... e(λ1+λ2+λ 3 )tgives6F3sym(λ1,λ2,λ 3 ) = −6 H1(λ1+λ2+λ 3 )F3sym(λ1,λ2,λ 3 )− 6H3sym(λ1,λ2,λ 3 )F1(λ1)F1(λ2)F1(λ 3 ) − 4[F1(λ1)F2sym(λ2,λ 3 )H2sym(λ1,λ2+λ 3 ) ... (s1+c)(s2+c)(s 3 +c)___________________________________] =(a−b) 3 K_______ [s+3a(a−c) 3 _______ − s+2a+b 3( a−c)2(b−c)____________ + s+a+2b 3( a−c)(b−c)2____________ − s+3b(c −b) 3 _______]A 3 [(s1+a)2(s2+a)2(s 3 +a)2K_____________________] ... =s+a+b+cK__________A 3 [(s1+a)(s1+b)(s2+a)(s2+b)(s 3 +a)(s 3 +b)K___________________________________] =(a−b) 3 K_______ [s+3b1______ − s+2a+b 3 ________ + s+a+2b 3 ________ − s+3a1______]A 3 [(s1+a)(s1+b)(s2+a)(s2+b)(s 3 +a)(s 3 +b)K (s1+c)(s2+c)(s 3 +c)___________________________________]...