... part of (5.2.2) isfeven= d0+c 1 d 1 +c2d2+··· (5.2 .12 )where in terms of intermediate variablesα 1 =a 1 b 1 αn=anbnbn 1 ,n≥2(5.2 .13 )we haved0= b0,c 1 =α 1 ,d 1 =1+ α2cn=−α2n 1 α2n−2,dn =1+ α2n 1 +α2n,n≥2(5.2 .14 )You ... b0,c 1 =α 1 ,d 1 =1+ α2cn=−α2n 1 α2n−2,dn =1+ α2n 1 +α2n,n≥2(5.2 .14 )You can find the similar formula for the odd part in the review by Blanch [1] .Oftena combination of the transformations (5.2 .14 ) and (5.2 .11 ) is ... good as other methods. 17 2Chapter 5. Evaluation of Functions Sample page from NUMERICAL RECIPES IN C: THE ART OF SCIENTIFIC COMPUTING (ISBN 0-5 21- 4 310 8-5)Copyright (C) 19 88 -19 92 by Cambridge University...