1 VEC TO VA CAC DANG BAI TAP

. các véc tơ b;a biết: a) )7;4(c);4;3(b) ;1; 2(a b) )3 ;1( c);3;2(b) ;1; 1(a Bài 2. Cho bốn điểm A (1; 1); B(2; -1) ; C(4;3); D (16 ;3). Hãy biểu diễn véc tơ AD theo. 6 GV: Nguyn Vn Huy ( 0909 64 65 97 ) Hỡnh hc 10 trục to độ và hệ trục to độ Phần 1. Trục to độ Bài 1. Trên trục x'Ox cho 2 điểm A, B có tọa độ...

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... discover. 8. I dont remember ..of the decision to change the company policy on vacations. a. telling b. being told c. to tell d. to be told. 9. The children to the zoo. a. were enjoyed taken b. enjoyed ... taking. 10 . A new bike was bought .him on his birthday. a. to b. for c. with d. on. 11 . His car needs . a. be fixed b. fixing c. to be fixing d. fixed. 12 . Her watch needs . a. reparing b. to be ... have never made to do anything we didnt want to do. d. We had never made to do anything we didnt want to do. 10 . Brian told me that somebody had attacked him in the street. a. I was told by Brian...

. VẬT LÝ 12 4+ E =222222 1 2 1 2 1 2 1 AmkAkxmvEEtđ+ Kích thích bằng va chạm : dùng định luật bảo to n động lượng, bảo to n động năng ( va chạm. đoạn: 1 N2N )1( 1 01 teNN 1{ 22NN - e- )(34tt }302teNNDạng 4 : Định luật bảo to n năng lượng to n phần và bảo to n động...

. 6,022 .10 23 mol -1 . *ănăvănngălng: 1eV = 1, 6 .10 -19 J; 1MeV = 1, 6 .10 -13 J *ănăvăkhiălngăngunătă(đnăvăCacbon): 1u = 1, 66055 .10 -27kg. 2.ănăvăkhiălngăngunătă(u): 27 1, 007276 1 1,66055 .10 1, 008665pnmuu kgmu 3.ăCácăcơngăthcăliênăh: 2 1 2 1 32 1 02 1 32 1 0 ầUYN TảI I ảC MƠN...

... nhau thì: T2 = T 1 2 + T22 ; 222 1 2 11 1fff * Song song: k = k 1 + k2 + …  cùng treo một vật khối lượng như nhau thì:2 2 2 1 2 1 1 1 T T T   ; f2=f 1 2+f22 * ... Acos(t + ). Trong đó: 2 2 2 1 2 1 2 2 1 2 os( )A A A A A c     1 1 2 2 1 1 2 2sin sintanos osA AA c A c   với  1 ≤  ≤ 2 (nếu  1 ≤ 2 ) Chú ý:   ... cắt thành các lò xo có độ cứng k 1 , k2, … và chiều dài tương ứng là l 1 , l2, … thì có: kl = k 1 l 1 = k2l2 = … 7. Ghép lò xo: * Nối tiếp 1 2 1 1 1 k k k    cùng treo một...

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wAAAAINgAAAMEGAACAYAMAABBsAAAACDYAAADBBgAAgGADAABAsAEAAAg2AAAABBsAAIBgAwAAQLABAAAg2AAAAAQbAAAAgg0AAECwAQAAINgAAAAEGwAAAIINAAAAwQYAACDYAAAAEGwAAACCDQAAAMEGAACAYAMAABBsAAAACDYAAADBBgAAgGADAABAsAEAAAg2AAAABBsAAIBgAwAAQLABAAAINgAAAAQbAAAAgg0AAECwAQAAINgAAAAEGwAAAIINAAAAwQYAACDYAAAAEGwAAACCDQAAAMEGAAAg2AAAABBsAAAACDYAAADBBgAAgGADAAAQbAAAAAg2AAAABBsAAIBgAwAAQLABAAAINgAAAAQbAACAYAMAAECwAQAAINgAAAAEGwAAAIINAABAsAEAACDYAAAAEGwAAACCDQAAAMEGAAAg2AAAABBsAAAACDYAAADBBgAAgGADA ... 3,22 ,13 ,1 vvv. + Khi 2 ,1 vvà 3,2vcùng phương, cùng chiều thì v 1, 3 = v 1, 2 + v2,3 + Khi 2 ,1 vvà 3,2vcùng phương, ngược chiều thì v 1, 3 = |v 1, 2 - v2,3| + Khi 2 ,1 vvà ... tốc: 3,22 ,13 ,1 vvv Khi 2 ,1 vvà 3,2vcùng phương, cùng chiều thì v 1, 3 = v 1, 2 + v2,3 Khi 2 ,1 vvà 3,2vcùng phương, ngược chiều thì v 1, 3 = |v 1, 2 - v2,3| LUYỆN...

... ngBài 1. Ta có: i 1 =aD 1 = 3 .10 -3 m; 1 iL= 8  có 9 vân sáng ca bc x có bc sóng  1 và có 17 - 9 + 3 = 11 vân sáng ca bc x có bc sóng 2 i2 = 1 11 L= 2,4 .10 -3 ... 0,48 .10 -6 m.Bài 2. Các vân trùng có: k 1 aD 1 = k2aD2 k2 = k 1 2 1 =43k 1 ; các vân sáng trùng ng vi k 1 = 0, 4, 8, 12 , và k2 = 0, 3, 6, 9, . Vì i 1 =aD 1 = 1, 8 .10 -3 ... dng:348 10 0AK min 19 3min 0AKhc hc 6,625 .10 .3 .10 eU =  0,6625 .10  eU 1, 6 .10 .18 ,75 .10 m.Bài tp minh haBài 1 . Mt èn phát ra bc x có tn s f = 10 14 Hz. Bc x này thuc...