... 2OGE@}6W#<8-•$b?Ω+>$π_&X*+6$πc2?_?h−&q*eWWFZ3.$_Z?Z_??π&A*+/@u:IlW,.a. sin(100 t ).(A)4π ι = 4 π +b. sin(100 t ).(A)4π ι = 2 π −24RCL∼ABc. sin(100 t ).(A)4π ι = 4 π −d. sin(100 t ).(A )4π ι = 2 π +XJ<1ggK2W#<8@;g+CH•$_??Ωe;<3>$π_XeDW-W_a+~µq+5.WWF#<8$Z??Z&_??π*&A*26ETDGWU.H%2_??2Z™242Z??2Z™262Z??™222h??™269[gH(¡$Z??Ω2e•$_??Ω2e¡>$_??Ω2 ( ¡%4$_??ZΩe˜$ABZU$Z_??Z??$Z%e ( @$ABZR$Z_??_??$ZZ2 ( r$@¢2˜$ZZ2Z??2Z$Z??™20.CW-WWFBb__A.E?+•a@™+lWWDN.a%2O:W0EUW%2?+•Z ... 2?+cc6#<8-•$h?Ω+>$π_&X*+6$π`2?_?h−&q*+50FWWFZ3/@u$_??Z_??π&A*+E.IlWN.Ha.P 125W,i 2,5sin(100 t )(A)4π= = π +b.P 125W,i 2,5sin(100 t )(A)4π= = π −c.P 125W,i 2,5 2sin(100 t )(A)4π= = π −d.P 125W,i 2,5 2sin(100 t )(A)4π= = π +XJ<#g;K2%\g<gW#<8FuWG.QG24\g<gW#<8FuQG.WG.26\\g<gW#<8E ... −+$Z?b&Ω*26L5 2a.Z 173 ,i sin(100 t )(A)63π= Ω = π −L5 2b.Z 117,3 ,i sin(100 t )(A)63π= Ω = π −L5 2c.Z 117,3 ,i sin(100 t )(A )63π= Ω = π +L5 2d.Z 173 ,i sin(100 t )(A)63π= Ω = π...