... A + eVmax hf = A + 1,25eVmax => h(f f) = 0,25eVmax = 0 ,25( hf A) => hf = 1,25hf 0,25A => f = 1,25f 0,25A/h A/h = 3,86.1,6.10-19/6, 625. 10-34- = 0,932 1015 => f= 1,25f 0,25A/h = 1,639.1015 Hz ... ỏp xoay chiu cú biu thc u=U0cos(100t) vo hai u on mch RLC ni tip Ti thi im cng dũng in mch cú ln cc i thỡ in ỏp hai u on mch cú ln Khong thi gian ngn nht gia hai thi im m cụng sut tc thi bng ... < AB hf = A + 1, 25eV , ( ) A MAX SAU ( 1) 0, 25 AA 0, 25. 3,86.1, 6.10 19 hf SAU = AA + 1, 25 ( hf AA ) f SAU = 1, 25 f = 1, 25. 1,5.1015 1, 642.1015 ( Hz ) 34 h 6, 625. 10 ( ) c 3.108...