... D)X1(8 :26 )dX 2 =dt ¼ (m 2 À D)X 2 (8 :27 )dS1=dt ¼ C1F À m1X1=Y1À DS1(8 :28 )dS 2 =dt ¼ C 2 F À m 2 X 2 =Y 2 À DS 2 (8 :29 )wherem1¼ m1,max=[1 þ K1=(S1=V)] (8:30)m 2 ¼ m 2 ,max=[1 ... Y1 and Y 2 togive:(X1=X1,0)A1=[(Y1S1,0þ X1,0À X1)=(Y1S1,0)]B1¼ exp (m1,maxt)(8: 52) (X 2 =X 2 ,0)A 2 =[(Y 2 S 2 ,0þ X 2 ,0À X 2 )=(Y 2 S 2 ,0)]B 2 ¼ ... Interactions 22 1dX1=dt ¼ m1X1À m 2 X 2 =Y 2 (8:57)dX 2 =dt ¼ m 2 X 2 (8:58)dS=dt ¼Àm1X1=Y1(8:59)where m1 and m 2 are given by Eqs (8.36) and (8.37), respectively. This set of equations...