Principles of Engineering Mechanics (2nd Edition) Episode 10 docx

... time-constant T. 10. 7 The hydraulic relay of problem 10. 6 is modified by the addition of a spring of stiffness S and a damper of damping constant C, as shown in Fig. 10. 55. Show that ... tion of the load is given seconds. Find when the maximum acceleration of the load occurs and determine its value. 10. 12 Derive all of equations 10. 17. 10. 13 See example 10. 3. Rewrite ... the total mass times the acceleration of the centre of mass, and is independent of any rotation. Moment of momentum The moment of momentum of a particle about a point 0 is defined...

Principles of Engineering Mechanics (2nd Edition) Episode 4 pot

... moment of external forces = C moment of (mass x acceleration) = moment of the rate of change of = rate of change of the moment of or momentum momentum We may n~~ke use of ... equal to the product of the total mass and the acceleration of the centre of mass. We must now consider the effect of the positions of the lines of action of the applied forces, ... the acceleration of the centre of mass is the same whether or not the line of action of the resultant passes through the centre of mass. Consider initially a group of particles in...

Principles of Engineering Mechanics (2nd Edition) Episode 5 pot

... side of a hill which slopes at 30" away from the centre of curvature of the path as shown. The radius of curvature to the centre of mass can be taken as 30m. The coefficient of ... Moment of inertia of a right circular uniform i) Moment of inertia about the axis of the cylinder. In Fig. 6.8, the mass of an elemental rod is pLdr(rdO), where p is the density of the ... total mass of 760 kg. Each rear wheel moment of inertia of 6 kg m2. The moment of inertia of the front whee1s may be neg1ected. 6.21 See Fig. 6.41, A lift cage with a mass of 2000...

Principles of Engineering Mechanics (2nd Edition) Episode 6 doc

... consequence of equations 8.8 to 8 .10 is the relationship which exists between the velocity of approach and the velocity of recession of the points of contact. Velocity of approach ... and that of the spider is 0.09 kg m2. Each planet has a mass of 2.0 kg and an axial moment of inertia of 0.0025 kg m2. The centres of the Planet wheels are at a radius of 120mm ... radii of the paths. Denoting the angular cylinder of mass ml and radius r rests at the bottom of a speeds of L and R and the cage of the differential gear cylindrical surface of...

Principles of Engineering Mechanics (2nd Edition) Episode 7 pot

... 9.6 so that, on a graph of log8 against logv, lines of constant d appear as straight lines of slope - 1 and lines of constant f appear as lines of slope +1, as shown in ... has a mass of 0.6 kg and a diameter of 50mm. The puck is sliding on a frictionless horizontal surface at a speed of 10 m/s and strikes a rough vertical surface, the direction of motion makes ... 650 kgm'. The mass of the wheels may be neglected. a) If the angle of the incline is 10& quot; above the horizontal, determine the velocity of the axle of the leading wheels immediately...

Principles of Engineering Mechanics (2nd Edition) Episode 9 ppsx

... shown in Figs 10. 5(a) and (b), then 6, = EF&, as shown in Fig. 10. 5(c). Equations 10. 2, 10. 6, 10. 7, and 10. 9(b) are 10. 7 Frequency response methods 167 Sketches of the Nyquist ... pick-off point as shown in Figs 10. 2, 10. 3, and 10. 4. In Fig. 10. 3, the simplest form of the multiplier E will be a constant, and the most complicated form can always be reduced to a ratio of ... product of co- 7 Hz sinusoidal force of amplitude equal to 1% of the ordinates.) weight of machine A is applied to the machine at A what is the amplitude of motion of the structure...

Principles of Engineering Mechanics (2nd Edition) Episode 12 pps

... of the tube shall be the same as that of the rod. So with reference to Fig. 12.22 we see that the compression of the tube is equal to the initial lack of fit plus the compression of ... of area and denoted by I. Similar to moment of inertia, the second moment of area is often written as I=Ak2 where A is the cross-section area and k is known as the radius of ... yz plane (1 2.64) The proofs of these two theorems are similar to those given for moments of inertia in section 6.3. Using the definition of second moment of area equation 12.62 becomes...

Principles of Engineering Mechanics (2nd Edition) Episode 14 pps

... 36)w0 = 8640 10. 19 ala2 = 4oa3, 10. 20 gBOlI(A -g) 10. 17 a) Td = 6 + O.Olw,, 10 s, 10. 18 360Nm, ( 112 4 d(ao a2 10. 22 a) 10. 46, 10. 23 50 10. 24 a) b) 25 10( 1 + 0.2jw) ... 10. 7 A = A1/AzwhereAl = 12c, 10. 6 12/11, (11 + 12)/(11 k) A>= l~C+S(ll+l~)/k, T= C(l1+lz)l(kA2), q = Clk 10. 10 4 N drad, 0.8 rad 10. 11 t = 1 s, 0.147 rads2 10. 14 ... [vx' vy' v,'] The unit vectors of one set of co-ordinates is expressible in terms of the unit vectors of another set of co-ordinates; thus i' = alli+alj+a13k...

Principles of Engineering Mechanics Second Edition pdf

... study of the motion of material bodies and of the associated forces. The study of motion is called kinematics and involves the use of geometry and the concept of time, whereas the study of the ... vector sum of the external forces acting on a particular set of particles equals the total mass times the acceleration of the centre of mass, irrespective of the individual motion of the separate ... Kinetics of a particle in plane motion, 21 Introduction. Newton’s laws of motion. Units. Types of force. Gravitation. Frames of reference. Systems of particles. Centre of mass. Free-body...

Principles of Engineering Mechanics Second Edition H. R. Harrison potx

... Part 3 Engineering Mechanics syllabuses of degree courses in engineering. The emphasis of the book is on the principles of mechanics and examples are drawn from a wide range of engineering ... vector sum of the external forces acting on a particular set of particles equals the total mass times the acceleration of the centre of mass, irrespective of the individual motion of the separate ... vary with time of flight as shown in Fig. 3.24. The vertically upwards direction is +y and the value of g may be taken as 10 N/kg. The mass of the projectile is 10 kg and is assumed...

Xem thêm