... 276.9 271.6 2 63. 3 250.5 232 .8 2 13. 5125 31 0.9 31 0.5 30 9 .3 307.1 30 3.2 296.0 282.2 257.5150 34 0.0 34 0.0 33 9.6 33 9.1 33 7.9 33 5 .3 324.7Agreement between the temperature fields for the (a) and (b) grids ... )21T 237 4.6 439 8.062.5K390.2K2=ì+ì= <Node 3 (to find T 3 ):2c2B3TTT300K4Tqx/k0++++=&( ) 3 1T348. 539 0. 237 4. 630 062.5K369.0K4=++++=<Node 1 (to find T1):2C21 30 02TT4Tqx/k0+++=&( ... where x and y arein mm and the temperatures are in °C.y\x 0 15 30 45 600 50 80 .33 85.16 80 .33 5015 50 63. 58 67. 73 63. 58 50 30 50 56.27 58.58 56.27 5045 50 52.91 54.07 52.91 5060 50 51 .32 51.86...