... Ca(OH)2 (0 ,111 mol) → CaCO (x)3Ba(OH)2Ca(HCO ) (0 ,111 -x) BaCO (0 ,111 -x)+CaCO (0 ,111 -x)3 2 3 3→ Nên 100x+(0 ,111 -x)100+(0 ,111 -x)197=20,95 → x= 0,061 → nCO2= 0,061+2(0 ,111 -0 ,061)= ... +Phản ứng 3,66.10 -2 3,75.10 -4 0 0Sau phản ứng (3,66.10 -2 – 3,75.10 -4 )0 3,75.10 -4 3,75.10 -4 Nên Ka= x(x+3,75.10 -4 )/(0,036225-x)=10 -4 ,76 → x = 6, 211. 10 -4 pH = 3,207=3,21c. ... nCa(OH)2 = 0 ,115 molCO2 + Ca(OH)2 (0,151mol) → CaCO (x)3Ba(OH)2Ca(HCO ) (0 ,115 -x) BaCO (0 ,115 -x)+CaCO (0 ,115 -x)3 2 3 3→ Nên 100x+(0 ,115 -x)100+(0 ,115 -x)197=24,305...