Options futures and other derivatives solutions manual (san) by john hull

Chapter 1 introduction of options, futures, and other derivatives

Chapter 1 introduction  of options, futures, and other derivatives
... 2 012 Foreign Exchange Quotes for GBP, May 24, 2 010 (See page 5) Bid Offer Spot 1. 4407 1. 4 411 1- month forward 1. 4408 1. 4 413 3-month forward 1. 4 410 1. 4 415 6-month forward 1. 4 416 1. 4422 Options, Futures, ... 17 .40 28.30 29.30 40.60 41. 30 520 9.00 9.30 19 .10 19 .90 31. 40 32.00 540 4.20 4.40 12 .70 13 .00 23 .10 24.00 560 1. 75 2 .10 7.40 8.40 16 .80 17 .70 Options, Futures, and Other Derivatives, 8th Edition, ... = S (1+ r )T where r is the 1- year (domestic currency) riskfree rate of interest In our examples, S = 14 00, T = 1, and r =0.05 so that F = 14 00 (1+ 0.05) = 14 70 Options, Futures, and Other Derivatives, ...
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Primer on Electricity Futures and Other Derivatives

Primer on Electricity Futures and Other Derivatives
... selling a futures contract on or near the delivery date Other electric rate derivatives include options, price swaps, basis swaps, and forward contracts Futures and options are traded on an exchange ... returns on positions taken in futures and other derivatives contracts A related concern is that, where futures contracts are settled through delivery—a rare event, as we discuss, but one that nonetheless ... in contracts Electricity futures and other electric rate derivatives help electricity generators, consumers, and marketers manage, or hedge, price risks in a competitive electricity market Futures...
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fundamentals of heat and mass transfer solutions manual phần 1 docx

fundamentals of heat and mass transfer solutions manual phần 1 docx
... d/y = 5.80 10 11 J With a furnace energy consumption of Ef = E/ηf = 6.45 10 11 J, the annual cost of the loss is C = Cg Ef = 0. 01 $/MJ × 6.45 10 5MJ = $6450 < COMMENTS: The heat loss and related ... value of the heat rate PROBLEM 1. 10 KNOWN: Thickness, diameter and inner surface temperature of bottom of pan used to boil water Rate of heat transfer to the pan FIND: Outer surface temperature of ... temperatures Th with Tw = 20°C 200 Initial rate of change, dTw/dt (K.s^ -1) 400 Heat flux (kW/m^2) 300 200 10 0 15 0 10 0 50 0 300 500 700 900 11 00 13 00 300 500 700 900 11 00 Hot plate temperature, Th (C) Hot...
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fundamentals of heat and mass transfer solutions manual phần 2 docx

fundamentals of heat and mass transfer solutions manual phần 2 docx
... reductions in q and m are achieved with r2 = 0 .26 -3  m With increasing r2, q and m decrease from values of 17 02 W and 8×10 kg/s at r2 = 0 .25 m to 0. 627 W and 2. 9×10-6 kg/s at r2 = 0.30 m COMMENTS: ... surface of the insulation, it follows that q′ cond = q′ conv + q′ rad Ts,1 − Ts ,2 ln ( r2 r1 ) 2 k ( = Ts ,2 − T∞ + Ts ,2 − Tsur ( 2 r2 h ) ( 2 r2 h r ) where h r = εσ Ts ,2 + Tsur 2 ) (Ts ,2 + Tsur ... r1 ) − (1 r2 )] , and, from Eq 2 ) (Ts ,2 + Tsur ) With t = 10 mm (r2 = 26 0 mm), ε = 0 .2 and T∞ = Tsur = 29 8 K, an iterative solution of the energy balance equation yields Ts ,2 29 7.7 K, where...
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fundamentals of heat and mass transfer solutions manual phần 3 pdf

fundamentals of heat and mass transfer solutions manual phần 3 pdf
... 0.6 939 T11 + 7.65 The initial estimates (k = 0) are carefully chosen to minimize calculation labor; let ε < 1.0 k T1 34 0 33 8.9 33 8 .3 338 .8 33 9.4 33 9.8 34 0.1 34 0 .3 T2 33 0 33 6 .3 337 .4 33 8.4 33 8.8 33 9.2 ... 282.4 31 0.9 34 0.0 25 180.2 2 03. 6 228 .3 254.4 281.8 31 0.5 34 0.0 50 178.4 201.6 226.2 252.4 280.1 30 9 .3 339 .6 75 175.4 198.2 222.6 248.7 276.9 30 7.1 33 9.1 100 171.1 1 93. 3 217.2 2 43. 1 271.6 30 3.2 33 7.9 ... 33 9.2 33 9.4 33 9.5 T3 31 5 32 4 .3 328.0 32 8.2 32 8.9 32 9 .3 329.7 32 9.9 T4 250 237 .2 241.4 247.7 251.6 254.0 255.4 256.4 T5 225 232 .1 241.5 245.7 248.7 250.5 251.7 252.5 T6 205 225.4 226.6 230 .6 232 .9...
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fundamentals of heat and mass transfer solutions manual phần 4 docx

fundamentals of heat and mass transfer solutions manual phần 4 docx
... 356.9 357 .4 357.9 358 .4 358.9 359 .4 T02 3 54. 9 355 .4 355.9 356 .4 356.9 357 .4 T03 351.6 352.1 352.6 353.1 353.6 3 54. 1 T 04 346 .9 347 .4 347 .9 348 .4 348 .9 349 .3 T05 340 .9 341 .4 341 .9 342 .3 342 .8 343 .2 ... 20 30 40 45 T0 85 85 85 85 76.9 76.9 68.8 68.8 61.7 61.7 T1 85 85 85 76.9 76.9 68.8 68.8 61.7 61.7 55.6 T2 85 85 68.8 68.8 60.7 60.7 54. 6 54. 6 49 .5 49 .5 T3 85 52.5 52.5 44 .4 44. 4 40 .4 40 .4 37.3 ... 125.00 137.50 143 .75 146 .88 148 .44 149 .22 149 .61 149 .80 T2 (°C) Implicit 50 83.33 105.55 120.37 130.25 136.83 141 .22 144 .15 146 .10 147 .40 100 100 100 100 100 100 100 100 100 100 < The heat flux at...
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fundamentals of heat and mass transfer solutions manual phần 5 ppsx

fundamentals of heat and mass transfer solutions manual phần 5 ppsx
... 75. 5 W m ⋅ K q′ = hπ D ( Ts − T∞ ) = 75. 5 W m ⋅ K π ( 0.01m ) (50 − 20 ) C = 71.1W m  Fluid: Saturated Water (5 m s ) 0.01m VD = = 68, 55 2 Re D = ν 7 25 × 10−6 N ⋅ s m 994 kg m3 0.62 ( 68, 55 2 ... ≈ 0 .51 ( 9 25) ( 0.686) k 0.0373 W/m ⋅ K h = Nu D = 13 .5 = 50 .4 W/m2 ⋅ K Do 0.01 m 0 .5 0.37 1/4 0 .5 0.37 ×1 = 13 .5 Hence ( ) 1/2  50 .4 W/m2 ⋅ K 0.0314 m   m =  5 m   ( 35 W/m ⋅ K ) 5. 89 ... 600 55 0 50 0 450 400 350 300 50 100 150 200 250 300 Time, t(s) Without radiation With radiation, eps = 0.8 Continued The agreement between predictions with and without radiation for t < 50 s implies...
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fundamentals of heat and mass transfer solutions manual phần 6 docx

fundamentals of heat and mass transfer solutions manual phần 6 docx
... 8 .60 was used The effects of m are as follows Continued PROBLEM 8.30 (Cont.) 67 70 69 .8 Outlet temperature, Tmo(C) Outlet temperature, Tmo(C) 66 65 64 63 62 61 60 0.005 69 .6 69.4 69 .2 69 0.0 06 ... rate and properties of hot fluid Initial temperature, volume and properties of pharmaceutical Heat transfer coefficient at outer surface and dimensions of coil FIND: (a) Expressions for Tc(t) and ... the heat loss is q ′ = 3 46 W / m PROBLEM 8. 36 KNOWN: Inner and outer diameter of a steel pipe insulated on the outside and experiencing uniform heat generation Flow rate and inlet temperature of...
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fundamentals of heat and mass transfer solutions manual phần 7 pot

fundamentals of heat and mass transfer solutions manual phần 7 pot
... Node Tm(K) 391 .70 385.95 380 .70 375 .92 371 .56 10 3 67. 61 364.03 360.81 3 57. 91 355.32 11 12 13 14 15 353.02 351.00 349.25 3 47. 75 346.50 16 17 18 19 20 345.49 344 .70 344.15 343.82 343 .71 From these ... 12.2 343 − Ts,i = 0. 175 0.60 + 2.64 Ts,i − 273 )1/ } (Ts,i − 273 ) + 0.5 × 5. 67 × 10−8 Ts,i − ( 273 )4    Ts,i ≈ 314 .7 K ≈ 41 .7 C A trial -and- error solution gives < The heat loss per unit length ... significant if 0.1 37 ReD < 4 .7 GrD Pr ( ) where GrD = RaD/Pr, find using results from above and in part (a) for ω = 5000 rpm, 0.1 37 11, 076 ? < ? 4 .7 ( 27, 981 0 .70 28 ) 0 .70 18     = 383...
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fundamentals of heat and mass transfer solutions manual phần 8 ppsx

fundamentals of heat and mass transfer solutions manual phần 8 ppsx
... 11.14 and 11.15 where ∆T1 = Th,i - Tc,o = 80 °C and ∆T2 = Th,o - Tc,i = 120°C Hence, ∆T1m = (120 80 )°C/ln(120 /80 ) = 98. 7°C and L= q 3000 W = = 0.9 68 m (π D ) U∆T1m (π × 0.02 m ) 500 W m2⋅ K × 98. 7 ... Cmin/Cmax = (5,000 × 41 78) /(10,000 × 4 188 ) = 0.499 Combining Eqs (1) and (2), find Th,o = 80 °C − 0.7 × 3 48. 2 × 103 W / (10,000/3600 ) k g / s × 4 188 J / k g ⋅ K ( Th,o = ( 80 − 21.0 ) ° C = 59°C ... Overall heat transfer coefficient, U, for the HXer, outlet temperature of cooling water, Tc,o,   and condensation rate of the steam m h ; and (b) Compute and plot Tc,o and m h as a function of the...
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fundamentals of heat and mass transfer solutions manual phần 9 ppt

fundamentals of heat and mass transfer solutions manual phần 9 ppt
... PROBLEM 12 .99 (Cont.) t= ( −11 2.4504 ×10 K −1 −1 ⋅s ) ( 292 8 K )  3  ln 292 8 + 2741 292 8 + 300 − ln 292 8 − 2741 292 8 − 300   2741  −1  300   +2  tan −1   − tan  292 8    292 8   ... 4.17E-5 0.0417 6.39E-5 0.702 600 5.179E-5 0.0446 7.39E-5 0.701 700 6.671E-5 0.0 499 9. 44E-5 0.706 800 8.29E-5 0.0548 0.000116 0.715 90 0 0.0001003 0.0 597 0.0001 39 0.721 1000 0.0001187 0.0647 0.000165 ... rate, M is the mass of PCM, and hfg is the heat of fusion of PCM Irradiation: -8 4 G = σTw = 5.67 × 10 W/m ⋅K (1200 K) = 117,573 W/m Emissive power: Eb = σ Tm = σ ( 87 +273 ) = 95 2 W / m λT =...
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fundamentals of heat and mass transfer solutions manual phần 10 doc

fundamentals of heat and mass transfer solutions manual phần 10 doc
... coefficient and temperature of gas flow over the tube Temperature of surroundings FIND: (a) Rate of heat transfer to tube without ash deposit, (b) Rate of heat transfer with an ash deposit of diameter ... Diameters of heated tube and radiation shield Tube surface temperature and temperature of ambient air and surroundings FIND: Temperature of radiation shield and heat loss per unit length of tube ... Dimensions and inclination angle of a flat-plate solar collector Absorber and cover plate temperatures and emissivities FIND: (a) Rate of heat transfer by free convection and radiation, (b) Effect of...
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báo cáo sinh học:" Postoperative outcome of caesarean sections and other major emergency obstetric surgery by clinical officers and medical officers in Malawi" docx

báo cáo sinh học:
... bulk of emergency obstetric operations at district hospitals in Malawi The postoperative outcomes of their procedures are comparable to those of medical officers However, in order to sustain and ... medical officers (MOs)) are licensed to practice independently and perform major emergency and elective surgery Unlike in Mozambique [9,10] and Tanzania [11], the delegation of major surgery ... as 93% of major emergency obstetric operations in government district hospitals were done by COs and this includes surgery on complicated conditions This is similar to earlier findings by Fenton...
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The meaning and structure of the inaugural address by John F. Kennedy in 1961 A systemic functional analysis = Cấu trúc và ngữ nghĩa bài diễn văn nhậm chức của

The meaning and structure of the inaugural address by John F. Kennedy in 1961 A systemic functional analysis = Cấu trúc và ngữ nghĩa bài diễn văn nhậm chức của
... on the meaning and structure of the inaugural address by John F Kennedy in 1961 using systemic functional grammar as the theoretical framework In part A, the topic, the aim, the scope, and the ... helps strengthen my notion of its applications in language teaching and learning In this study, the analysis of structure and meaning of the inaugural address by John F Kennedy in 1961 is conducted ... Oanh ii ABSTRACT This study applies systemic functional grammar in order to investigate the meaning and structure of the inaugural address by John F Kennedy in 1961 Based on the framework of systemic...
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