... 5,0 .10 -4 [ ] 5,0 .10 -4-x 2x 213,164(2x) 10 (5, 0 .10 x)−−⇒ =− x = 5 .10 - 4 2x = 42381613410x 5101 010x5−−−−<=,,. 0,5 đ Vậy: + -8,23 93 2[Ag(NH ) ]=2x =10 5,9 .10 M−= ... 5 .10 -3 5 .10 -2 0,485 [ ] (5 .10 -3-x) (5 .10 -2-x) x 0,485+3x 3 10, 073 2x(0, 485 3x) 10 (5 .10 x)(5 .10 x)−− −+⇒ =− − 0.5đ Với x << 5 .10 -3 ta được : ( )61330 7105 10x710x861485010x10x25x−−−−<== ... 3FeFC = 5 .10 -3M; FC−= 0,485M; 2SCNC 5 .10 M−−= FeF3 Fe3+ + 3F - 10 -13 ,10 Fe3+ + SCN- FeSCN2+ 10 +3,03 FeF3 + SCN- FeSCN2+ + 3F- K = 10 -10, 07 0,5...