C¸c bµi to¸n vÒ pt bpt V« tû C©u 1. Gi¶i c¸c ph¬ng tr×nh sau: a) xxx 2114 −=−−+ ( x = 0) b) 2(x 2 -2x) + 0932 2 =−−− xx (1 5 ± ) c) 211 22 =−++−− xxxx (x = 1) d) )121(11 22 xxx −+=−+ ( x= 1; x=1/2) e) (4x - 1 ) 12814 22 ++=+ xxx (VN) f) 513413 2 −+−=+ xxx g) x 3 + 2 = 3 3 23 − x ( x=1; x = -2 ) h) 1111 22 =++++−+−+ xxxxxx ( PP hµm sè xÐt f(x) = xxxx ++−+ 1 2 ) i) 123 22 =−+−+− xxxx (x= 1+-v5)/2) j) 253294123 2 +−+−=−+− xxxxx (x= 2) k) 112 3 −−=− xx ( x = 1; 2; 10) o) )0(77 28 94 2 >+= + xxx x ( x = (v50-3)/7) p) ) x 3 + 1 = 2 3 12 − x (x = (-1 5 ± )/2) q) x 30)35(35 3 33 3 =−+− xxx (x = (3 5 ± )/2) l) ( 0)(log)11 2 2 =−++− xxxx (QG KD 99) m) 1221221 =−−−−−+− xxxx n) (x+5)(2-x)= 3 xx 3 2 + s) 33 2 +− xx + 63 2 +− xx = 3 t) 2 221)2)(1( xxxx −+=−+ . xxx x ( x = (v5 0-3 )/7) p) ) x 3 + 1 = 2 3 12 − x (x = (- 1 5 ± )/2) q) x 30)3 5(3 5 3 33 3 =−+− xxx (x = (3 5 ± )/2) l) ( 0)(log)11 2 2 =−++− xxxx (QG KD. pt bpt V« tû C©u 1. Gi¶i c¸c ph¬ng tr×nh sau: a) xxx 2114 −=−−+ ( x = 0) b) 2(x 2 -2 x) + 0932 2 =−−− xx (1 5 ± ) c) 211 22 =−++−− xxxx (x = 1) d) )12 1(1 1