:-I#-P#Ac$-W2efUef2fNTWIMM+C+ Trường PT Triệu Sơn #-P#Ac$- ÔN TẬP HẾT CHƯƠNG: DAO ĐỘNG CƠ Lb8GAHP#%VO #FIooooooo. 3R4‡&^’AC,-IIMM+C+ (FR:B+IMM+C+- Mạng học tập, giải trí hàng đầu! Chuyên cung cấp tài liệu, bài giảng,... pt=$p3pt b 001 0 b ? b :C4:-I#-P#Ac$-W2efUef2fNTWIMM+C+