Advanced Mathematical Methods for Scientists and Engineers Episode 5 Part 5 ppt

Advanced Mathematical Methods for Scientists and Engineers Episode 1 Part 2 ppt

Advanced Mathematical Methods for Scientists and Engineers Episode 1 Part 2 ppt

... is the angle from a to b and n is a unit vector that is orthogonal to a and b and in the direction s uch that the ordered triple of vectors a, b and n form a right-handed system. 29 a b b θ b Figure ... vectors a and b. We can write b = b ⊥ + b  where b ⊥ is orthogonal to a and b  is parallel to a. Show that a × b = a × b ⊥ . Finally prove the distributive law for arbitrary b...
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Advanced Mathematical Methods for Scientists and Engineers Episode 1 Part 3 pptx

Advanced Mathematical Methods for Scientists and Engineers Episode 1 Part 3 pptx

... 3.11. -1 -0 .5 0 .5 1 0 .5 1 1 .5 2 2 .5 -1 -0 .5 0 .5 1 0 .5 1 1 .5 2 2 .5 -1 -0 .5 0 .5 1 0 .5 1 1 .5 2 2 .5 -1 -0 .5 0 .5 1 0 .5 1 1 .5 2 2 .5 Figure 3.11: Four Finite Taylor Series Approximations of e x Note that for ... passes through the points (x, y(x)) and (x + ∆x, y(x + ∆x)). See Figure 3 .5. y x ∆ y ∆ x Figure 3 .5: The increments ∆x and ∆y. 56 -10 -5...
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Advanced Mathematical Methods for Scientists and Engineers Episode 1 Part 4 pptx

Advanced Mathematical Methods for Scientists and Engineers Episode 1 Part 4 pptx

... of x and an increasing function of δ for positive x and δ. Thus for any fixed δ, the maximum value of √ x + δ − √ x is bounded by √ δ. Therefore on the interval (0, 1), a sufficient condition for ... −2) −1/3 The first derivative exists and is nonzero for x = 2. At x = 2, the derivative does not exist and thus x = 2 is a critical point. For x < 2, f  (x) < 0 and for...
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Advanced Mathematical Methods for Scientists and Engineers Episode 1 Part 5 pdf

Advanced Mathematical Methods for Scientists and Engineers Episode 1 Part 5 pdf

... (0 .58 9 755 , 0, 0.34781). The closest point is shown graphically in Figure 5. 10. -1 -0 .5 0 0 .5 1 -1 -0 .5 0 0 .5 1 0 0 .5 1 1 .5 2 -1 -0 .5 0 0 .5 1 0 0 .5 1 1 .5 2 Figure 5. 10: Paraboloid, Tangent Plane and ... particle at time t, then the velocity and acceleration of the particle are dr dt and d 2 r dt 2 , 154 Figure 5. 2: The gradient of the distance from the ori...
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Advanced Mathematical Methods for Scientists and Engineers Episode 1 Part 7 ppt

Advanced Mathematical Methods for Scientists and Engineers Episode 1 Part 7 ppt

... This is zero if and only if u 0 = u 1 = u 2 = u 3 = 0. Thus there 217 -10 -5 5 10 - 15 -10 -5 5 Figure 6.23: (z) − (z) = 5 Solution 6.16 | e ıθ −1| = 2  e ıθ −1  e −ıθ −1  = 4 1 − e ıθ − e −ıθ +1 ... real-variable counterparts. 7.1 Curves and Regions In this section we introduce curves and regions in the complex plane. This material is necessary for the study of branch p...
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Advanced Mathematical Methods for Scientists and Engineers Episode 1 Part 8 ppt

Advanced Mathematical Methods for Scientists and Engineers Episode 1 Part 8 ppt

... are an infinite set of rational numbers for which ı z has 1 as one of its values. For example, ı 4 /5 = 1 1 /5 =  1, e ı2π /5 , e ı4π /5 , e ı6π /5 , e ı8π /5  7.8 Riemann Surfaces Consider the mapping ... See Figure 7.18 and Figure 7.19 for plots of the real and imaginary parts of the cosine and sine, respectively. Figure 7.20 shows the modulus of the cosine and the sine...
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Advanced Mathematical Methods for Scientists and Engineers Episode 1 Part 9 ppt

Advanced Mathematical Methods for Scientists and Engineers Episode 1 Part 9 ppt

... Hints Cartesian and Modulus-Argument Form Hint 7.1 Hint 7.2 Trigonometric Functions Hint 7.3 Recall that sin(z) = 1 ı2 ( e ız − e −ız ). Use Result 6.3.1 to convert between Cartesian and modulus-argument form. Hint ... solutions. Solution 7 .5 We write the expressions in terms of Cartesian coordinates.    e z 2    =    e (x+ıy) 2    =    e x 2 −y 2 +ı2xy    = e x 2 −y 2...
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Advanced Mathematical Methods for Scientists and Engineers Episode 2 Part 2 pptx

Advanced Mathematical Methods for Scientists and Engineers Episode 2 Part 2 pptx

... the real and imaginary parts. u r = 1 r v θ , v r = − 1 r u θ u r = 1 r v θ , u θ = −rv r Solution 8. 15 Since w is analytic, u and v satisfy the Cauchy-Riemann equations, u x = v y and u y = ... = 1 r ∂ ∂r  r ∂u ∂r  + 1 r 2 ∂ 2 u ∂θ 2 = 0. Therefore u is harmonic and is the real part of some analytic function. Example 9.3.9 Find an analytic function f(z) whose real part is u(r...
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Advanced Mathematical Methods for Scientists and Engineers Episode 2 Part 3 ppt

Advanced Mathematical Methods for Scientists and Engineers Episode 2 Part 3 ppt

... contour and do the integration. z − z 0 = e ıθ , θ ∈ [0 . . . 2π)  C (z − z 0 ) n dz =  2π 0 e ınθ ı e ıθ dθ =     e ı(n+1)θ n+1  2π 0 for n = −1 [ıθ] 2π 0 for n = −1 =  0 for n = −1 ı2π for ... have found a formula for writing the analytic function in terms of its real part, u(r, θ). With the same method, we can find how to write an analytic function in terms of its ima...
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Advanced Mathematical Methods for Scientists and Engineers Episode 2 Part 5 pps

Advanced Mathematical Methods for Scientists and Engineers Episode 2 Part 5 pps

... , converges for α > 1 and diverges for α ≤ 1. Hint, Solution 56 4 Example 12.3.2 Convergence and Uniform Convergence. Consider the series log(1 − z) = − ∞  n=1 z n n . This series converges for |z| ... large. Thus this series is not uniformly convergent in the domain |z| ≤ 1, z = 1. The series is uniformly convergent for |z| ≤ r < 1. 54 5 12.2.2 Uniform Convergence and...
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