...
2
. The inner product of two vectors x and y is
given by
x ·y = (x
1
1
+ x
2
2
) ·(y
1
1
+ y
2
2
). (17 .20 )
Since
1
and
2
are orthonormal, we have
x ·y = x
1
y
1
+ x
2
y
2
, (17 .21 )
so ... KERNELS
and
y
1
2
= x
Z
1
− x
Z
2
2
+ y
2
2
. (17.15)
Eqs. 17.14 and 17.15 imply that
x
Z
1
− x
Z
2
2
= 0 (17.16)
so, by the strict...
... implies that
h
2
(ξ
g
) ≥ 2, h
2
(ξ
g
) ≥ 1, h
2
(ξ
b
) ≥ 1, h
2
(ξ
b
) ≥ 0, (24 .8)
h
1
(ξ
0
) + 0.9(h
2
(ξ
0
) −h
2
(ξ
g
)) ≥ 0, and h
1
(ξ
0
) + 0.8(h
2
(ξ
0
) −h
2
(ξ
b
)) ≥ 0. (24 .9)
The solution ... positive and nonzero payoff,
and (2) utility functions are strictly increasing at any date at which that payoff is nonzero.
21 9
22 0 CHAPTER 22 . MULTIDATE ARBITRAG...