... ®)a. 2Na + 2H 2 O –& gt; 2 NaOH + H 2 b. H 2 O +CaO –& gt; Ca(OH) 2 c. Mg + 2 HCl –& gt; MgCl 2 + H 2 C©u 2: 1 chän D; (1®) 2 chän B (2 )C©u 3: PTHH:a. Mg + 2 HCl –& gt; MgCl 2 + H 2 (1®)b. ... molPh¶n øng: 0 ,25 mol 0 ,25 mol Sau P¦ 0 0 ,25 mol 0 ,25 . 2 mol 0 ,25 mol gmCaCO 25 10 025 ,03=⋅=gmNaCl 25 ,29 5,5 822 5,0=⋅⋅=m CaCl 2 (d)g55,511105,0=⋅=gmddsaupu35 125 1 115, 26 =−+=C% NaCl ... (1®)b. nMg = 12: 24 = 0,5 mol (0,5 ®)Theo PTHH: nMg=n H 2 = 0,5 mol (0,5 ®)VH 2 = 0,5 . 22 ,4 = 11 ,2 (l) (1®)c. Sè ph©n tö NaOH gÊp ®«i sè ph©n tö H 2 – >n NaOH = 2 n H 2 = 2. 0,5 = 1...