... is Ͻ0.5. As viscous
and then turbulent separation occurs around particles
10
3
10
2
10
1
10
0
10
1
Fall velocity, mm s
1
Sphere diameter, mm
10
1
10
0
10
1
10
–2
silt
sand gravel
Stokes law
V
p
... acceleration. In fact, quadrants 2 and 4 dominate, giving
deceleration and implying a “structure” to turbulence.
LEED-Ch-04.qxd 11 /26/05 13 :24 Page 11 6
Flow, defo...
... m
2
s
1
Kinetic energy of rotation
v = 50 rad s
1
m = 1. 15 ؒ 10
–5
kg
r = 1 ؒ 10
–3
m
I = 4.6 ؒ 10
12
kg m
2
L = 2.3 ؒ 10
10
kg m
2
s
1
E
k
= 0.5 mR
2
v
2
= 0.5 Iv
2
LEED-Ch-03.qxd 11 /27/05 ... constant
u
1
u
2
a
1
a
2
Q
1
Q
2
Q
1
= Q
2
= a
1
u
1
= a
2
u
2
u
1
> u
2
Fig. 2.22 Continuity of mass: variable density case in 1D.
a = area
a
2
&...
...
sin u A sin u
(24) F
1x
= s
1
sin u A cos u
(25) F
3x
= s
3
cos u A sin u
x
F
3
F
1
F
θ
F
N
F
S
F
1Z
F
1X
F
3X
F
3Z
( 21) F
N
= F
1Z
+ F
3Z
(20) F
S
+ F
3X
= F
1X
; F
S
= F
1X
... determined as shown in
Fig. 3.64 by simple trigonometric calculations (Equations
10 and 11 ), resulting in a value of 82Њ. To simplify things
we divide the total angle, ␣, between the...
... 1C
tЈ
a
a
1. 5
1. 0
0.5
0.0
0 30 60 90
1A
1C
1B
2
3
TЈ
a
a
3.0
2.0
1. 0
0.0
0 30 60 90
1C
1A
1B
3
2
LEED-Ch-04.qxd 11 /26/05 14 :02 Page 17 8
17 0 Chapter 4
400 km
San Andreas fault system
N
Fig. 4 .10 9 The San Andreas fault ... layers.
Inflexion line
Hinge line
Hinge line
Axial surface
Axial surfaces
(a)
(b)
(c)
Fig. 4 .11 6 Geometric elements of a fold in a folded surface in 3D....
... due to cool-
ing and crystallization
11 00
13 00
15 00
Temperature (
º
C)
3.3 2.9
2 .1
1.5
0.8
5.3
8.2
2.5
3 .1
3.5
5.6
17 .0
Pressure (kbar)
510 15202530
Liquidus
Fig. 5 .13 Variation of andesite melt ... ions and also join to aluminum ions in
linked rings. The linked groups are said to be in a state of
polymerization and are a feature of silicate melts. It is the
continuous...