... A = 0, 2 ln t +1 2 t 2 + c, A = 0−1 2 t 2 + ln t + c, A = 2 y =1A+t 2 A +2 + ct−A, A = 2 ln t +1 2 t 2 + c, A = 0−1 2 + t 2 ln t + ct 2 , A = 2 For positive A, the ... constants.0 1 2 2 1 2 1 0 1c1c 2 c3= 2 01c1= 1, c 2 = 2, c3= 0The solution subject to the initial condition isx =0 2 1et +2 110e2t.As t ... origin are:y =1A+t 2 A +2 , A > 01A+t 2 A +2 + ct−A, A < 0, A = 2 −1 2 + t 2 ln t + ct 2 , A = 2 Equations in the Complex PlaneSolution 14. 151. Consider the equation...