...
int intVar1 = 27;
int intVar2 = intVar1;
if(intVar1 == intVar2)
System.out.println("They're equal");
This is the same as the syntax in C and ... that Java doesn't use pointers. Although it surprises
some people, pointers aren't necessary for the creation of complex data structures and
algorithms. In fact, eliminating p...
...
int out, in, min;
for(out=0; out<nElems -1; out++) // outer loop
{
min = out; // minimum
for (in= out +1; in& lt;nElems; in+ +) // inner loop
if(a [in] ... the same way Java does. The delimiters
are the braces '{'and'}', brackets '['and']', and parentheses '('and')'. Each opening...
... ListIterator iter1 = theList.getIterator(); // new iter
iter1.insertAfter( 21) ; // insert links
iter1.insertAfter(40);
iter1.insertAfter(30);
iter1.insertAfter(7); ... if(previous==null) // at beginning of list
first = newLink; // first > newLink
else // not at beginning
previous.next = newLink; // old prev > newLink
ne...
... search, insertion, and deletion?
In investigating the answers, you must keep in mind two facts. First, accessing data on a
disk drive is much slower than accessing it in main memory. ... shown in Figure 10 .11 .
Figure 10 .11 : Selecting the rightmost children
These figures show how to switch among different nodes in the third row by clic...
...
non-darkened lines, leaving only the minimum spanning tree. A final button press
restores the original graph, in case you want to use it again.
Java Code for the Minimum Spanning Tree
... first. Indeed, taking certain courses may be a prerequisite to obtaining a degree in
a certain field. Figure 13 .11 shows a somewhat fanciful arrangement of courses
necessary for gradua...
... while(nTree < nVerts)
{
int indexMin = getMin(); // get minimum from sPath
int minDist = sPath[indexMin].distance;
if(minDist == INFINITY) // if all infinite ...
distance
int minDist = INFINITY; // assume minimum
int indexMin = 0;
for(int j =1; j<nVerts; j++) // for each vertex,
{ // if it's in tree and...
...
min = out; // minimum
for (in= out +1; in& lt;nElems; in+ +) // inner loop
if(a [in] < a[min] ) // if min greater,
min = in; // we have a new min
swap(out, min); ... for(out=nElems -1; out> ;1; out ) // outer loop
(backward)
for (in= 0; in& lt;out; in+ +) // inner loop (forward)
if( a [in] > a [in+ 1] ) // out of order?...
...
h + 1. In the last step (see Figure 8 .10 f -g), we form the final heap, storing all the n
entries, by joining two heaps storing (n − 1) /2 entries (constructed in the previous
step) and adding ... in the heap
tree. (Continues in Code Fragment 8 .14
.)
485
cursively, bottom-up heap construction consists of the following h + 1 = log(n + 1)
steps:
1. In the first step (...