fundamentals of heat and mass transfer solutions manual phần 10 doc

... of heat transfer to tube without ash deposit, (b) Rate of heat transfer with an ash deposit of diameter Dd = 0.06 m, (c) Effect of deposit diameter and convection coefficient on heat rate and contributions ... specification of nearly optimum αa(λ) for absorber.PROBLEM 13 .109 KNOWN: Dimensions and emissivity of double pane window. Thickness of air gap. Temperatures of room and ambient air and the related ... 13.111KNOWN: Diameters and temperatures of a heated tube and a radiation shield.FIND: (a) Total heat loss per unit length of tube, (b) Effect of shield diameter on heat rate.SCHEMATIC:ASSUMPTIONS:...

fundamentals of heat and mass transfer solutions manual phần 2 docx

... Temperature and volume of hot water heater. Nature of heater insulating material. Ambientair temperature and convection coefficient. Unit cost of electric power.FIND: Heater dimensions and insulation ... Kq=ln 1.04 12 2m 1.4 W/m K1.04m 2m 10 W/m K400 300 K +111 0.962 m2 1.4 W/m K1.04m 10 W/m K 100 K 100 Kq=2.23 10 K/W + 15.30 10 K/W 4.32 10 K/W + 29.43 10 ππππ−+⋅⋅−−+⋅⋅+××××q ... through a pipe of prescribed inner and outer radii. Emissivity of outer surface magnesia insulation, and convectioncoefficient. Temperature of ambient air and surroundings.FIND: Heat loss per...

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... 120 s) and T(0.15 m, 120s) using the finite-element software FEHTfor a surface emissivity of 0.94 and (b) Plot the temperature histories for x = 0, 150 and 600 mm, and explain key features of your ... independent of time.Hence,()()p1 p po11 2T T 1 2Fo Bi Fo Fo T T Bi FoT+∞=−−⋅+ ++⋅.(5)End Nodal Point 10: p1 p 10 10abc c pTTxqqq A c2tρ+−∆++=⋅ ⋅∆()()pp p1ppp 910 10 10 cc ... outline of the slab, the boundary conditions, and the triangular mesh before using the Reduce-mesh option.PROBLEM 5.96 (Cont.)() ()73xq L,t 10W m K 149.80 100 C 0.010m 2 10 W m 0.010m 2′′=⋅...

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... pharmaceutical. Heat transfer coefficient at outer surface and dimensions of coil.FIND: (a) Expressions for Tc(t) and Th,o(t), (b) Plots of Tc(t) and Th,o(t) for prescribed conditions.Effect of ... 8.34KNOWN: Flow rate and inlet temperature of water passing through a tube of prescribed length,diameter and surface temperature.FIND: (a) Outlet water temperature and rate of heat transfer to water ... the mass rate and Reynolds number,( ) ( )()23cmmAu0.7740 kg/m200 kPa /101 .3 kPa0.025 m/4 6 m/sρπ==×&-3m4.50110kg/s.=×&( )33D-724m44.50 110 kg/sRe9.14 310. D250. 710 Ns/m0.025...

fundamentals of heat and mass transfer solutions manual phần 3 pdf

... guesses.(2) Note that the rate of heat transfer by convection to the top surface of the rod must balance the rate of heat transfer by conduction to the sides and bottom of the rod.NOTE TO INSTRUCTOR: ... ( )( )q50 W/mK[1/2120.5 5100 120.6 4100 121.2 9100 123.8 9100 134.5 7100 1/2147.1 4100 ]′=⋅−+−+−+−+−+−q6711 W/m.′=<COMMENTS: For nodes a through d, there is no heat transfer into the control ... amounts of heat transfer to the air and heat sinkare determined by the values of h and t,cR.′′PROBLEM 4.54 (Cont.)The heat rate by convection between the bar and fluid is given as,()conv a...

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fundamentals of heat and mass transfer solutions manual phần 5 ppsx

... emissivity of Nichrome wire. Electricalcurrent. Temperature of air flow and surroundings. Velocity of air flow. (a) Surface and centerline temperatures of the wire, (b) Effect of flow velocity and ... stream velocity and temperature of air coolant. (a) Average pin convection coefficient, (b) Pin heat transfer rate, (c) Total heat rate, (d) Effect of velocity and pin diameter on total heat rate. ... 8 10 Fluid velocity, V (m/s)0 100 00200003000040000 Heat rate, q'a *100 , q'w, q'o *10 (W/m)Air - q' *100 Water - q'Oil - q' *10 (1) Note the inapplicability of...

fundamentals of heat and mass transfer solutions manual phần 7 pot

... emissivity, and power dissipation of cylindrical heater. Temperature of ambientair and surroundings.FIND: Steady-state temperature of heater and time required to come within 10 °C of this temperature.SCHEMATIC:ASSUMPTIONS: ... Summary of the calculations above and for water and ethylene glycol:Fluid RaD()2DhW/mK⋅ q(W)Air 6.750 × 10 4 10. 6 1.55 <Water 7.273 × 10 71299 187 <Ethylene glycol 15.82 × 10 6 ... 50°C.FIND: (a) Length of tube and number of coils required to provide an exit temperature of Tm,o = 38°C, and (b) Variations expected in Tm,o for a ± 10 % change in the mass flow rate for...

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fundamentals of heat and mass transfer solutions manual phần 8 ppsx

... −°=°<The rate of heat transfer to the air is()pc,o c,iq mc T T 0.03kg/s 100 8J/ kg K 62.8 C 1900 W=−=×⋅×°= and the rate of condensation is4cond6fgq 1900Wm 8.70 10 kg /sh2.183 10 J /kg−== ... (a) Overall heat transfer coefficient, U, for the HXer, outlet temperature of cooling water, Tc,o, and condensation rate of the steam hm; and (b) Compute and plot Tc,o and hm as ... 32h14.44 10 9.59 10 3.58 10 m K W 4.12 10 m K WU−−− −=×+×+× ⋅=× ⋅2hU243WmK=⋅.With Ch = Cmin = 4.160 × 10 4 W/K and Cc = Cmax = 2.09 × 10 5 W/K, Cmin/Cmax = 0.199 and qmax...

fundamentals of heat and mass transfer solutions manual phần 9 ppt

... )48244s2ss hsr0.95.6710W/mK273K1TGI90.2W/msrsrεσρπππ−×⋅−====⋅( )()26258sdq46.290.2W/msr510m2.2210sr1.5110W−−−−=+⋅×××=×86232dG1.5110W/210m7.5710W/m.−−−=××=× <(b) ... allowable value of Ts = 1800 K, it follows that84 84 84o0.391 5.67 10 (2400) 0.8 5.67 10 (300) 2 0.46 5.67 10 (1800)h(1800 300)−− −×× +×× −×××=−5252o7.335 10 3.674 10 5.476 10 h 126W ... history of theworkpiece from the start of heating to the end of cooling; identify key features of the process;determine the total time requirement; and justify the lumped-capacitance method of analysis.SCHEMATIC:ASSUMPTIONS:...

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