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THCS HUNH VĂN LY HƯNG DN CHM V THANG ĐI"M (THAM KH%O) .c0 f "/g$#*h$ , ,EJ- i: ≤ 5 'ijk*-Hl2E#""-+$#:4,? )EJ-"/ , 5 ,- I$-Hl2.43($.4,m2 A43 5 (.42 3A4 ,J,5 55 cm=+ )E5J )E5J )EJ G ,- L#"@Nn&>K(GM 5 4,M 5 M, ⇒ 4 5, 55 + + 4 5 )E5J )EJ )E5J ? 5EJ- i>-0THl2&>KB7TD$#(L45:M5 .UN-Hl245E'45 'iL:45I$-Hl2L45 N%!"b2c0o"'&"@$= 2iI$-+$#4,i5 \0N=@4, )E5J )E5J )EJ )EJ )EJ )E5J Ti&$-S#"-"/ 5 , :MZ45:Y,  ⇒ :45 I$-Hl2L4mB&N%!"R-S#"-"/%&5Vm )E5J J ?- iBp6$-+$# 21$#"$-Hl23A%&6$"= 'i4^i5 34 ? 5 5 R R − 4 G= 5 R ⇒ 3A4^ G 2i.34.A#  ⇒ #"@23A.2c$D". I$-Hl24m) ) E#;23.A4m) ) E#"@23A.-70 Ti;234G) ) E3%&"*c$#"@229#;2A3. F%0k$%&c-H!$#N]$$S""F*#"@23A.= )E5J )EZJ )EJ )EJ )EJ )EJ )EJ )EJ q r^3s.t5),,5),5 ^uv(.wjx.3 C$jy !"#"$%&'&")*+C$#/!"#"$*@-7 A&",(G-"/  ^+#R$'"/012JMG? ' 6:'"F(Z4M5 2 .1$#"$-Q$#12 ( ) 5 , , )E , , x x x x x x x x x + − + × = − > ≠ − A&"5(5-"/ .&>KL4:MG2;-znT  {@2-n$&>K'"F-znT -"|0-"/,V5 ' apT Bg:@2-n$B&BpT} (L45:MmN\$2~$#SP*Q$#R-S 2 6R-S#"-"/329T B&T} 'O$#2@2I$ A&"G(5-"/ .#"@23A.B0C$#D"3=A"F3A4m2V3.4•2=  I$A.B&3%&N]$G2€>Kk**c$ ' I$>K-2@2#;2AE.%&N]$-F$*+ A&"?(G-"/ .#"@23A.B0C$#D"3E-H!$#23=ap-H!$#N]$3V3 =R"%&-"/-K" :1$#29.|03=•0Bp-H!$#Q$#>$#>$#BX"A.2`"3D"‚=  .1$#"$(‚4. ' .1$#‚%&"F*0LF$29-H!$#N]$3V3 = 2 I$‚'"F34m2B&A.4,G2= F Đáp án A&" h$#"" "/ A&", G-"/  JMG? 4,JGMmG,mG 4JG )EJ )EJ ' Z4M5-(:ƒ,  J , 5 , x x− − − = G:,4:4,) )E5J )E5J )E5J )E5J 2  ( ) 5 , , )E , , x x x x x x x x x + − + × = − > ≠ − ( ) ( ) 5 , , , , , x x x x x x x x x + − + × = + − − = − akL-Q$#12-Hl221$#"$ )EJ )EJ A&"5  L:4,VL45B&&>KL4:MG-Hl2 :MG45 :4, akL&>K-Hl2:@2-n$L4:MG )E5J )E5J ' A$##"@NnH„$#1$# : ) G L4:MG G )  : ) m L45:Mm G )  ap-+$#2I$:@2…"-zn-Hl2)EJ-"/2;'$##"@NnB&E:EL , 2 H„$#N6$&$-S#"-"/ 5:Mm4:MG  :4, L:4,B&L45:Mm4†L4? R-S3,V? )E5J )E5J A&"G 6 8 A B C H  A. 5 43A 5 M3. 5 4†A. 5 4GmMm?4,)) 4†A.4,)2 2;3=A.43A=3. 4† = m=• ?E• ,) AB AC AH cm BC = = = )E5J )E5J )E5J )E5J ' M2; ) • ‡ >"$ JG ,) B B= ⇒ ≈ M.ˆ) ) JG ) 4GZ ) )EJ )EJ L 3  : . A A&"? D A B C H E )E5J  :["#"@23.B&3‚  ¶ · ‡ ‡ AC AD D C AHC AED H AC EAD =   = ⇒ ∆ = ∆   =  4†.4‚ )EJ )E5J '  · ) & ) AHC AED AH AE v AED ∆ = ∆ ⇒ = = 4†3‚%&'@$I$293V3 B&‚‰3‚D"‚ ‚0S23(3 akL‚%&"F*0LF$293V3 )E5J )EJ )E5J 2 .=,G. 4Gm 4†. 5 ,G.MGm4) .? . 4) .4?2P2.42 )E5J )E5J )E5J )E5J ĐỀ KI"M TRA HỌC K I Bài 1: G-"/ ^+#R$2@2'"/012(   ( ) ( ) 55 GJ5J −+− '  ,G , ,G , + + − c) )mG??5,G =+−−−+− xxx Bài 2: GEJ-"/ ."-H!$#Q$#T (L45:Y5 T} (L4:M,  {@2-n$8>KE'29T B&T} ' apT B&T} 2 6R-S#"-"/29T B&T} Bài 3: GEJ-"/ .#"@23A.B0C$#D"3E-H!$#23=ap-H!$#N]$c3E'@$I$3=gAB&.Š 2@2"F*0LF$AE.‚BX"-H!$#N]$E‚%&"F*-"/  .1$#"$(AM.‚4A. ' .1$#"$'-"/E3E‚Q$#&$# 2 .1$#"$‚%&"F*0LF$29-H!$#N]$-H!$#I$A.  A‹ f r ,   ( ) ( ) 55 GJ5J −+− GJ5J −+−= ( ) ( ) JG5J −+−= 4, '  ,G , ,G , + + − ( )( ) ( )( ) ,G,G ,G ,G,G ,G −+ − + +− + = 5 ,G 5 ,G − + + = G= c) )mG??5,G =+−−−+− xxx ( ) , ≥ x )m ,G ,?5,G =+−−−+− xxx m,,?,G −=−−−+− xxx m,5 −=−− x G, =−x , =− x :4,) akL*H„$#N6$2;$#"8:4,) , , , 5  T (L45:Y5 45:M? 45E'4? T} (L4:M, 4,E'4, ' apT B&T} 2 H„$#N6$&$-S#"-"/29T B&T} , ,EJ 5:M?4:M, ⇔ 5:Y:4,Y? ⇔ G:4G ⇔ :4, L:45B&&>KL4:M, L4,M, L45 BkL#"-"/2929T B&T} %&,V5 , G  .1$#"$(AM.‚4A. 2;(A4AI$2Œ""F*0LF$2`$0 .‚4.I$2Œ""F*0LF$2`$0 &A.4AM. akLA.4AM.‚ ' .1$#"$'-"/E3E‚Q$#&$# 2;(  BAHBAD ‡‡ = I$2Œ""F*0LF$2`$0  EACCAH ‡‡ = I$2Œ""F*0LF$2`$0 ⇒  BAHBAD ‡‡ + M EACCAH ‡‡ + 4 ‡‡ 5 CAHHAB + 4 CAB ‡ =5 45=) )  4,•) ) akLE3E‚Q$#&$# 2 .1$#"$‚%&"F*0LF$29-H!$#N]$-H!$#I$A. #R"%&N0$#-"/29A. 2;3%&N0$#-"/29‚34‚ 4†3%&-H!$#N0$#'6$296$$#A‚. 4†3iiA &A ⊥ ‚ 4†3 ⊥ ‚ &34A4.4•A. 4†30S2-H!$#N]$-H!$#I$A. akL‚%&"F*0LF$29-H!$#N]$-H!$#I$A. )EJ , , , Phòng GD Huyện Tân Uyên ĐỀ KI"M TRA HỌC K I (THAM KH%O) Trường THCS Vĩnh Tân THỜI GIAN : 90 Phút Toán lớp 9 MÔN : TOÁN LP 9 Câu 1(^+#R$2@2'"/012>0(,EJ-   ?•J5Z?,5G +− ' 5G ? ,J 5G ? ,J + − − Câu 2 : ""*H„$#N6$#B&'Œ*H„$#N6$>0(5-   , Jx + ≤ '  5  m , •x x− + = Câu 3:,EJ- .T , (L4:YGV T 5 (L45:M,  6-/T , >$#>$#BX"T 5 V ' a"F*H„$#N6$-H!$#Q$#T >$#>$#BX"T 5 B&-"|0-"/3GV, =ap-zn &>KBg6-Hl2= Câu 4(,EJ- .#"@23A.B0C$#D"3=A"F2>A4 G ,) =I$>"$.E2>.E#.E2#.= Câu 5 (3,5đ) .-H!$#N]$ gS-"/3$O'\$$#&"-H!$#N]$Š""F*0LF$3AE3.BX" -H!$#N]$AE.%&2@2"F*-"/ =R"‚%&#"-"/29A.B&3EBp-H!$#I$.=  .1$#"$‚A4‚. ' .1$#"$A>$#>$#BX"3 2 "$-ST&"3=A"FA452EA.45 G 2 F Đáp án S"T0$# "/ A&", ^+#R$'"/012(   G G ,5 G 5) G ,? G− + = '  5G ? ,J 5G ? ,J+ − − 4 5 5 5 J G 5 J G + − − 45 5 J G 5 J G 5 G+ − + = )=ZJ- )=ZJ- A&"5 ""*H„$#N6$(  , Jx + ≤  Ž4†:M,Ž5J: ≥ , Ž4†:Ž5?$k$  akL:Ž5? ' 5  m , •x x− + = G , •x⇔ − = G:Y,4•P2G:,4• :4GP2:4 Z G − akL2;$#"8%&:4GV:4 Z G − )=ZJ- ,E5J- A&"G  /T , >$#>$#BX"T 5 " (  ≠ )B&45a6YG ≠ ,  akL456"-H!$#Q$#N\$>$#>$#BX"$0 ' a6T >$#>$#BX"T 5 $\$T 2;TD$#(L45:M' &T -"|03GV, $\$I$-Hl2'4J akLT (L45:YJ= ap-zn )=J- )EJ- )EJ- A&"? .>A4 G ,) = 2;(>"$ 5 A4,2> 5 A4, , ,) 4†>"$A4 , ,)  #A4 >"$ , G B cosB = V2#A4G ) ) C B ∧ ∧ + = a6#"@23A.B0C$#D"3  \$>"$.42>A4 G ,) V2>.4>"$A4 , ,) V#.42#A4GV2#.4#A4 , G ,EJ- A&"J ap6$-+$# D E A B O C  .^(‚A4‚. bI$2Œ""F*0LF$2`$0E2;(3A43.=akL#"@23A.2c$ D"3 &3%&"*c$#"@229#;2A3.=-;32•$#%&-H!$#N0$#N_229 A. 4†‚A4‚.= ' .^(Aii3B62~$#B0C$##;2BX"A. 2 ‚4A 5 YA‚ 5 4?YG4,2 A 5 4‚=3L?4,=34†34?2 )=J- ,- ,- ,- ]$#c$L\$ s.• YjyY‘s.5),,5),5 v3()*+(không kể thời gian phát đề) NH!$#.w@"] A&",(,- aX"#"@Nn$&29:6'"/012>02;$#<(   V  A&"5(5- I$(    A&"G(,- ""*H„$#N6$( = A&"?(5EJ- N$#2~$#P*Q$#R-S:L2&>K 2;Tzn%& B&&>KL4:Y?2;-zn%&  ap-zn B& N\$2~$#S8N’2R-S ' 6R-S#"-"/329 B& 'O$#*[*@$ 2 {@2-n$B&$29-H!$#Q$# (L4:M$E'"F >$# >$#BX" B&2`N’20$#D"-"/2;0$#-S'O$#Y5 A&"J(GEJ- .$“-H!$#N]$cE-H!$#I$3A=Š2@2"F*0LF$3:EAL2~$#*IBX" $“-H!$#N]$-K"BX"3A=ap'@$I$‚'Œ”="F*0LF$29$“-H!$#N]$D"‚2`3:EAL b1_•.E  .1$#"$NO$#.43.MA ' I$>K-#;2. 2 R"%&#"-"/29.B&3‚E#R"%&#"-"/29B&A‚=1#"@2 ‚%&6$#6Wa6>W= ĐÁP ÁN A&" S"T0$# "/ , ,- :@2-n$⟺5:,)≥) ⟺ x ≥ 5 N xác đn$⟺:Ym> 0 ⟺ x > 6 )=5J )=5J )=5J )=5J 5 5- 34 4,5 4J A4 4 45Y 4?Y )=J )=J )=5J )=J )=5J G ,- (:≥ ⟺ = 5 ⟺ x+ 1 =25 )=5J )=5J )=5J )=5J ⟺ x =24 ( tho ? 5=J-  ' 2 + (d 3 ) // (d 2 ) nên m = 1 và n ≠ -4 + (d 3 ) c`N’20$#D"-"/2;0$#-S'O$#5⇒ n = -2 (tho akLT G (L4:Y5 )=J )=J )=5J )=5J )=5J )=5J )=5J )=5J NH!$#.w@$A6$ 7 ĐỀ THI KI"M TRA HỌC KÌ I. NĂM HỌC 2011 – 2012 C$"(TOÁN 9 !"#"$(*+C$#/*@-7 ĐỀ BI: Câu 1:,EJ-"/ .'"/01234 ?? 5 +− xx i6:-/'"/01232;$#<= 'i6:"345 Câu 2:,-"/ ^+#R$2@2'"/012>0( i 5Z Z?,, +− 'i xxxx Z55,• G , •5 −+− BX":†) Câu 3:,EJ-"/ .&>K 5 x y −= T , B&&>KL45:MGT 5 iapT , B&T 5 N\$2~$#P*Q$#R-S= 'i{@2-n$2@28>KB&'29&>KL4:M'T G =A"FT G >$#>$#T , B&T G 2`T , D"S-"/N\$N’20$#= Câu 4:5-"/ .'"/0124 x x x x x x ? ? 55  − ⋅ + + − BX" ?V) ≠> xx i^+#R$= 'i6:-/ŽG Câu 5:,EJ-"/ .#"@23A.2;3A4G2E3.4?2EA.4J2= i.1$#"$#"@23A.B0C$# 'iŠ-H!$#23=I$3EAE.E#;2. Câu 6:5EJ-"/ .-H!$#N]$ E-H!$#I$3AE-"/0S2-H!$#N]$ =ap-K":1$#BX"3|0 =A2`-H!$#N]$•.=R"‚%&#"-"/293.B&A= i.1$#"$NO$#(‚ ⊥ 3A= 'iR"–%&-"/-K":1$#BX"‚|0=.1$#"$NO$#(–3%&"F*0LF$29 2i.1$#"$NO$#(–%&"F*0LF$29-H!$#N]$AVA3 [...]... KHI 9 Thi gian lm bi 90 phỳt (Khụng k thi gian phỏt ) Bi 1 (1) Rut gon biờu thc : 1 5 1 A= 45 15 + 180 3 (2 5) 2 3 9 2 Bi 2 (1.5) Giai phng trinh : 16 x + 16 9 x + 9 + 4 x + 4 = 16 x + 1 y= 2m + 4 x 3m m 1 Bi 3 (1) Cho ham sụ Vi gia tri nao cua m thi ham sụ ó cho la ham sụ bõc nht Bi 4 (1.5) a) Xac inh ham sụ y = ax+b biờt thi ham sụ song song vi ng thng y = 3x+1 va i qua iờm A(2 ; 5) b) Ve thi. .. MON = 90 ã BOD ã COD ; kờ bự 0 Ghi chỳ: Hc sinh cú th cú cỏch gii khỏc, ỳng vn cho im Trng THCS TN PHC KHNH KIấM TRA HC KY I Mụn TON KHI 9 Thi gian lm bi 90 phỳt (Khụng k thi gian phỏt ) 0,75 Bi 1 (1) Rut gon biờu thc : 1 5 1 A= 45 15 + 180 3 (2 5) 2 3 9 2 Bi 2 (1.5) Giai phng trinh : 16 x + 16 9 x + 9 + 4 x + 4 = 16 x + 1 y= 2m + 4 x 3m m 1 Bi 3 (1) Cho ham sụ Vi gia tri nao cua m thi ham... Tiờp tuyờn chung trong tai A ct tiờp chung ngoai BC K a Chng minh goc BAC = 90 0 b Tinh sụ o goc OKO' c Tinh ụ dai BC biờt OA = 9cm, O'A = 4cm PHềNG GDT HUYN TN UYấN TRNG THCS Lấ TH TRUNG THI HC KY I (tham kho) Nm hc 2011-2012 Mụn : Toỏn 9 Thi gian: 90 ' (Khụng k thi gian phỏt ) bi Cõu 1: (1,5 im) 2x + 3 a, Vi gia tri nao cua x thi cn thc 15 + 3 2 1+ 5 3 1 b, Tinh : Cõu 2: (2im) Rut gon cac biờu thc... PHềNG GDT HUYN TN UYấN TRNG THCS Lấ TH TRUNG THI HC KY I (tham kho) Nm hc 2011-2012 Mụn : Toỏn 9 Thi gian: 90 ' (Khụng k thi gian phỏt ) bi Cõu 1: (1,5 im) 2x + 3 a, Vi gia tri nao cua x thi cn thc co nghia ? 15 + 3 2 1+ 5 3 1 b, Tinh : Cõu 2: (2im) Rut gon cac biờu thc sau: a 2 a + 2 4 a a +2 a 2 a a/ vi a>0, a 4 4 4 x + 20 3 5 + x + 9 x + 45 = 6 3 b/ Giai phng trinh: Cõu 3: (2 im)... 3 Cõu 4 2 a, Tinh x, y trong hinh ve: y= x= (7 2 + 92 ) = 130 0,5 0,5 63 130 0,5 b, Tinh goc B, goc C va diờn tich tam giac ABC : tan B = 9 7 => à B 5207 ' 1 SABC = (7 .9) = 31,5 2 0 0 0,5 0 Võy goc C = 90 - 52 7 37 53 (vdt) Cõu 5 2,5 - Ve hinh ung 0,75 a, Chng minh rng bụn iờm B, E, D, C cựng thuục mụt ng tron Ta co: ã BEC = 90 (CE AB) ã BDC = 90 0 (BD AC) 1 0 BEC vuụng tai E co EO la ng trung... Uyờn Trng THCS Thai Hoa ấ THI HC Kè I MễN TON LP 9 NM HC 2011-2012 Bai 1: ( 1 ) Vi gia tri nao cua x thi biờu thc sau co nghia : ; Bai 2: ( 2 ) Tinh: Bai 3: (1 ) Giai phng trinh : Bai 4 : ( 2,5 ) Trong cựng mt phng toa ụ Oxy cho ham sụ va ham sụ y = x 4 co thi la d) Ve thi va trờn cựng mụt hờ trc toa ụ e) Tim toa ụ giao iờm A cua f) Xac inh m va n cua ng thng va co d thi la bng phep toan : y... THCS HUYNH VN LUY Cõu 1 (1) Cho biờu thc A = 3 =2 3 2 ấ THI HKI - MễN TON 9( tham khao) Thi gian lam bai : 90 phut 2 x ) Tim iờu kiờn cua x ờ A co nghia ) Tim x sao cho A = 4 ) ) ) ) ) ) Cõu 2 ( 2 ) : Cho tam giac ABC vuụng tai A, biờt tan C = 3 4 , ng cao AH= 12 cm Tinh BH, AB 2 2 Cõu 3 (1,5 ) Cho ham sụ y= ax + 1 Tim hờ sụ a biờt rng khi x=1+ thi y= 3+ Cõu 4 (2,5 ) Trong mt phng toa ụ Oxy cho ng thng... ug 0.5 a Chng minh goc BAC = 90 0 hoc sinh chng minh KA = KB = KC => AK la trung tuyờn ABC va AK = 1/2BC =>ABC vuụng tai A hay BC = 90 0 b Tinh sụ o goc OKO' ả ả ả ả K1 = K 2 va K 3 = K 4 hoc sinh chng minh c ã OKO ' = 90 0 ta co hai tia phõn giac cua hai goc kờ bự => c Tinh ụ dai BC biờt OA = 9cm, O'A = 4cm Tam giac OKO' vuụng tai K va co KA la ng cao nờn KA2 = AO.AO' = 9. 4 = 36 => IA = 6cm hoc sinh... ; m 1 thi ham sụ ó cho la ham sụ bõc nht a) Xac inh ung ham sụ y = 3x 1 b) thi ham sụ y = 3x 1 la ng thng i qua iờm (0 ; -1) va 1 ;0 ữ 3 iờm Ve ung thi ham sụ y = 3x 1 (d) : y = 2x + m 3 va (d) : y = 3x 2m + 12 Vi a a (2 3) nờn : (d) va (d) ct nhau tai mụt iờm trờn trc tung b = b m 3 = - 2m + 12 3m = 15 m=5 4 16 5 25 sin = sin2 = Do sin2 + cos2 = 1 cos2 = 1 - sin2 16 9 3 ... phng trinh 4 9 x + 45 = 6 3 2 x+5 3 5+ x +4 x+5 = 6 0,25 4 x + 20 3 5 + x + 0,25 3 x+5 = 6 0,5 x + 5 = 2( Kx 5) x+5= 4 x = -1 (thoa món iờu kiờn) Võy x=-1 a, ham sụ bõc nht y = (m - 2)x + 3 Cõu 3 2 Ham sụ ng biờn khi : Nghich biờn khi: m < 2 m 2 > 0 m > 2 0,25 0,25 b) vi m = 3 : Ve thi ham sụ : y = x + 3 x 0 -3 y = x +3 3 0 0,25 0,75 - ve thi : c) Xac inh gia tri cua m ờ thi ham sụ i . 4†3%&-H!$#N0$#'6$ 29 6$$#A‚. 4†3iiA &A ⊥ ‚ 4†3 ⊥ ‚ &34A4.4•A. 4†30S2-H!$#N]$-H!$#I$A. akL‚%&"F*0LF$ 29 -H!$#N]$-H!$#I$A. )EJ , , , Phòng GD Huyện Tân Uyên ĐỀ KI"M TRA HỌC K I (THAM KH%O) Trường THCS Vĩnh Tân THỜI GIAN : 90 Phút Toán lớp 9 MÔN : TOÁN LP 9 Câu 1(^+#R$2@2'"/012>0(,EJ-. = , 2=I$-ST&"A.'"F342E™34?2 #"@2™B0C$#D"B&2;3%&-H!$#2$$ 3 5 43=3™4=?4Gm 4†34m2 R2>"$I$-Hl2A.4534,52 , q ^uv.wjš^ ĐỀ THI HỌC K I (tham khảo) Năm học 2011-2012 Môn : Toán 9 Thời gian: 90 ' (Không kể thời gian phát đề) Đề bài Câu 1: (1,5 điểm) EaX"#"@Nn$& 29 :62›$12 5:. (L4:Y5 )=J )=J )=5J )=5J )=5J )=5J )=5J )=5J NH!$#.w@$A6$ 7 ĐỀ THI KI"M TRA HỌC KÌ I. 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