java software solutions foundations of program design 4th edition phần 1 potx

... represented000000 01 0 010 0 011 010 0 010 1 011 0 011 1 10 00 10 01 1 010 10 11 110 0 11 01 111 0 11 11 00000000 01 00 010 00 011 0 010 00 010 10 011 00 011 1 010 00 010 01 010 10 010 11 011 00 011 01 011 10 011 11 10000 10 0 01 10 010 10 011 10 100 10 1 01 1 011 0 10 111 11 000 11 0 01 110 10 11 011 11 100 11 1 01 111 10 11 111 1 bit 2 bits 3 bits 4 bits2 items 4 items 8 items 16 items5 bits32 ... number of items that can be represented000000 01 0 010 0 011 010 0 010 1 011 0 011 1 10 00 10 01 1 010 10 11 110 0 11 01 111 0 11 11 00000000 01 00 010 00 011 0 010 00 010 10 011 00 011 1 010 00 010 01 010 10 010 11 011 00 011 01 011 10 011 11 10000 10 0 01 10 010 10 011 10 100 10 1 01 1 011 0 10 111 11 000 11 0 01 110 10 11 011 11 100 11 1 01 111 10 11 111 1 ... 3 bits 4 bits2 items 4 items 8 items 16 items5 bits32 items0000 01 010 011 10 0 10 1 11 0 11 100 01 10 11 0 1 6 CHAPTER 1 computer systemsDigital technology breaks information into discrete...

Java software solutions foundations of program design 4th edition phần 8 potx

... 8)Decimal(base 10 )Hexadecimal(base 16 )0 1 10 11 10 0 10 1 11 0 11 1 10 00 10 01 1 010 10 11 110 0 11 01 111 0 11 11 10000 10 0 01 10 010 10 011 10 1000 1 234567 10 11 12 13 14 15 16 17 20 21 2223240 1 23456789 10 11 12 13 14 15 16 17 18 19 200 1 23456789ABCDEF 10 11 12 13 14 688 ... 16 )0 1 10 11 10 0 10 1 11 0 11 1 10 00 10 01 1 010 10 11 110 0 11 01 111 0 11 11 10000 10 0 01 10 010 10 011 10 1000 1 234567 10 11 12 13 14 15 16 17 20 21 2223240 1 23456789 10 11 12 13 14 15 16 17 18 19 200 1 23456789ABCDEF 10 11 12 13 14 688 APPENDIX B number systemsthat is a power of 2. We section the bits into groups of that power. ... hexadecimal to binary40C6 16 = 10 0000 011 00 011 02 10 0000 011 00 011 040C6 11 00 010 0 0000 011 0APPENDIX A glossary 665comment—A programming language construct thatallows a programmer to embed human-readableannotations...

Java software solutions foundations of program design 4th edition phần 2 pdf

... language.figure 2 .11 Some packages in the Java standard class libraryPackage Provides support to java. applet java. awt java. beans java. io java. lang java. math java. net java. rmi java. security Create programs ... variable?2 .10 What are the four integer data types in Java? How are they different?2 .11 What is a character set?2 .12 What is operator precedence?2 .13 What is the result of 19 %5 when evaluated in a Java ... in each of thelisted assignment statements?int iResult, num1 = 25, num2 = 40, num3 = 17 , num4 = 5;double fResult, val1 = 17 .0, val2 = 12 .78;◗ iResult = num1 / num4;◗ fResult = num1 / num4;◗...

java software solutions foundations of program design 4th edition phần 3 pptx

... with Accountobjects. Such programs are often called driver programs because all they do isdrive the use of other, more interesting parts of our program. They are often usedfor testing purposes.The ... fundamental programming 4writing classes 18 6 CHAPTER 3 program statementslisting 3 .17 //********************************************************************// ExamGrades .java Author: Lewis/Loftus//// ... header.keyconcept3 .10 drawing using conditionals and loops 19 1listing 3 .19 //********************************************************************// Boxes .java Author: Lewis/Loftus// // Demonstrates...

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java software solutions foundations of program design 4th edition phần 4 pot

... of list[5]0 1 23456789 10 11 12 13 14 The array is createdwith 15 elements,indexed from 0 to 14 0 1 23456789 10 11 12 13 14 0 10 200 10 2030405060708090 10 0 11 0 12 0 13 0 14 00 10 20304099960708090 10 0 11 0 12 0 13 0 14 0The ... f2.setValue (888);tester.changeValues (a1, a2, a3);a1 a2f1 f2 f1 f2f3 f3a1 a2a3 a3 11 1 11 1 222 333 11 1222 333a1 a2f1 f2 f1 f2f3 f3a1 a2a3 a3 11 1 11 1 888 333999222 333999STEP 5 STEP 6f3 = ... BasicArray program After threeiterations of thefirst loop0 1 23456789 10 11 12 13 14 After completingthe first loop0 1 23456789 10 11 12 13 14 After changingthe value of list[5]0 1 23456789 10 11 12 13 14 The...

Java software solutions foundations of program design 4th edition phần 5 pdf

... answers.int primes = {2, 3, 4, 5, 7, 11 }; float elapsedTimes[] = {11 .47, 12 .04, 11 .72, 13 .88}; int[] scores = int[30]; int[] primes = new {2,3,5,7 ,11 }; int[] scores = new int[30]; char ... Listing 7 .14 represents a generic type of food.The constructor of FoodItem accepts the number of grams of fat and the number of servings of that food. The calories method returns the number of caloriesdue ... every class inevery Java program. keyconcept7.4 polymorphism 411 The Staff class shown in Listing 7 .17 maintains an array of objects that rep-resent individual employees of various kinds. Note...

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Java software solutions foundations of program design 4th edition phần 6 pps

... the TestData program isrun might look like this:85 90 93 15 82 79 52 71 70 9874 57 41 66 22 16 67 65 24 8486 61 91 79 18 81 64 41 68 81 98 47 28 40 69 10 85 82 64 41 23 61 27 10 59 89 88 26 ... 89 73 36 54 91 42 73 95 58 19 41 18 14 63 80 96 30 17 2824 37 40 64 94 23 98 10 78 5089 28 64 54 59 23 61 15 80 88 51 28 44 48 73 21 41 52 35 388.4 object serializationWhen a program terminates, ... (exception);}}}Widget: 14 at 3.35 = 46.9Spoke: 13 2 at 0.32 = 42.24Wrap: 58 at 1. 92 = 11 1.36Thing: 28 at 4 .17 = 11 6.76Brace: 25 at 1. 75 = 43.75Clip: 409 at 0 .12 = 49.08Cog: 14 2 at 2.08 = 295.36outputanswers...

Java software solutions foundations of program design 4th edition phần 7 docx

... few.summary of key concepts 10 .0 software development models 5 71 the program is being maintained. When the changes are serious ornumerous enough, a new version of the program is released for use. A program ... themaintenance tasks, and often the responsibilities of personnel change.Therefore, maintainers often do not understand the software as well asMaintaining software is theprocess of modifying a pro-gram ... responsibilities.A design or code walkthroughis a meeting in which severalpeople review and critique a software design or implementation.576 CHAPTER 10 software engineeringkeyconcept 10 .3 evolutionary...

Java software solutions foundations of program design 4th edition phần 9 ppsx

... the result of this BigDecimal multiplied with the value of arg. The scale of the resulting Big-Decimal is the result of the addition of the two BigDecimal’s scales.766 APPENDIX M the java class ... arg)Returns the result of a logical operation of this BigInteger and the value of arg. The not methodreturns the logical not of this BigInteger.public int bitCount()Returns the number of bits from this ... toByteArray()Returns the two’s complement of this BigInteger in an array of bytes.public static BigInteger valueOf(long arg)Returns a BigInteger from the value of arg.APPENDIX L java syntax 753Return StatementreturnExpression;Throw...

Java software solutions foundations of program design 4th edition phần 10 ppsx

... natural base of logarithms (2. 718 2 818 284590452354) and theratio of the circumference of a circle to its diameter (3 .14 159265358979323846).858 APPENDIX M the java class libraryJTextArea (javax.swing)A ... int ysrc1, int xsrc1, intysrc2, int xdest1, int ydest1, int xdest1, int ydest2, Color bgc, ImageObserverobsv)public abstract boolean drawImage(Image src, int xsrc1, int ysrc1, int xsrc1, intysrc2, ... instance of a GridLayout with a dimension of r rows and c columns (default of 1 by any).public GridLayout(int r, int c, int hg, int vg)Creates a new instance of a GridLayout with a dimension of r...

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