Sat math essentials 2 docx

... times you have takenthe SAT, you’re smart to be using this book. The onlyway to raise your SAT score is through preparationand practice.–TAKING THE SAT 2 Where Is the SAT Given?Many high ... Tested on the SAT? The SAT has approximately 160 questions divided intoeight test sections:■three critical reading sections ■two 25 -minute sections■one 20 -minute section■three math sections ... to the SAT. It answers basic questions you may have about the exam.Chapter 2 provides information about what to expect on the Math sections of the SAT and how best toprepare for the SAT. Chapter...

... dec-imal. (͙ 32 ෆ)3= (͙ 32 ෆ)(͙ 32 ෆ)(͙ 32 ෆ) = 32 32 ෆ= 32 16ෆ 2 ෆ= ( 32) (4) 2 ෆ= 128 2 ෆ. 2 ෆcan-not be expressed as a repeating or terminatingdecimal, therefore, 128 2 ෆis an irrationalnumber.19. ... ͙(x 2 – xෆ1) 2 + (yෆ 2 – y1) 2 ෆDistance = ͙(11 – (ෆ–1)) 2 +ෆ((–7)ෆ– 2) 2 ෆDistance = ͙( 12) 2 +ෆ(–9) 2 ෆDistance = ͙144 + 8ෆ1ෆDistance = 22 5ෆDistance = 15 units 12. 17.6 If ... ᎏ1 2 ᎏ(8) (20 ) =ᎏ1 2 ᎏ(160) = 80 square units.–PRACTICE TEST 2 – 21 5Section 11. If m = 6, then the expression ᎏm3 2 ᎏ– 4m + 10 is equal toa. – 12. b. 2. c. 6.d. 12. e. 22 . 2. Which...

... dec-imal. (͙ 32 ෆ)3= (͙ 32 ෆ)(͙ 32 ෆ)(͙ 32 ෆ) = 32 32 ෆ= 32 16ෆ 2 ෆ= ( 32) (4) 2 ෆ= 128 2 ෆ. 2 ෆcan-not be expressed as a repeating or terminatingdecimal, therefore, 128 2 ෆis an irrationalnumber.19. ... ͙(x 2 – xෆ1) 2 + (yෆ 2 – y1) 2 ෆDistance = ͙(11 – (ෆ–1)) 2 +ෆ((–7)ෆ– 2) 2 ෆDistance = ͙( 12) 2 +ෆ(–9) 2 ෆDistance = ͙144 + 8ෆ1ෆDistance = 22 5ෆDistance = 15 units 12. 17.6 If ... Attendees>554%<1810%33–55 21 %18 24 41% 25 –34 24 %A6√⎯3BEDFC–PRACTICE TEST 3– 23 2 22 4–LEARNINGEXPRESS ANSWER SHEET–1. 2. 3.4.5.6.7.8.9.10.11. 12. 13.14.15.16.a b c d ea...

... terms. 2, 4,8,16, 32, Ter m 1 ϭ 2 Ter m 2 ϭ 4, which is 2 ϫ 2 Ter m 3 ϭ 8, which is 2 ϫ 2 ϫ 2 Ter m 4 ϭ 16, which is 2 ϫ 2 ϫ 2 ϫ 2 You can also write out each term using exponents:Ter m 1 ϭ 2 Ter ... m 2 ϭ 2 ϫ 2 1Ter m 3 ϭ 2 ϫ 2 2Ter m 4 ϭ 2 ϫ 2 3We can now write a formula:Te r m n ϭ 2 ϫ 2 n Ϫ 1So, if the SAT asks you for the thirtieth term, you know that:Term 30 ϭ 2 ϫ 2 30 Ϫ 1ϭ 2 ... x 2 , so its equationis therefore y ϭ x 2 Ϫ 3.xy 123 4561 2 345–1 2 –6–5–4–3–1 2 3–4–5–6xy 123 45671 2 345–1 2 –3–1 2 3–4–5–6–7–ALGEBRA REVIEW–84c ϩ 2d ϭ 13c ϩ 2( 11 Ϫ 2c)...

... e1 2 3456789•1 2 34567890•/1 2 34567890•/1 2 34567890•1 2 3456789•1 2 34567890•/1 2 34567890•/1 2 34567890•1 2 3456789•1 2 34567890•/1 2 34567890•/1 2 34567890•1 2 3456789•1 2 34567890•/1 2 34567890•/1 2 34567890•16. 17. 18. 19. 20 . 21 . 22 . 23 . 24 . ... 24 . 25 . 26 . 27 . 28 . 29 . 30.1 2 3456789•1 2 34567890•/1 2 34567890•/1 2 34567890•1 2 3456789•1 2 34567890•/1 2 34567890•/1 2 34567890•1 2 3456789•1 2 34567890•/1 2 34567890•/1 2 34567890•1 2 3456789•1 2 34567890•/1 2 34567890•/1 2 34567890•1 2 3456789•1 2 34567890•/1 2 34567890•/1 2 34567890•1 2 3456789•1 2 34567890•/1 2 34567890•/1 2 34567890•1 2 3456789•1 2 34567890•/1 2 34567890•/1 2 34567890•1 2 3456789•1 2 34567890•/1 2 34567890•/1 2 34567890•1 2 3456789•1 2 34567890•/1 2 34567890•/1 2 34567890•1 2 3456789•1 2 34567890•/1 2 34567890•/1 2 34567890•1 2 3456789•1 2 34567890•/1 2 34567890•/1 2 34567890•ᎏ8 ... unitse. 36π square units 12. If the diagonal of a square measures 16 2 ෆcm, what is the area of the square?a. 32 2 ෆcm 2 b. 64 2 ෆ cm 2 c. 128 cm 2 d. 25 6 cm 2 e. 5 12 cm 2 13. If m > n, which...

... ͙(x 2 – xෆ1) 2 + (yෆ 2 – y1) 2 ෆ10 = ͙(4 – (–ෆ 2) ) 2 +ෆ((–1) –ෆm) 2 ෆ10 = ͙(6) 2 +ෆ(–1 – mෆ) 2 ෆ10 = ͙36 + mෆ 2 + 2mෆ+ 1ෆ10 = ͙m 2 + 2 ෆm + 37ෆ100 = m 2 + 2m + 37m 2 + ... above?a. y = (x + 3) 2 + 2 b. y = (x + 3) 2 – 2 c. y = (x – 3) 2 + 2 d. y = (x – 3) 2 – 2 e. y = (3x + 3) 2 – 2 4433 2 211–1–1 2 2 3–3–4–4yx–PRACTICE TEST 1–18615. 24 If the height ... 27 .5 degreesb. 55 degreesc. 70 degreesd. 110 degreese. 125 degrees 20 . The expression is equivalent toa. 2 2 ෆ.b. .c. .d. .e. .2x 2 ෆᎏ͙xෆx 2 ෆᎏ͙xෆ 2 2 ෆᎏ͙xෆ 2 ෆᎏ 2 x͙ 32 ෆᎏ͙4xෆACBDO55˚–PRACTICE...

... + 12 cm = 60 cm.9. 4Substitute 2 for xand 5 for y:(3xy+ x)ᎏxyᎏ=((3) (2) (5) + 2) ᎏ 2 5ᎏ= (30 + 2) ᎏ 2 5ᎏ= 32 ᎏ 2 5ᎏ= (͙5 32 ෆ) 2 = 2 2= 4. Or, 3 (2) (5) = 30, 30 + 2 = 32, ... equationto find the value of a:–6b + 2a – 25 = 5,–6(–3) + 2a – 25 = 5, 18 + 2a = 30, 2a = 12, a = 6. Finally, (ᎏabᎏ) 2 = (ᎏ–63ᎏ) 2 = (–ᎏ1 2 ᎏ) 2 = ᎏ14ᎏ.13. 6 If j@k = –8 when ... equal to 2 r 2 , or 2 (9) 2 = 2( 81)π = 1 62 square units.8. d. Cross multiply:a 20 ෆ= a 2 20 ෆ= 2 180ෆa 2 ͙4ෆ͙5ෆ= 2 36ෆ͙5ෆ2a 2 ͙5ෆ= 12 5ෆa 2 = 6a = ͙6ෆ9. b. Since triangle DEC...

... + 12 cm = 60 cm.9. 4Substitute 2 for xand 5 for y:(3xy+ x)ᎏxyᎏ=((3) (2) (5) + 2) ᎏ 2 5ᎏ= (30 + 2) ᎏ 2 5ᎏ= 32 ᎏ 2 5ᎏ= (͙5 32 ෆ) 2 = 2 2= 4. Or, 3 (2) (5) = 30, 30 + 2 = 32, ... equationto find the value of a:–6b + 2a – 25 = 5,–6(–3) + 2a – 25 = 5, 18 + 2a = 30, 2a = 12, a = 6. Finally, (ᎏabᎏ) 2 = (ᎏ–63ᎏ) 2 = (–ᎏ1 2 ᎏ) 2 = ᎏ14ᎏ.13. 6 If j@k = –8 when ... equal to 2 r 2 , or 2 (9) 2 = 2( 81)π = 1 62 square units.8. d. Cross multiply:a 20 ෆ= a 2 20 ෆ= 2 180ෆa 2 ͙4ෆ͙5ෆ= 2 36ෆ͙5ෆ2a 2 ͙5ෆ= 12 5ෆa 2 = 6a = ͙6ෆ9. b. Since triangle DEC...

... undefined when x = 2? a. y = ᎏxx+ 2 2ᎏb. y = ᎏx 2 +4xx +4ᎏc. y = ᎏx 2 2–x4+x4+4ᎏd. y = ᎏx 2 –+x 2 3+x + 2 2ᎏe. y = ᎏxx 2 2++ 2 6xx++ 2 8ᎏ 2. If graphed, ... of angle ACB?a.ᎏ1 2 ᎏb. 2 ෆc.d.e. cannot be determined͙3ෆᎏ 2 2 ෆᎏ 2 –PRACTICE TEST 2 20 7 20 0–LEARNINGEXPRESS ANSWER SHEET–1. 2. 3.4.5.6.7.8.9.10.11. 12. 13.14.15.16.a ... pattern below?ᎏ1,100 24 ᎏ,ᎏ59 12 ᎏ,ᎏ 2 856ᎏ,ᎏ17 28 ᎏ, a.ᎏ1 2 ᎏb.ᎏ 2 9ᎏc.ᎏ9 2 ᎏd.ᎏ94ᎏe. 1AJMLQNDCBOPKZ70˚–PRACTICE TEST 2 21 215. If 40% of j is equal...