HANOI UNIVERSITY OF MINING AND GEOLOGY ADVANCED PROGRAM IN CHEMICAL ENGINEERING ADECH02-5/2017 Petroleum Refining HOMEWORK HELP- SOLUTION PROB 8.5 Name : Dai Duong Van K4 The feed of 100,000 BPD with API = 24 (distillation column) TBP(°R) = {( ln −𝐿𝑉% API = -0.0004 𝑉% + T°C = T°R = ° − ° + SG = 𝐴𝑃𝐼+ + } 𝑉% − (8.0) 𝑉% + (8.1) (8.2) (8.3) (8.4) From the CDU unit, we get CDU-Gasoline cut as well as AGO and VGO cuts FCC- Gasoline cut is also produced from the FCC as well as LCO, which is then fed to a hydrocracking unit to produce Hydrocracking-Gasoline We must calculate the total amount of gasoline (lb/h) that is produced from all units Consider the crude distillation unit : 190-380°F cut IBP = 190 °F = 87.78°C = 649.67°R EBP= 380°F= 193.33°C= 839.67°R Substituting in eq ( 8.0) to get LV% at IBP and EBP : Cut vol % = 44.71-35.95=8.76% Cut mid volume = 40.33 Substituting the cut mid volume in eq ( 8.1) to get API= 30.29 From the Eq (8.4) ,we get SG = 0.875 Cut volume = 0.0876(100,000)= 8760 BPD Cut amount = 8760(SG)(14.60)=8760(0.875)(14.60)=111,909 lb/h Calculate of sulphur content : M= 42.965[exp(2.097× − 𝑏 − 𝑏 M= 111.50 lb/lb mol I=2.266× n= + 𝐼 −𝐼 / − exp = 1.495 × − + = 𝑏 𝑖 + 𝑖 m= M(n – 1.475) = 2.23 since M< 200 sulphur wt% = 177.448 – 170.946 + + × − + − × − = = sulphur amount = 0.0072(111,909) = 805.74 lb/h − + 650- 850°F cut ( AGO) IBP = 650°F = 343.33°C = 1109.67°R EBP= 850°F= 454.44°C= 1309.67°R Substituting in eq ( 8.0) to get LV% at IBP and EBP : Cut vol % = 55.54-51.87=3.67% = − ] 𝑏 𝑏 𝑏 𝑏 = 𝑤% − = Cut mid volume = 53.705 Substituting the cut mid volume in eq ( 8.1) to get API= 25.36 From the Eq (8.4) ,we get SG = 0.902 Cut volume = 0.0367(100,000)= 3670 BPD Cut amount = 3670(SG)(14.60)=3670(0.902)(14.60)=48,330.964 lb/h Calculate of sulphur content : M= 42.965[exp(2.097× − 𝑏 − 𝑏 M= 340.35 lb/lb mol I=2.266× n= + 𝐼 −𝐼 / − exp = 1.516 × − = 𝑏 + + + − = − + − 𝑖 m= M(n – 1.475) = 13.95 × × − = − 𝑖 − + 𝑏 = sulphur amount = 0.02827(48,330.964) = 1366.32 lb/h = 850-1050°F cut ( VGO) IBP = 850°F = 454.44°C = 1309.67°R EBP= 1050°F= 565.56°C= 1509.67°R Substituting in eq ( 8.0) to get LV% at IBP and EBP : Cut vol % = 58.46-55.54=2.92% Cut mid volume = 57.0 Substituting the cut mid volume in eq ( 8.1) to get API= 23.57 𝑏 since M>200 sulphur wt% = -58.02+ 38.463 ] 𝑏 𝑤% 𝑏 − = From the Eq (8.4) ,we get SG = 0.912 Cut volume = 0.0292(100,000)= 2920 BPD Cut amount = 2920(SG)(14.60)=2920(0.912)(14.60)= 38,880.384 lb/h Total feed to FCC = 48,330.964 lb/h + 38,880.384 lb/h = 87,211.348 lb/h SG for AGO = 0.902 and SG for VGO = 0.912 Then SG for mixed feed = + So API = 24.68 + + = Consider the FCC unit : Conversion = 72% Coke wt% = 0.05356×CONV – 0.18598×API + 5.966975 = 5.2333 𝑉 − LCO LV%= 0.0047× × Gases wt% = 0.0552×CONV + 0.597 = 4.5714 𝑉+ = Gasoline LV% = 0.7754 ×CONV – 0.7778 = 55.051 i n 𝑉% = × 𝑉% = 𝑉 + × = 𝑉 + = 𝑉% = Gasoline API = - 0.19028 × LCO API = − × × 𝑉% = 𝑉% = × 𝑉+ 𝑉+ 𝑉+ × × 𝑉 + × 𝑎 = = 𝑉− 𝑉− 𝑖 × = = 𝑉+ 𝑉% + ×CONV + 1.725715 × ( Feed API ) = 17.63 Gasoline amount = 0.55051×(6590)BPD×0.7715×14.60 = 40,863.86 lb/h Feed to hydrocracking ( LCO) = 0.1628×6590 BPD = 1072.852 BPD Considering the gas oil hydrotreater unit : Middle distillate HT SCFB = 𝑓 + % − = = 100% severity of the hydrotreater SCFB = + Since the feed is 1072.852 BPD: Δ 𝑝 = − − = ( 𝑝 = 𝑓) + + = Gasoline amount =1072.852 × 0.919×14.6= 14,394.88 lb/h = The total amount of Gasoline = CDU-Gasoline+FCC-Gasoline+Hydrocracking-Gasoline = 111,909 lb/h +40,863.86 lb/h +14,394.88 lb/h = 167,168 lb/h